Unity3D c#代码来自Mohsen的回答。

以下是Mohsen用c#编写的针对Unity3D的回答。它改编自上面Alec Thilenius给出的c#答案。

using UnityEngine;
using System.Collections;

public class ColorTools {

    /// <summary>
    /// Converts an HSL color value to RGB.
    /// Input: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )**strong text**
    /// Output: Color ( R: [0.0, 1.0], G: [0.0, 1.0], B: [0.0, 1.0], A: [0.0, 1.0] )
    /// </summary>
    /// <param name="hsl">Vector4 defining X = h, Y = s, Z = l, W = a. Ranges [0, 1.0]</param>
    /// <returns>RGBA Color. Ranges [0.0, 1.0]</returns>
    public static Color HslToRgba(Vector4 hsl)
    {
        float r, g, b;

        if (hsl.y == 0.0f)
            r = g = b = hsl.z;
        else
        {
            var q = hsl.z < 0.5f ? hsl.z * (1.0f + hsl.y) : hsl.z + hsl.y - hsl.z * hsl.y;
            var p = 2.0f * hsl.z - q;
            r = HueToRgb(p, q, hsl.x + 1.0f / 3.0f);
            g = HueToRgb(p, q, hsl.x);
            b = HueToRgb(p, q, hsl.x - 1.0f / 3.0f);
        }

        return new Color(r, g, b, hsl.w);
    }

    // Helper for HslToRgba
    private static float HueToRgb(float p, float q, float t)
    {
        if (t < 0.0f) t += 1.0f;
        if (t > 1.0f) t -= 1.0f;
        if (t < 1.0f / 6.0f) return p + (q - p) * 6.0f * t;
        if (t < 1.0f / 2.0f) return q;
        if (t < 2.0f / 3.0f) return p + (q - p) * (2.0f / 3.0f - t) * 6.0f;
        return p;
    }

    /// <summary>
    /// Converts an RGB color value to HSL.
    /// Input: Color ( R: [0.0, 1.0], G: [0.0, 1.0], B: [0.0, 1.0], A: [0.0, 1.0] )
    /// Output: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
    /// </summary>
    /// <param name="rgba"></param>
    /// <returns></returns>
    public static Vector4 RgbaToHsl(Color rgba)
    {

        float max = (rgba.r > rgba.g && rgba.r > rgba.b) ? rgba.r : 
            (rgba.g > rgba.b) ? rgba.g : rgba.b;
        float min = (rgba.r < rgba.g && rgba.r < rgba.b) ? rgba.r : 
            (rgba.g < rgba.b) ? rgba.g : rgba.b;

        float h, s, l;
        h = s = l = (max + min) / 2.0f;

        if (max == min)
            h = s = 0.0f;
        else
        {
            float d = max - min;
            s = (l > 0.5f) ? d / (2.0f - max - min) : d / (max + min);

            if (rgba.r > rgba.g && rgba.r > rgba.b)
                h = (rgba.g - rgba.b) / d + (rgba.g < rgba.b ? 6.0f : 0.0f);

            else if (rgba.g > rgba.b)
                h = (rgba.b - rgba.r) / d + 2.0f;

            else
                h = (rgba.r - rgba.g) / d + 4.0f;

            h /= 6.0f;
        }

        return new Vector4(h, s, l, rgba.a);
    }

}

当你需要RGB到HSV，反之亦然:

function rgbToHsv(r, g, b)
{
    r /= 255, g /= 255, b /= 255;

    var min = Math.min(r, g, b),
    max = Math.max(r, g, b),
    delta = max - min,
    h = 0, s = 0, v = max;

    if (min != max)
    {
        s = (delta / max);

        switch (max)
        {
            case r: h = (g - b) / delta + (g < b ? 6 : 0); break;
            case g: h = (b - r) / delta + 2; break;
            case b: h = (r - g) / delta + 4; break;
        }

        h /= 6;
    }

    return [h, s, v];
}

function hsvToRgb(h, s, v)
{
    var step = h / (1 / 6),
    pos = step - Math.floor(step), // the hue position within the current step
    m = (Math.floor(step) % 2) ? (1 - pos) * v : pos * v, // mix color value adjusted to the brightness(v)
    max = 1 * v,
    min = (1 - s) * v,
    med = m + ((1 - s) * (v - m)),
    r, g, b;

    switch (Math.floor(step))
    {
        case 0:
            r = max;
            g = med;
            b = min;
            break;
        case 1:
            r = med;
            g = max;
            b = min;
            break;
        case 2:
            r = min;
            g = max;
            b = med;
            break;
        case 3:
            r = min;
            g = med;
            b = max;
            break;
        case 4:
            r = med;
            g = min;
            b = max;
            break;
        case 5:
            r = max;
            g = min;
            b = med;
            break;
    }

