我正在寻找一种方法来取代字符在一个Swift字符串。
示例:“This is my string”
我想用“+”替换“”以获得“This+is+my+string”。
我怎样才能做到这一点呢?
我正在寻找一种方法来取代字符在一个Swift字符串。
示例:“This is my string”
我想用“+”替换“”以获得“This+is+my+string”。
我怎样才能做到这一点呢?
当前回答
Swift 3, Swift 4, Swift 5解决方案
let exampleString = "Example string"
//Solution suggested above in Swift 3.0
let stringToArray = exampleString.components(separatedBy: " ")
let stringFromArray = stringToArray.joined(separator: "+")
//Swiftiest solution
let swiftyString = exampleString.replacingOccurrences(of: " ", with: "+")
其他回答
修改现有可变字符串的类别:
extension String
{
mutating func replace(originalString:String, withString newString:String)
{
let replacedString = self.stringByReplacingOccurrencesOfString(originalString, withString: newString, options: nil, range: nil)
self = replacedString
}
}
使用:
name.replace(" ", withString: "+")
迅速扩展:
extension String {
func stringByReplacing(replaceStrings set: [String], with: String) -> String {
var stringObject = self
for string in set {
stringObject = self.stringByReplacingOccurrencesOfString(string, withString: with)
}
return stringObject
}
}
继续使用let replacedString = yorString。stringbyreplacement (replaceStrings: [" ","?","."],加上:“+”)
函数的速度是我几乎不能感到骄傲的,但是你可以在一次传递一个String数组来进行多次替换。
var str = "This is my string"
str = str.replacingOccurrences(of: " ", with: "+")
print(str)
如果你不想使用Objective-C NSString方法,你可以使用split和join:
var string = "This is my string"
string = join("+", split(string, isSeparator: { $0 == " " }))
split(string, isSeparator:{$0 == " "})返回一个字符串数组(["This", "is", "my", "string"])。
join用一个+连接这些元素,产生所需的输出:"This+is+my+string"。
很少发生在我身上,我只是想改变字符串中的(一个单词或字符)
所以我用了字典
extension String{
func replace(_ dictionary: [String: String]) -> String{
var result = String()
var i = -1
for (of , with): (String, String)in dictionary{
i += 1
if i<1{
result = self.replacingOccurrences(of: of, with: with)
}else{
result = result.replacingOccurrences(of: of, with: with)
}
}
return result
}
}
使用
let mobile = "+1 (800) 444-9999"
let dictionary = ["+": "00", " ": "", "(": "", ")": "", "-": ""]
let mobileResult = mobile.replace(dictionary)
print(mobileResult) // 001800444999