假设我有一个垂直线性布局:

[v1]
[v2]

默认情况下,v1已经可见= GONE。我想用一个展开动画显示v1,同时下推v2。

我是这样做的:

Animation a = new Animation()
{
    int initialHeight;

    @Override
    protected void applyTransformation(float interpolatedTime, Transformation t) {
        final int newHeight = (int)(initialHeight * interpolatedTime);
        v.getLayoutParams().height = newHeight;
        v.requestLayout();
    }

    @Override
    public void initialize(int width, int height, int parentWidth, int parentHeight) {
        super.initialize(width, height, parentWidth, parentHeight);
        initialHeight = height;
    }

    @Override
    public boolean willChangeBounds() {
        return true;
    }
};

但是用这个解决方案,当动画开始时我有一个眨眼。我认为这是由于v1在应用动画之前显示全尺寸。

用javascript,这是一行jQuery!android有什么简单的方法吗?


当前回答

我改编了汤姆·埃斯特兹(Tom Esterez)目前接受的答案,这个答案有效,但动画起伏不定,不太流畅。我的解决方案基本上是用ValueAnimator替换动画,它可以与你选择的Interpolator相匹配,以实现各种效果,如超调、反弹、加速等。

这个解决方案非常适用于具有动态高度的视图(即使用WRAP_CONTENT),因为它首先测量实际所需的高度,然后动画到该高度。

public static void expand(final View v) {
    v.measure(ViewGroup.LayoutParams.MATCH_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT);
    final int targetHeight = v.getMeasuredHeight();

    // Older versions of android (pre API 21) cancel animations for views with a height of 0.
    v.getLayoutParams().height = 1;
    v.setVisibility(View.VISIBLE);

    ValueAnimator va = ValueAnimator.ofInt(1, targetHeight);
    va.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
        public void onAnimationUpdate(ValueAnimator animation) {
            v.getLayoutParams().height = (Integer) animation.getAnimatedValue();
            v.requestLayout();
        }
    });
    va.addListener(new Animator.AnimatorListener() {
        @Override
        public void onAnimationEnd(Animator animation) {
            v.getLayoutParams().height = ViewGroup.LayoutParams.WRAP_CONTENT;
        }

        @Override public void onAnimationStart(Animator animation) {}
        @Override public void onAnimationCancel(Animator animation) {}
        @Override public void onAnimationRepeat(Animator animation) {}
    });
    va.setDuration(300);
    va.setInterpolator(new OvershootInterpolator());
    va.start();
}

public static void collapse(final View v) {
    final int initialHeight = v.getMeasuredHeight();

    ValueAnimator va = ValueAnimator.ofInt(initialHeight, 0);
    va.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
        public void onAnimationUpdate(ValueAnimator animation) {
            v.getLayoutParams().height = (Integer) animation.getAnimatedValue();
            v.requestLayout();
        }
    });
    va.addListener(new Animator.AnimatorListener() {
        @Override
        public void onAnimationEnd(Animator animation) {
            v.setVisibility(View.GONE);
        }

        @Override public void onAnimationStart(Animator animation) {}
        @Override public void onAnimationCancel(Animator animation) {}
        @Override public void onAnimationRepeat(Animator animation) {}
    });
    va.setDuration(300);
    va.setInterpolator(new DecelerateInterpolator());
    va.start();
}

然后你只需调用expand(myView);或崩溃(myView);。

其他回答

是的,我同意上面的评论。事实上,它似乎是正确的(或者至少是最简单的?)事情要做的是指定(在XML中)一个初始布局高度“0px”——然后你可以传递另一个参数“toHeight”(即“最终高度”)到你的自定义动画子类的构造函数,例如,在上面的例子中,它看起来像这样:

    public DropDownAnim( View v, int toHeight ) { ... }

不管怎样,希望这能有所帮助!:)

加上Tom Esterez的精彩回答和Erik B的精彩更新,我想我应该发布我自己的观点,将扩展和收缩方法压缩为一个。通过这种方式,你可以有这样一个动作……

button.setOnClickListener(v -> expandCollapse(view));

... 它调用下面的方法,并让它在每次onClick()之后弄清楚要做什么…

public static void expandCollapse(View view) {

    boolean expand = view.getVisibility() == View.GONE;
    Interpolator easeInOutQuart = PathInterpolatorCompat.create(0.77f, 0f, 0.175f, 1f);

    view.measure(
        View.MeasureSpec.makeMeasureSpec(((View) view.getParent()).getWidth(), View.MeasureSpec.EXACTLY),
        View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED)
    );

    int height = view.getMeasuredHeight();
    int duration = (int) (height/view.getContext().getResources().getDisplayMetrics().density);

    Animation animation = new Animation() {
        @Override protected void applyTransformation(float interpolatedTime, Transformation t) {
            if (expand) {
                view.getLayoutParams().height = 1;
                view.setVisibility(View.VISIBLE);
                if (interpolatedTime == 1) {
                    view.getLayoutParams().height = ViewGroup.LayoutParams.WRAP_CONTENT;
                } else {
                    view.getLayoutParams().height = (int) (height * interpolatedTime);
                }
                view.requestLayout();
            } else {
                if (interpolatedTime == 1) {
                    view.setVisibility(View.GONE);
                } else {
                    view.getLayoutParams().height = height - (int) (height * interpolatedTime);
                    view.requestLayout();
                }
            }
        }
        @Override public boolean willChangeBounds() {
            return true;
        }
    };

    animation.setInterpolator(easeInOutQuart);
    animation.setDuration(duration);
    view.startAnimation(animation);

