如何修复此代码中的弃用警告?或者，还有其他的选择吗?
Handler().postDelayed({
context?.let {
//code
}
}, 3000)
当前回答
使用这个
Looper.myLooper()?.let {
Handler(it).postDelayed({
//Your Code
},2500)
}
其他回答
我通常用这个
代码:
Handler(Looper.myLooper() ?: return).postDelayed({
// Code what do you want
}, 3000)
截图:
考虑使用协程
scope.launch {
delay(3000L)
// do stuff
}
Handler()和Handler(Handler.)回调回调)构造函数已弃用。因为这可能会导致bug和崩溃。显式使用Executor或Looper。
对于Java
Handler handler = new Handler(Looper.getMainLooper());
handler.postDelayed(new Runnable() {
@Override
public void run() {
//do your work here
}
}, 1000);
使用Executor而不是handler获取更多信息。 使用ScheduledExecutorService实现post delay:
ScheduledExecutorService worker = Executors.newSingleThreadScheduledExecutor();
Runnable runnable = () -> {
public void run() {
// Do something
}
};
worker.schedule(runnable, 2000, TimeUnit.MILLISECONDS);
根据文档(https://developer.android.com/reference/android/os/Handler#Handler()):
Implicitly choosing a Looper during Handler construction can lead to bugs where operations are silently lost (if the Handler is not expecting new tasks and quits), crashes (if a handler is sometimes created on a thread without a Looper active), or race conditions, where the thread a handler is associated with is not what the author anticipated. Instead, use an Executor or specify the Looper explicitly, using Looper#getMainLooper, {link android.view.View#getHandler}, or similar. If the implicit thread local behavior is required for compatibility, use new Handler(Looper.myLooper()) to make it clear to readers.
我们应该停止使用没有Looper的构造函数，而是指定一个Looper。
