我最近发现onActivityResult已弃用。我们该怎么处理呢?

有什么替代方案吗?


当前回答

我使用kotlin扩展,使它非常简单。在你的扩展中添加以下扩展功能。kt文件:

fun AppCompatActivity.startForResult(intent: Intent,
    onResult: (resultCode: Int, data: Intent?) -> Unit
) {
    this.registerForActivityResult(ActivityResultContracts.StartActivityForResult()) {result ->
        onResult(result.resultCode, result.data)
    }.launch(intent)
}

现在,在继承AppCompatActivity的任何活动中,你可以使用下面的简单代码:

val i = Intent(this, TargetActivity::class.java)
startForResult(i) { resultCode, data ->
   //put your code here like:
   if (resultCode == RESULT_OK) {
      //your code here...
      }
   }
}

更新 上述实现可能导致以下异常: java.lang.IllegalStateException: LifecycleOwner xxxx正在尝试注册,而当前状态为恢复。生命周期所有者必须在启动之前调用寄存器。

因此,registerForActivityResult应该提前调用,例如在onCreate之前。这是另一种解决方案。

在你的扩展中添加以下扩展功能。kt文件:

fun AppCompatActivity.registerForResult(onResult: (resultCode: Int, data: Intent?) -> Unit):
        ActivityResultLauncher<Intent> {
    return this.registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { result ->
        onResult(result.resultCode, result.data)
    }
}

现在,在继承AppCompatActivity的任何活动中,你可以使用下面的简单代码:

为每个需要结果的操作定义一个类成员变量

private val myActionResult = registerForResult { resultCode, data ->
   //put your code here like:
   if (resultCode == RESULT_OK) {
      //your code here...
      }
   }
}

启动动作

val i = Intent(this, TargetActivity::class.java)
myActionResult.launch(i)

其他回答

在我的情况下,我试图使用意图,我直接移动到下一个活动,而不使用谷歌登录。

对我有用的是:

在OnCreate中为登录按钮设置onClickListener:

     btnSignIn.setOnClickListener {
        signIn()
        }

    private fun signIn() {
        val intent = client.signInIntent
        mainActivityResultLauncher.launch(intent)
    }

在上面的代码中,我写了去下一个活动的意图,但我必须写client.signInIntent

    var mainActivityResultLauncher = registerForActivityResult(ActivityResultContracts.StartActivityForResult()){ result ->

        if(result.resultCode == Activity.RESULT_OK){
            val data = result.data
            val task = GoogleSignIn.getSignedInAccountFromIntent(data)
            try {
                // Google Sign In was successful, authenticate with Firebase
                val account = task.getResult(ApiException::class.java)!!
                Log.d(TAG, "firebaseAuthWithGoogle:" + account.id)
                firebaseAuthWithGoogle(account.idToken!!)
            } catch (e: ApiException) {
                // Google Sign In failed, update UI appropriately
                Log.w(TAG, "Google sign in failed", e)
            }
        }
    }

我的目标是用最少的代码更改重用startActivityForResult方法的当前实现。为此,我使用onActivityResultFromLauncher方法创建了一个包装器类和接口。

interface ActivityResultLauncherWrapper {

    fun launchIntentForResult(activity: FragmentActivity, intent: Intent, requestCode: Int, callBack: OnActivityResultListener)

    fun unregister()

    interface OnActivityResultListener {
        fun onActivityResultFromLauncher(requestCode: Int, resultCode: Int, data: Intent?)
    }
}

class ActivityResultLauncherWrapperImpl : ActivityResultLauncherWrapper {
    private var weakLauncher: WeakReference<ActivityResultLauncher<Intent>>? = null

    override fun launchIntentForResult(
            activity: FragmentActivity,
            intent: Intent,
            requestCode: Int,
            callBack: ActivityResultLauncherWrapper.OnActivityResultListener
    ) {

        weakLauncher = WeakReference(
                activity.registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { result ->
                    callBack.onActivityResultFromLauncher(requestCode, result.resultCode, result.data)
                }
        )

        weakLauncher?.get()?.launch(intent)
    }

    override fun unregister() {
        weakLauncher?.get()?.unregister()
    }
}

我在我的项目中使用匕首,我在需要的地方注入了包装器

@Inject
lateinit var activityResultLauncher: ActivityResultLauncherWrapper

但是包装器也可以直接实例化:

val activityResultLauncher = ActivityResultLauncherWrapper()