    return [Math.round(r * 255), Math.round(g * 255), Math.round(b * 255)];
}

由于circuitpython不支持colorsys(或目前移植到)，如果你试图在树莓派上处理这个转换，下面的工作(受制于本线程其他地方提到的舍入精度限制):

def hslToRgb (h, s, l): #in range 0-1 for h,s,l
    if s == 0:
        r = g = b = l #achromatic
    else:
        def hue2rgb(p, q, t):
            if t < 0: t += 1
            if t > 1: t -= 1
            if t < 1.0 / 6.0: return p + (q - p) * 6 * t
            if t < 1.0 / 2.0: return q
            if t < 2.0 / 3.0: return p + (q - p) * ((2.0 / 3.0) - t) * 6
            return p
        if l < 0.5:
            q = l * (1 + s)
        else:
            q = l + s - l * s
        p = 2 * l - q
        r = hue2rgb(p, q, h + 1.0/3.0)
        g = hue2rgb(p, q, h)
        b = hue2rgb(p, q, h - 1.0/3.0)
    return [round(r * 255), round(g * 255), round(b * 255)]

我从Brandon Mathis的HSL Picker源代码中得到了这个。

它最初是用CoffeeScript编写的。我使用在线转换器将其转换为JavaScript，并拿出验证用户输入是否为有效RGB值的机制。这个答案适用于我的用例，因为我发现这篇文章上投票最多的答案不能产生有效的HSL值。

注意，它返回一个hsla值，表示不透明/透明。0是完全透明的，1是完全不透明的。

function rgbToHsl(rgb) {
  var a, add, b, diff, g, h, hue, l, lum, max, min, r, s, sat;
  r = parseFloat(rgb[0]) / 255;
  g = parseFloat(rgb[1]) / 255;
  b = parseFloat(rgb[2]) / 255;
  max = Math.max(r, g, b);
  min = Math.min(r, g, b);
  diff = max - min;
  add = max + min;
  hue = min === max ? 0 : r === max ? ((60 * (g - b) / diff) + 360) % 360 : g === max ? (60 * (b - r) / diff) + 120 : (60 * (r - g) / diff) + 240;
  lum = 0.5 * add;
  sat = lum === 0 ? 0 : lum === 1 ? 1 : lum <= 0.5 ? diff / add : diff / (2 - add);
  h = Math.round(hue);
  s = Math.round(sat * 100);
  l = Math.round(lum * 100);
  a = parseFloat(rgb[3]) || 1;
  return [h, s, l, a];
}

简短而精确- JS

使用这个JS代码(更多:rgb2hsl, hsv2rgb rgb2hsv和hsl2hsv) - php版本在这里

// input: h as an angle in [0,360] and s,l in [0,1] - output: r,g,b in [0,1]
function hsl2rgb(h,s,l) 
{
   let a=s*Math.min(l,1-l);
   let f= (n,k=(n+h/30)%12) => l - a*Math.max(Math.min(k-3,9-k,1),-1);
   return [f(0),f(8),f(4)];
}   

// oneliner version let hsl2rgb = (h,s,l, a=s*Math.min(l,1-l), f= (n,k=(n+h/30)%12) => l - a*Math.max(Math.min(k-3,9-k,1),-1)) => [f(0),f(8),f(4)]; // r,g,b are in [0-1], result e.g. #0812fa. let rgb2hex = (r,g,b) => "#" + [r,g,b].map(x=>Math.round(x*255).toString(16).padStart(2,0) ).join(''); console.log(`hsl: (30,0.2,0.3) --> rgb: (${hsl2rgb(30,0.2,0.3)}) --> hex: ${rgb2hex(...hsl2rgb(30,0.2,0.3))}`); // --------------- // UX // --------------- rgb= [0,0,0]; hs= [0,0,0]; let $ = x => document.querySelector(x); function changeRGB(i,e) { rgb[i]=e.target.value/255; hs = rgb2hsl(...rgb); refresh(); } function changeHS(i,e) { hs[i]=e.target.value/(i?255:1); rgb= hsl2rgb(...hs); refresh(); } function refresh() { rr = rgb.map(x=>x*255|0).join(', ') hh = rgb2hex(...rgb); tr = `RGB: ${rr}` th = `HSL: ${hs.map((x,i)=>i? (x*100).toFixed(2)+'%':x|0).join(', ')}` thh= `HEX: ${hh}` $('.box').style.backgroundColor=`rgb(${rr})`; $('.infoRGB').innerHTML=`${tr}`; $('.infoHS').innerHTML =`${th}\n${thh}`; $('#r').value=rgb[0]*255; $('#g').value=rgb[1]*255; $('#b').value=rgb[2]*255; $('#h').value=hs[0]; $('#s').value=hs[1]*255; $('#l').value=hs[2]*255; } function rgb2hsl(r,g,b) { let a=Math.max(r,g,b), n=a-Math.min(r,g,b), f=(1-Math.abs(a+a-n-1)); let h= n && ((a==r) ? (g-b)/n : ((a==g) ? 2+(b-r)/n : 4+(r-g)/n)); return [60*(h<0?h+6:h), f ? n/f : 0, (a+a-n)/2]; } refresh(); .box { width: 50px; height: 50px; margin: 20px; } body { display: flex; } <div> <input id="r" type="range" min="0" max="255" oninput="changeRGB(0,event)">R<br> <input id="g" type="range" min="0" max="255" oninput="changeRGB(1,event)">G<br> <input id="b" type="range" min="0" max="255" oninput="changeRGB(2,event)">B<br> <pre class="infoRGB"></pre> </div> <div> <div class="box hsl"></div> </div> <div> <input id="h" type="range" min="0" max="360" oninput="changeHS(0,event)">H<br> <input id="s" type="range" min="0" max="255" oninput="changeHS(1,event)">S<br> <input id="l" type="range" min="0" max="255" oninput="changeHS(2,event)">L<br> <pre class="infoHS"></pre><br> </div>

