使用.*，并确保您使用的实现相当于单行，以便在行尾匹配。

这里有一个很好的解释-> http://www.regular-expressions.info/dot.html

试试这个:

I bought (.* )?sheep

甚至

I bought .*sheep

(.*?)匹配任何东西-我已经使用它很多年了。

如果你使用JavaScript, ES2018添加了/s (dotAll)标志。带有/s标志的点。将匹配任何字符，包括换行符。

游戏机log(“line_1 \ nline_2”。match (/ + / s))

注意:目前还不是所有浏览器都支持它。

Regex: /I bought.*sheep./ Matches - the whole string till the end of line I bought sheep. I bought a sheep. I bought five sheep. Regex: /I bought(.*)sheep./ Matches - the whole string and also capture the sub string within () for further use I bought sheep. I bought a sheep. I bought five sheep. I boughtsheep. I bought a sheep. I bought fivesheep. Example using Javascript/Regex 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[0]; Output: "I bought sheep. I bought a sheep. I bought five sheep." 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[1]; Output: " sheep. I bought a sheep. I bought five "

(.*?)不适合我。我试图匹配注释周围的/* */，其中可能包含多行。

试试这个:

([a]|[^a])

这个正则表达式匹配a或除a之外的任何东西，当然，它意味着匹配所有东西。

顺便说一句，在我的情况下，/\*([a]|[^a])*/匹配C风格的注释。

感谢@mpen提供了一个更简洁的方式。

[\s\S]