是否可以查询包含以下列的表名
LIKE '%myName%'
?
是否可以查询包含以下列的表名
LIKE '%myName%'
?
当前回答
这个简单的查询对我有用。
SELECT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_schema = 'schemaName'
AND column_name like '%model%';
其他回答
SQL Server:
SELECT Table_Name, Column_Name
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_CATALOG = 'YOUR_DATABASE'
AND COLUMN_NAME LIKE '%YOUR_COLUMN%'
神谕:
SELECT owner, table_name, column_name
FROM all_tab_columns
WHERE column_name LIKE '%YOUR_COLUMN_NAME%'
AND OWNER IN ('YOUR_SCHEMA_NAME');
就这么简单!!(SQL,PL/SQL)我一直使用它来查找给定数据库(模式)中列名的所有实例。
我想要一些不会让我眼睛流血的桌子和视图。
查询
SELECT
t.TABLE_TYPE AS [Type],
c.TABLE_NAME AS [Object],
c.COLUMN_NAME AS [Column]
FROM
INFORMATION_SCHEMA.COLUMNS AS c
LEFT JOIN INFORMATION_SCHEMA.TABLES AS t ON
t.TABLE_CATALOG = c.TABLE_CATALOG AND
t.TABLE_SCHEMA = c.TABLE_SCHEMA AND
t.TABLE_NAME = c.TABLE_NAME
WHERE
c.COLUMN_NAME LIKE '%myName%'
ORDER BY
[Type],
[Object],
[Column]
后果
Type Object Column
----------------------------
BASE TABLE Table1 myName1
BASE TABLE Table2 myName2
VIEW View1 myName1
VIEW View2 myName2
此外,还可以找到具有指定模式的列名。
SELECT 'DBName' AS DBName,
column_name,
table_name,
table_schema
FROM dbname.information_schema.columns
WHERE column_name LIKE '%YourColumnName%'
AND table_schema IN ( 'YourSchemaName' )
您还可以在多个数据库中找到同一列。
SELECT 'DBName1' AS DB,
column_name,
table_name,
table_schema
FROM dbname1.information_schema.columns
WHERE column_name LIKE '%YourColumnName%'
UNION
SELECT 'DBName2' AS DB,
column_name,
table_name,
table_schema
FROM dbname2.information_schema.columns
WHERE column_name LIKE '%YourColumnName%'
我不知道为什么很多人建议使用sys.columns加入sys.table。
您可以使用以下代码:
SELECT Object_name(object_id) AS TableName,
*
FROM sys.columns
WHERE NAME LIKE '%MyName%'
or
如果还需要架构名称:
SELECT *
FROM information_schema.columns
WHERE column_name LIKE '%MyName%'
它将返回table_name、schema_name、column_name
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c
ON t.object_id = c.object_id
WHERE c.name LIKE '%colName%'
ORDER BY schema_name,
table_name;