我开始学习swift是通过苹果公司提供的swift上的iBook-The swift Programming Language。这本书说要创建一个空字典，应该使用[:]，就像声明数组为[]一样:
我声明一个空数组，如下所示:
let emptyArr = [] // or String[]()
但是在声明空字典时，我得到语法错误:
let emptyDict = [:]
如何声明一个空字典?
当前回答
斯威夫特4
let dicc = NSDictionary()
//MARK: - This is empty dictionary
let dic = ["":""]
//MARK:- This is variable dic means if you want to put variable
let dic2 = ["":"", "":"", "":""]
//MARK:- Variable example
let dic3 = ["name":"Shakeel Ahmed", "imageurl":"https://abc?abc.abc/etc", "address":"Rawalpindi Pakistan"]
//MARK: - This is 2nd Variable Example dictionary
let dic4 = ["name": variablename, "city": variablecity, "zip": variablezip]
//MARK:- Dictionary String with Any Object
var dic5a = [String: String]()
//MARK:- Put values in dic
var dic5a = ["key1": "value", "key2":"value2", "key3":"value3"]
var dic5b = [String:AnyObject]()
dic5b = ["name": fullname, "imageurl": imgurl, "language": imgurl] as [String : AnyObject]
or
//MARK:- Dictionary String with Any Object
let dic5 = ["name": fullname, "imageurl": imgurl, "language": imgurl] as [String : AnyObject]
//MARK:- More Easy Way
let dic6a = NSDictionary()
let dic6b = NSMutalbeDictionary()
其他回答
你必须给字典一个类型
// empty dict with Ints as keys and Strings as values
var namesOfIntegers = Dictionary<Int, String>()
如果编译器可以推断类型，则可以使用较短的语法
namesOfIntegers[16] = "sixteen"
// namesOfIntegers now contains 1 key-value pair
namesOfIntegers = [:]
// namesOfIntegers is once again an empty dictionary of type Int, String
你可以像这样简单地声明它:
var emptyDict:NSMutableDictionary = [:]
要用[:]也就是空字典字面量创建一个空字典，实际上需要首先提供上下文，就像键和值的类型一样。使用[:]创建空字典的正确方法是:
var dict: [String: Int] = [:]
它很方便你找路
var dict:Dictionary = [:]
var emptyDictionary = [String: String]()
var populatedDictionary = ["key1": "value1", "key2": "value2"]
注意:如果你打算改变字典的内容，那么就把它声明为一个变量(var)。你可以将一个空字典声明为常量(let)，但如果你想要改变它，这将是毫无意义的，因为常量值在初始化后不能被改变。
