我如何使一个表达式匹配绝对任何东西(包括空白)?例子:
Regex:我买了_____羊。
火柴:我买了羊。我买了一只羊。我买了五只羊。
我尝试使用(.*),但似乎没有工作。
我如何使一个表达式匹配绝对任何东西(包括空白)?例子:
Regex:我买了_____羊。
火柴:我买了羊。我买了一只羊。我买了五只羊。
我尝试使用(.*),但似乎没有工作。
当前回答
/。如果没有换行符,*/效果很好。如果它必须匹配换行符,这里有一些解决方案:
Solution | Description |
---|---|
/.*/s |
/s (dot all flag) makes . (wildcard character) match anything, including line breaks. Throw in an * (asterisk), and it will match everything. Read more. |
/[\s\S]*/ |
\s (whitespace metacharacter) will match any whitespace character (space; tab; line break; ...), and \S (opposite of \s ) will match anything that is not a whitespace character. * (asterisk) will match all occurrences of the character set (Encapsulated by [] ). Read more. |
其他回答
Regex: /I bought.*sheep./ Matches - the whole string till the end of line I bought sheep. I bought a sheep. I bought five sheep. Regex: /I bought(.*)sheep./ Matches - the whole string and also capture the sub string within () for further use I bought sheep. I bought a sheep. I bought five sheep. I boughtsheep. I bought a sheep. I bought fivesheep. Example using Javascript/Regex 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[0]; Output: "I bought sheep. I bought a sheep. I bought five sheep." 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[1]; Output: " sheep. I bought a sheep. I bought five "
(.*?)匹配任何东西-我已经使用它很多年了。
试试这个:
I bought (.* )?sheep
甚至
I bought .*sheep
通常点匹配除换行符以外的任何字符。
因此,如果。*不起作用,设置“点也匹配换行符”选项(或使用(?s).*)。
如果您正在使用JavaScript,它没有“dotall”选项,请尝试[\s\ s]*。这意味着“匹配任意数量的空白或非空白字符”——有效地“匹配任何字符串”。
另一个只适用于JavaScript的选项是[^]*,它也匹配任何字符串。但是[\s\ s]*似乎使用得更广泛,可能是因为它更便于携带。
<?php
$str = "I bought _ sheep";
preg_match("/I bought (.*?) sheep", $str, $match);
print_r($match);
?>
http://sandbox.phpcode.eu/g/b2243.php