然后你必须用launchIntentForResult改变startActivityForResult方法。下面是一个从片段中调用它的例子:

activityResultLauncher.launchIntentForResult(
        requireActivity(),
        intent,
        REQUEST_CODE_CONSTANT,
        object: ActivityResultLauncherWrapper.OnActivityResultListener {
            override fun onActivityResultFromLauncher(requestCode: Int, resultCode: Int, data: Intent?) {
                /*do something*/
            }
        }
)

您将在匿名对象中收到结果。 你可以在Fragment或FragmentActivity中使用OnActivityResultListener,如果你实现了接口,并像这样重构当前的实现:

class MyFragment : Fragment(), OnActivityResultListener {
   
 ...
    
override fun onActivityResultFromLauncher(requestCode: Int, resultCode: Int, data: Intent?) {/*do somthing*/}

 ...

}

正如我们所知,Kotlin类ActivityResultLauncherWrapper也可以在java代码中使用。在我的项目中也有java类。这里有一个在Fragment中实现回调接口的例子:

public class MyFragment extends Fragment implements OnActivityResultListener {
    
...

    @Inject
    ActivityResultLauncherWrapper activityResultLauncher;
//ActivityResultLauncherWrapper activityResultLauncher = new ActivityResultLauncherWrapper()

...

public void launnchActivity(@NotNull Intent intent) {
        activityResultLauncher.launchIntentForResult(requireActivity(), intent, REQUEST_CODE_CONSTANT, this);
    }

...

 @Override
    public void onActivityResultFromLauncher(int requestCode, int resultCode, Intent data) {/*do somthing*/}
...
}

我希望这有助于为您的案例构建解决方案。

下面我来解释一下这种新方法

private val scan =
        registerForActivityResult(ActivityResultContracts.StartActivityForResult())
        { result: ActivityResult ->
            if (result.resultCode == AppCompatActivity.RESULT_OK && result.data != null) {

                var selected_hub = result!!.data!!.getParcelableExtra<ExtendedBluetoothDevice>(Utils.EXTRA_DEVICE)
                Log.d(TAG,"RECONNECT PROCESS "+selected_hub!!.name)
                reconnect(selected_hub!!)

            }
        }

从活动或片段调用此方法

private fun callScan() {
        val intent = Intent(requireActivity(), ScanningMeshDevices::class.java)
        scan.launch(intent)
    }

onActivityResult, startActivityForResult, requestPermissions和onRequestPermissionsResult从1.3.0-alpha04开始在androidx.fragment上被弃用,android.app.Activity上没有。 相反,你可以使用registerForActivityResult的活动结果api。

以下是我的解决方案:

在我们的项目中,我们有超过20次的startActivityForResult(和onActivityResult)。

我们希望尽可能少地更改代码(并继续使用请求代码),同时引入一个优雅的解决方案以供将来使用。

既然我们很多开发人员都使用BaseActivity概念——为什么不利用它呢?

下面是BaseActivity:

abstract class BaseActivity : AppCompatActivity()
{
    private var requestCode: Int = -1
    private var resultHandler: ActivityResultLauncher<Intent>? = null

    override fun onCreate(savedInstanceState: Bundle?)
    {
        super.onCreate(savedInstanceState)
        registerForActivityResult()
    }

    private fun registerForActivityResult()
    {
        if (shouldRegisterForActivityResult())
        {
            resultHandler = registerForActivityResult(ActivityResultContracts.StartActivityForResult()) { result ->

                onActivityResult(result.data, requestCode, result.resultCode)
                this.requestCode = -1
            }
        }
    }

   fun startActivityForResult(requestCode: Int, intent: Intent)
   {
       this.requestCode = requestCode
       resultHandler?.launch(intent)
   }

   protected open fun onActivityResult(data: Intent?, requestCode: Int, resultCode: Int)
   {
       // For sub activities
   }

   protected open fun shouldRegisterForActivityResult(): Boolean
   {
      // Sub activities that need the onActivityResult "mechanism", should override this and return true
       return false
   }
}

这是SubActivity:

class SubActivity : BaseActivity()
{
    companion object
    {
        private const val SOME_REQUEST_CODE = 300
    }

    private fun testActivityResult()
    {
        val intent = Intent(this, OtherActivity::class.java)
        startActivityForResult(SOME_REQUEST_CODE, intent)
    }

    override fun shouldRegisterForActivityResult(): Boolean
    {
        return true
    }

    override fun onActivityResult(data: Intent?, requestCode: Int, resultCode: Int)
    {
        if (requestCode == SOME_REQUEST_CODE)
        {
            // Yes!
        }
    }
}

希望它能帮助到别人