假设我有一个垂直线性布局:

[v1]
[v2]

默认情况下,v1已经可见= GONE。我想用一个展开动画显示v1,同时下推v2。

我是这样做的:

Animation a = new Animation()
{
    int initialHeight;

    @Override
    protected void applyTransformation(float interpolatedTime, Transformation t) {
        final int newHeight = (int)(initialHeight * interpolatedTime);
        v.getLayoutParams().height = newHeight;
        v.requestLayout();
    }

    @Override
    public void initialize(int width, int height, int parentWidth, int parentHeight) {
        super.initialize(width, height, parentWidth, parentHeight);
        initialHeight = height;
    }

    @Override
    public boolean willChangeBounds() {
        return true;
    }
};

但是用这个解决方案,当动画开始时我有一个眨眼。我认为这是由于v1在应用动画之前显示全尺寸。

用javascript,这是一行jQuery!android有什么简单的方法吗?


当前回答

来自@Tom Esterez和@Geraldo Neto的组合解决方案

public static void expandOrCollapseView(View v,boolean expand){

    if(expand){
        v.measure(ViewGroup.LayoutParams.MATCH_PARENT,ViewGroup.LayoutParams.WRAP_CONTENT);
        final int targetHeight = v.getMeasuredHeight();
        v.getLayoutParams().height = 0;
        v.setVisibility(View.VISIBLE);
        ValueAnimator valueAnimator = ValueAnimator.ofInt(targetHeight);
        valueAnimator.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
            @Override
            public void onAnimationUpdate(ValueAnimator animation) {
                v.getLayoutParams().height = (int) animation.getAnimatedValue();
                v.requestLayout();
            }
        });
        valueAnimator.setInterpolator(new DecelerateInterpolator());
        valueAnimator.setDuration(500);
        valueAnimator.start();
    }
    else
    {
        final int initialHeight = v.getMeasuredHeight();
        ValueAnimator valueAnimator = ValueAnimator.ofInt(initialHeight,0);
        valueAnimator.setInterpolator(new DecelerateInterpolator());
        valueAnimator.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
            @Override
            public void onAnimationUpdate(ValueAnimator animation) {
                v.getLayoutParams().height = (int) animation.getAnimatedValue();
                v.requestLayout();
                if((int)animation.getAnimatedValue() == 0)
                    v.setVisibility(View.GONE);
            }
        });
        valueAnimator.setInterpolator(new DecelerateInterpolator());
        valueAnimator.setDuration(500);
        valueAnimator.start();
    }
}

//sample usage
expandOrCollapseView((Your ViewGroup),(Your ViewGroup).getVisibility()!=View.VISIBLE);

其他回答

public static void slide(View v, int speed, int pos) {
    v.animate().setDuration(speed);
    v.animate().translationY(pos);
    v.animate().start();
}

// slide down
slide(yourView, 250, yourViewHeight);
// slide up
slide(yourView, 250, 0);

使用ValueAnimator:

ValueAnimator expandAnimation = ValueAnimator.ofInt(mainView.getHeight(), 400);
expandAnimation.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
    @Override
    public void onAnimationUpdate(final ValueAnimator animation) {
        int height = (Integer) animation.getAnimatedValue();
        RelativeLayout.LayoutParams lp = (LayoutParams) mainView.getLayoutParams();
        lp.height = height;
    }
});


expandAnimation.setDuration(500);
expandAnimation.start();

加上Tom Esterez的精彩回答和Erik B的精彩更新,我想我应该发布我自己的观点,将扩展和收缩方法压缩为一个。通过这种方式,你可以有这样一个动作……

button.setOnClickListener(v -> expandCollapse(view));

... 它调用下面的方法,并让它在每次onClick()之后弄清楚要做什么…

public static void expandCollapse(View view) {

    boolean expand = view.getVisibility() == View.GONE;
    Interpolator easeInOutQuart = PathInterpolatorCompat.create(0.77f, 0f, 0.175f, 1f);

    view.measure(
        View.MeasureSpec.makeMeasureSpec(((View) view.getParent()).getWidth(), View.MeasureSpec.EXACTLY),
        View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED)
    );

    int height = view.getMeasuredHeight();
    int duration = (int) (height/view.getContext().getResources().getDisplayMetrics().density);

    Animation animation = new Animation() {
        @Override protected void applyTransformation(float interpolatedTime, Transformation t) {
            if (expand) {
                view.getLayoutParams().height = 1;
                view.setVisibility(View.VISIBLE);
                if (interpolatedTime == 1) {
                    view.getLayoutParams().height = ViewGroup.LayoutParams.WRAP_CONTENT;
                } else {
                    view.getLayoutParams().height = (int) (height * interpolatedTime);
                }
                view.requestLayout();
            } else {
                if (interpolatedTime == 1) {
                    view.setVisibility(View.GONE);
                } else {
                    view.getLayoutParams().height = height - (int) (height * interpolatedTime);
                    view.requestLayout();
                }
            }
        }
        @Override public boolean willChangeBounds() {
            return true;
        }
    };

    animation.setInterpolator(easeInOutQuart);
    animation.setDuration(duration);
    view.startAnimation(animation);

}

我试图做一个我认为非常相似的动画,并找到了一个优雅的解决方案。这段代码假设你总是从0->h或h->0 (h是最大高度)。三个构造函数参数是view =要动画的视图(在我的例子中是webview), targetHeight =视图的最大高度,以及down =一个布尔值,用于指定方向(true =展开,false =折叠)。

public class DropDownAnim extends Animation {
    private final int targetHeight;
    private final View view;
    private final boolean down;

    public DropDownAnim(View view, int targetHeight, boolean down) {
        this.view = view;
        this.targetHeight = targetHeight;
        this.down = down;
    }

    @Override
    protected void applyTransformation(float interpolatedTime, Transformation t) {
        int newHeight;
        if (down) {
            newHeight = (int) (targetHeight * interpolatedTime);
        } else {
            newHeight = (int) (targetHeight * (1 - interpolatedTime));
        }
        view.getLayoutParams().height = newHeight;
        view.requestLayout();
    }

    @Override
    public void initialize(int width, int height, int parentWidth,
            int parentHeight) {
        super.initialize(width, height, parentWidth, parentHeight);
    }

    @Override
    public boolean willChangeBounds() {
        return true;
    }
}

是的,我同意上面的评论。事实上,它似乎是正确的(或者至少是最简单的?)事情要做的是指定(在XML中)一个初始布局高度“0px”——然后你可以传递另一个参数“toHeight”(即“最终高度”)到你的自定义动画子类的构造函数,例如,在上面的例子中,它看起来像这样:

    public DropDownAnim( View v, int toHeight ) { ... }

不管怎样,希望这能有所帮助!:)