}

我看到这个问题很受欢迎,所以我发布了我的实际解决方案。主要的优点是你不需要知道扩展的高度来应用动画,一旦视图被扩展,它会在内容改变时适应高度。这对我来说很有效。

public static void expand(final View v) {
    int matchParentMeasureSpec = View.MeasureSpec.makeMeasureSpec(((View) v.getParent()).getWidth(), View.MeasureSpec.EXACTLY);
    int wrapContentMeasureSpec = View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED);
    v.measure(matchParentMeasureSpec, wrapContentMeasureSpec);
    final int targetHeight = v.getMeasuredHeight();
    
    // Older versions of android (pre API 21) cancel animations for views with a height of 0.
    v.getLayoutParams().height = 1;
    v.setVisibility(View.VISIBLE);
    Animation a = new Animation()
    {
        @Override
        protected void applyTransformation(float interpolatedTime, Transformation t) {
            v.getLayoutParams().height = interpolatedTime == 1
                    ? LayoutParams.WRAP_CONTENT
                    : (int)(targetHeight * interpolatedTime);
            v.requestLayout();
        }

        @Override
        public boolean willChangeBounds() {
            return true;
        }
    };
    
    // Expansion speed of 1dp/ms
    a.setDuration((int)(targetHeight / v.getContext().getResources().getDisplayMetrics().density));
    v.startAnimation(a);
}

public static void collapse(final View v) {
    final int initialHeight = v.getMeasuredHeight();

    Animation a = new Animation()
    {
        @Override
        protected void applyTransformation(float interpolatedTime, Transformation t) {
            if(interpolatedTime == 1){
                v.setVisibility(View.GONE);
            }else{
                v.getLayoutParams().height = initialHeight - (int)(initialHeight * interpolatedTime);
                v.requestLayout();
            }
        }

        @Override
        public boolean willChangeBounds() {
            return true;
        }
    };
    
    // Collapse speed of 1dp/ms
    a.setDuration((int)(initialHeight / v.getContext().getResources().getDisplayMetrics().density));
    v.startAnimation(a);
}

正如@Jefferson在评论中提到的,你可以通过改变动画的持续时间(以及速度)来获得更流畅的动画。目前,它已设置为1dp/ms的速度

我今天也遇到了同样的问题,我想这个问题的真正解决方案是这样的

<LinearLayout android:id="@+id/container"
android:animateLayoutChanges="true"
...
 />

您必须为所有涉及移位的最顶层布局设置此属性。如果你现在将一个布局的可见性设置为GONE,另一个将在消失的布局释放它时占据空间。会有一个默认的动画,这是某种“淡出”,但我认为你可以改变这个-但最后一个我没有测试,现在。


如果在RecyclerView项目中使用这个,在onBindViewHolder中设置视图的可见性来展开/折叠,并调用notifyItemChanged(position)来触发转换。

override fun onBindViewHolder(holder: ItemViewHolder, position: Int) {
        ...

        holder.list.visibility = data[position].listVisibility
        holder.expandCollapse.setOnClickListener {
            data[position].listVisibility = if (data[position].listVisibility == View.GONE) View.VISIBLE else View.GONE
            notifyItemChanged(position)
        }
    }

如果你在onBindViewHolder中执行昂贵的操作,你可以使用notifyItemChanged(位置,有效载荷)优化部分更改

private const val UPDATE_LIST_VISIBILITY = 1

    override fun onBindViewHolder(holder: ItemViewHolder, position: Int, payloads: MutableList<Any>) {
        if (payloads.contains(UPDATE_LIST_VISIBILITY)) {
            holder.list.visibility = data[position].listVisibility
        } else {
            onBindViewHolder(holder, position)
        }
    }

    override fun onBindViewHolder(holder: ItemViewHolder, position: Int) {
        ...

        holder.list.visibility = data[position].listVisibility
        holder.expandCollapse.setOnClickListener {
            data[position].listVisibility = if (data[position].listVisibility == View.GONE) View.VISIBLE else View.GONE
            notifyItemChanged(position, UPDATE_LIST_VISIBILITY)
        }
    }

展开/折叠视图的最佳解决方案:

    @Override
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
        View view = buttonView.getId() == R.id.tb_search ? fSearch : layoutSettings;
        transform(view, 200, isChecked
            ? ViewGroup.LayoutParams.WRAP_CONTENT
            : 0);
    }

    public static void transform(final View v, int duration, int targetHeight) {
        int prevHeight  = v.getHeight();
        v.setVisibility(View.VISIBLE);
        ValueAnimator animator;
        if (targetHeight == ViewGroup.LayoutParams.WRAP_CONTENT) {
            v.measure(ViewGroup.LayoutParams.MATCH_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT);
            animator = ValueAnimator.ofInt(prevHeight, v.getMeasuredHeight());
        } else {
            animator = ValueAnimator.ofInt(prevHeight, targetHeight);
        }
        animator.addUpdateListener(animation -> {
            v.getLayoutParams().height = (animation.getAnimatedFraction() == 1.0f)
                    ? targetHeight
                    : (int) animation.getAnimatedValue();
            v.requestLayout();
        });
        animator.setInterpolator(new LinearInterpolator());
        animator.setDuration(duration);
        animator.start();
    }