以下是我在wiki +错误分析中发现并精确描述的公式，

来自Mohsen回答的c#代码。

下面是Mohsen用c#编写的答案代码，如果有人想要的话。注意:Color是自定义类，Vector4来自OpenTK。两者都很容易被你选择的其他东西取代。

Hsl到Rgba

/// <summary>
/// Converts an HSL color value to RGB.
/// Input: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
/// Output: Color ( R: [0, 255], G: [0, 255], B: [0, 255], A: [0, 255] )
/// </summary>
/// <param name="hsl">Vector4 defining X = h, Y = s, Z = l, W = a. Ranges [0, 1.0]</param>
/// <returns>RGBA Color. Ranges [0, 255]</returns>
public static Color HslToRgba(Vector4 hsl)
{
    float r, g, b;

    if (hsl.Y == 0.0f)
        r = g = b = hsl.Z;

    else
    {
        var q = hsl.Z < 0.5f ? hsl.Z * (1.0f + hsl.Y) : hsl.Z + hsl.Y - hsl.Z * hsl.Y;
        var p = 2.0f * hsl.Z - q;
        r = HueToRgb(p, q, hsl.X + 1.0f / 3.0f);
        g = HueToRgb(p, q, hsl.X);
        b = HueToRgb(p, q, hsl.X - 1.0f / 3.0f);
    }

    return new Color((int)(r * 255), (int)(g * 255), (int)(b * 255), (int)(hsl.W * 255));
}

// Helper for HslToRgba
private static float HueToRgb(float p, float q, float t)
{
    if (t < 0.0f) t += 1.0f;
    if (t > 1.0f) t -= 1.0f;
    if (t < 1.0f / 6.0f) return p + (q - p) * 6.0f * t;
    if (t < 1.0f / 2.0f) return q;
    if (t < 2.0f / 3.0f) return p + (q - p) * (2.0f / 3.0f - t) * 6.0f;
    return p;
}

Rgba到Hsl

/// <summary>
/// Converts an RGB color value to HSL.
/// Input: Color ( R: [0, 255], G: [0, 255], B: [0, 255], A: [0, 255] )
/// Output: Vector4 ( X: [0.0, 1.0], Y: [0.0, 1.0], Z: [0.0, 1.0], W: [0.0, 1.0] )
/// </summary>
/// <param name="rgba"></param>
/// <returns></returns>
public static Vector4 RgbaToHsl(Color rgba)
{
    float r = rgba.R / 255.0f;
    float g = rgba.G / 255.0f;
    float b = rgba.B / 255.0f;

    float max = (r > g && r > b) ? r : (g > b) ? g : b;
    float min = (r < g && r < b) ? r : (g < b) ? g : b;

    float h, s, l;
    h = s = l = (max + min) / 2.0f;

    if (max == min)
        h = s = 0.0f;

    else
    {
        float d = max - min;
        s = (l > 0.5f) ? d / (2.0f - max - min) : d / (max + min);

        if (r > g && r > b)
            h = (g - b) / d + (g < b ? 6.0f : 0.0f);

        else if (g > b)
            h = (b - r) / d + 2.0f;

        else
            h = (r - g) / d + 4.0f;

        h /= 6.0f;
    }

    return new Vector4(h, s, l, rgba.A / 255.0f);
}