我正在Chrome中开发一个扩展,我想知道:当一个元素出现时,最好的方法是什么?使用纯javascript,间隔检查,直到一个元素存在,或jQuery有一些简单的方法来做到这一点?


当前回答

受杰米·胡伯的启发,我想出了一个答案。

这是一个基于承诺的函数,你可以设置:

最大尝试次数-默认为10; 延迟(毫秒)-默认为100毫秒。

因此,默认情况下,它将等待1秒,直到元素出现在DOM上。

如果它没有出现,它将返回一个承诺。用null拒绝,这样您就可以按照您的愿望处理错误。

Code

export function _waitForElement(selector, delay = 10, tries = 100) {
  const element = document.querySelector(selector);


  if (!window[`__${selector}`]) {
    window[`__${selector}`] = 0;
    window[`__${selector}__delay`] = delay;
    window[`__${selector}__tries`] = tries;
  }

  function _search() {
    return new Promise((resolve) => {
      window[`__${selector}`]++;
      setTimeout(resolve, window[`__${selector}__delay`]);
    });
  }

  if (element === null) {
    if (window[`__${selector}`] >= window[`__${selector}__tries`]) {
      window[`__${selector}`] = 0;
      return Promise.resolve(null);
    }

    return _search().then(() => _waitForElement(selector));
  } else {
    return Promise.resolve(element);
  }
}

用法:

async function wait(){
    try{
        const $el = await waitForElement(".llama");
        console.log($el);
    } catch(err){
        console.error("Timeout - couldn't find element.")
    }
} 

wait();

在上面的例子中,它将等待选择器.llama。您可以添加更大的延迟,并在StackoverFlow的控制台上进行测试。

只需将类llama添加到DOM上的任何元素。

其他回答

我采取@Yong Wong的解决方案,但它有一个可选的超时,你可以指定根节点从哪里你想等待元素。

完整的异步/等待。

const $ = (selector, opts) => {
  let timeout = undefined;
  let root = undefined;

  if (opts) {
    ({ root, timeout } = opts);
  }

  if (root === undefined) root = document.body;
  
  const nodeFound = root.querySelector(selector);
  if (nodeFound) return new Promise(resolve => resolve(nodeFound));

  return new Promise((resolve, reject) => {
    let callback = () => {
      observer.disconnect();
    };

    const _resolve = (node) => {
      callback();
      resolve(node);
    };

    const _reject = (err) => {
      callback();
      reject(err);
    };

    if (timeout && timeout > 0) {
      const handle = setTimeout(() => {
        _reject(new Error("Element not found: timeout exceeded."));
      }, timeout);
      callback = () => {
        observer.disconnect();
        clearTimeout(handle);
      };
    }

    const observer = new MutationObserver(mutations => {
      for (const mutation of mutations) {
        for (const addedNode of mutation.addedNodes) {
          if (addedNode.matches(selector)) {
            _resolve(addedNode);
            return;
          }
        }
      }
    });

    observer.observe(root, {
      childList: true,
      subtree: true,
    });
  });
}

示例调用:

// wait for 10 seconds for 'div.bla-bla-bla' to appear as a child of 'div.some-container'
await $("div.bla-bla-bla", {
  timeout: 10000,
  root: document.querySelector("div.some-container") 
});

由于性能问题,DOMNodeInserted和其他DOM突变事件已被弃用——推荐的方法是使用MutationObserver监视DOM。不过,它只在较新的浏览器中受支持,所以当MutationObserver不可用时,您应该回到DOMNodeInserted上。

let observer = new MutationObserver((mutations) => {
  mutations.forEach((mutation) => {
    if (!mutation.addedNodes) return

    for (let i = 0; i < mutation.addedNodes.length; i++) {
      // do things to your newly added nodes here
      let node = mutation.addedNodes[i]
    }
  })
})

observer.observe(document.body, {
    childList: true
  , subtree: true
  , attributes: false
  , characterData: false
})

// stop watching using:
observer.disconnect()

这里有一个用Javascript编写的promise返回解决方案(没有混乱的回调)。默认情况下,它每200ms检查一次。

function waitFor(selector) {
    return new Promise(function (res, rej) {
        waitForElementToDisplay(selector, 200);
        function waitForElementToDisplay(selector, time) {
            if (document.querySelector(selector) != null) {
                res(document.querySelector(selector));
            }
            else {
                setTimeout(function () {
                    waitForElementToDisplay(selector, time);
                }, time);
            }
        }
    });
}

我认为仍然没有任何答案在这里与简单易读的工作实例。使用MutationObserver接口来检测DOM的变化,如下所示:

var observer = new MutationObserver(function(mutations) { if ($("p").length) { console.log("Exist, lets do something"); observer.disconnect(); //We can disconnect observer once the element exist if we dont want observe more changes in the DOM } }); // Start observing observer.observe(document.body, { //document.body is node target to observe childList: true, //This is a must have for the observer with subtree subtree: true //Set to true if changes must also be observed in descendants. }); $(document).ready(function() { $("button").on("click", function() { $("p").remove(); setTimeout(function() { $("#newContent").append("<p>New element</p>"); }, 2000); }); }); <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <button>New content</button> <div id="newContent"></div>

注意:关于MutationObserver的西班牙语Mozilla文档更多 详情,如果你想了解更多信息。

你也可以使用getElementById代替querySelector

这个函数和 https://stackoverflow.com/a/61511955/10798137

  async function waitForElementById(id, timeout = null, location = document.body) {
    return new Promise((resolve) => {
        let element = document.getElementById(id);
        if (element) {
            return resolve(element);
        }

        const observer = new MutationObserver(async () => {
            let element = document.getElementById(id);
            if (element) {
                resolve(element);
                observer.disconnect();
            } else {
                if (timeout) {
                    async function timeOver() {
                        return new Promise((resolve) => {
                            setTimeout(() => {
                                observer.disconnect();
                                resolve(false);
                            }, timeout);
                        });
                    }
                    resolve(await timeOver());
                }
            }
        });

        observer.observe(location, {
            childList: true,
            subtree: true,
        });
    });

使用它


    waitForElement("tag_id", 500).then((elm) => {
      console.log(elm)
    })

Or


    var elm = async waitForElement("tag_id", 500)