Java中是否内置了一个函数,使字符串中每个单词的第一个字符大写,而不影响其他字符?

例子:

乔恩·斯基特->乔恩·斯基特 miles o'Brien -> miles o'Brien (B仍然是大写,这排除了Title Case) 老麦当劳->

*(老麦当劳也会被发现,但我不指望它有那么聪明。)

快速浏览一下Java字符串文档就会发现只有toUpperCase()和toLowerCase(),它们当然没有提供所需的行为。当然,谷歌的结果主要是这两个函数。它看起来像一个已经被发明出来的轮子,所以问一下也无妨,这样我以后就可以用它了。


当前回答

如果你需要大写标题,这可能很有用。它将每个由" "分隔的子字符串大写,除了"a"或"the"之类的指定字符串。我还没有运行它,因为已经晚了,不过应该没问题。一次使用Apache Commons StringUtils.join()。如果你愿意,你可以用一个简单的循环来代替它。

private static String capitalize(String string) {
    if (string == null) return null;
    String[] wordArray = string.split(" "); // Split string to analyze word by word.
    int i = 0;
lowercase:
    for (String word : wordArray) {
        if (word != wordArray[0]) { // First word always in capital
            String [] lowercaseWords = {"a", "an", "as", "and", "although", "at", "because", "but", "by", "for", "in", "nor", "of", "on", "or", "so", "the", "to", "up", "yet"};
            for (String word2 : lowercaseWords) {
                if (word.equals(word2)) {
                    wordArray[i] = word;
                    i++;
                    continue lowercase;
                }
            }
        }
        char[] characterArray = word.toCharArray();
        characterArray[0] = Character.toTitleCase(characterArray[0]);
        wordArray[i] = new String(characterArray);
        i++;
    }
    return StringUtils.join(wordArray, " "); // Re-join string
}

其他回答

public void capitaliseFirstLetterOfEachWord()
{
    String value="this will capitalise first character of each word of this string";
    String[] wordSplit=value.split(" ");
    StringBuilder sb=new StringBuilder();

    for (int i=0;i<wordSplit.length;i++){

        sb.append(wordSplit[i].substring(0,1).toUpperCase().
                concat(wordSplit[i].substring(1)).concat(" "));
    }
    System.out.println(sb);
}

试试这个:

 private String capitalizer(String word){

        String[] words = word.split(" ");
        StringBuilder sb = new StringBuilder();
        if (words[0].length() > 0) {
            sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
            for (int i = 1; i < words.length; i++) {
                sb.append(" ");
                sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
            }
        }
        return  sb.toString();
    }

worddutil .capitalize(str) (from apache common -text)

(注意:如果你需要“fOO BAr”变成“fOO BAr”,那么用大写的(..)代替)

这里是RxJava解决方案的问题

    String title = "this is a title";
    StringBuilder stringBuilder = new StringBuilder();
    Observable.fromArray(title.trim().split("\\s"))
        .map(word -> word.substring(0, 1).toUpperCase() + word.substring(1).toLowerCase())
        .toList()
        .map(wordList -> {
            for (String word : wordList) {
                stringBuilder.append(word).append(" ");
            }
            return stringBuilder.toString();
        })
        .subscribe(result -> System.out.println(result));

不过我还不喜欢for循环。

Use:

    String text = "jon skeet, miles o'brien, old mcdonald";

    Pattern pattern = Pattern.compile("\\b([a-z])([\\w]*)");
    Matcher matcher = pattern.matcher(text);
    StringBuffer buffer = new StringBuffer();
    while (matcher.find()) {
        matcher.appendReplacement(buffer, matcher.group(1).toUpperCase() + matcher.group(2));
    }
    String capitalized = matcher.appendTail(buffer).toString();
    System.out.println(capitalized);