InputStream IS=new URL("http://www.petrol.si/api/gas_prices.json").openStream();   

  ByteArrayOutputStream BAOS=new ByteArrayOutputStream();
  IOUtils.copy(IS, BAOS);
  String d= new String(BAOS.toByteArray(),"UTF-8");           

System.out.println(d);

我做了一些计时测试，因为时间总是很重要的。

我试图以3种不同的方式将响应转换为字符串。（如下所示）为了可读性，我省略了try/catch块。

为了给出上下文，这是所有3种方法的前面代码：

   String response;
   String url = "www.blah.com/path?key=value";
   GetMethod method = new GetMethod(url);
   int status = client.executeMethod(method);

1)

 response = method.getResponseBodyAsString();

2)

InputStream resp = method.getResponseBodyAsStream();
InputStreamReader is=new InputStreamReader(resp);
BufferedReader br=new BufferedReader(is);
String read = null;
StringBuffer sb = new StringBuffer();
while((read = br.readLine()) != null) {
    sb.append(read);
}
response = sb.toString();

3)

InputStream iStream  = method.getResponseBodyAsStream();
StringWriter writer = new StringWriter();
IOUtils.copy(iStream, writer, "UTF-8");
response = writer.toString();

因此，在使用相同的请求/响应数据对每种方法运行了500次测试之后，以下是数字。再次，这些是我的发现，你的发现可能不完全相同，但我写这篇文章是为了向其他人说明这些方法的效率差异。

排名：方法#1进近#3-比#1慢2.6%2号进近——比1号进近慢4.3%

任何这些方法都是获取响应并从中创建字符串的适当解决方案。

如果不能使用Commons IO（FileUtils/IOUtils/CopyUtils），下面是一个使用BufferedReader逐行读取文件的示例：

public class StringFromFile {
    public static void main(String[] args) /*throws UnsupportedEncodingException*/ {
        InputStream is = StringFromFile.class.getResourceAsStream("file.txt");
        BufferedReader br = new BufferedReader(new InputStreamReader(is/*, "UTF-8"*/));
        final int CHARS_PER_PAGE = 5000; //counting spaces
        StringBuilder builder = new StringBuilder(CHARS_PER_PAGE);
        try {
            for(String line=br.readLine(); line!=null; line=br.readLine()) {
                builder.append(line);
                builder.append('\n');
            }
        } 
        catch (IOException ignore) { }

        String text = builder.toString();
        System.out.println(text);
    }
}

或者，如果你想要原始速度，我会根据Paul de Vrieze的建议（避免使用StringWriter（内部使用StringBuffer））提出一个变体：

public class StringFromFileFast {
    public static void main(String[] args) /*throws UnsupportedEncodingException*/ {
        InputStream is = StringFromFileFast.class.getResourceAsStream("file.txt");
        InputStreamReader input = new InputStreamReader(is/*, "UTF-8"*/);
        final int CHARS_PER_PAGE = 5000; //counting spaces
        final char[] buffer = new char[CHARS_PER_PAGE];
        StringBuilder output = new StringBuilder(CHARS_PER_PAGE);
        try {
            for(int read = input.read(buffer, 0, buffer.length);
                    read != -1;
                    read = input.read(buffer, 0, buffer.length)) {
                output.append(buffer, 0, read);
            }
        } catch (IOException ignore) { }

        String text = output.toString();
        System.out.println(text);
    }
}

我已经创建了这段代码，并且它有效。没有所需的外部插件。

有一个字符串到流和流到字符串的转换器：

import java.io.ByteArrayInputStream;
import java.io.InputStream;

public class STRINGTOSTREAM {

    public static void main(String[] args)
    {
        String text = "Hello Bhola..!\nMy Name Is Kishan ";

        InputStream strm = new ByteArrayInputStream(text.getBytes());    // Convert String to Stream

        String data = streamTostring(strm);

        System.out.println(data);
    }

    static String streamTostring(InputStream stream)
    {
        String data = "";

        try
        {
            StringBuilder stringbuld = new StringBuilder();
            int i;
            while ((i=stream.read())!=-1)
            {
                stringbuld.append((char)i);
            }
            data = stringbuld.toString();
        }
        catch(Exception e)
        {
            data = "No data Streamed.";
        }
        return data;
    }

这是最适合Android和任何其他JVM的纯Java解决方案。

这个解决方案非常好。。。它简单、快速，适用于大小河流！！（见上文第8号基准）

public String readFullyAsString(InputStream inputStream, String encoding)
        throws IOException {
    return readFully(inputStream).toString(encoding);
}

public byte[] readFullyAsBytes(InputStream inputStream)
        throws IOException {
    return readFully(inputStream).toByteArray();
}

private ByteArrayOutputStream readFully(InputStream inputStream)
        throws IOException {
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    byte[] buffer = new byte[1024];
    int length = 0;
    while ((length = inputStream.read(buffer)) != -1) {
        baos.write(buffer, 0, length);
    }
    return baos;
}

此外，您还可以从指定的资源路径获取InputStream：

public static InputStream getResourceAsStream(String path)
{
    InputStream myiInputStream = ClassName.class.getResourceAsStream(path);
    if (null == myiInputStream)
    {
        mylogger.info("Can't find path = ", path);
    }

    return myiInputStream;
}

要从特定路径获取InputStream，请执行以下操作：

public static URL getResource(String path)
{
    URL myURL = ClassName.class.getResource(path);
    if (null == myURL)
    {
        mylogger.info("Can't find resource path = ", path);
    }
    return myURL;
}