在我的例子中，我依赖snackbar# isshows()来获得更好的用户体验。

private Snackbar exitSnackBar;

@Override
public void onBackPressed() {
    if (isNavDrawerOpen()) {
        closeNavDrawer();
    } else if (getSupportFragmentManager().getBackStackEntryCount() == 0) {
        if (exitSnackBar != null && exitSnackBar.isShown()) {
            super.onBackPressed();
        } else {
            exitSnackBar = Snackbar.make(
                    binding.getRoot(),
                    R.string.navigation_exit,
                    2000
            );
            exitSnackBar.show();
        }
    } else {
        super.onBackPressed();
    }
}

private static final int TIME_INTERVAL = 2000;
private long mBackPressed;
    @Override
        public void onBackPressed() {

            if (mBackPressed + TIME_INTERVAL > System.currentTimeMillis()) {
                super.onBackPressed();
                Intent intent = new Intent(FirstpageActivity.this,
                        HomepageActivity.class);
                startActivity(intent);
                finish();

                return;
            } else {

                Toast.makeText(getBaseContext(),
                        "Tap back button twice  to go Home.", Toast.LENGTH_SHORT)
                        .show();

                mBackPressed = System.currentTimeMillis();

            }

        }

我已经尝试为此创建了一个utils类，因此任何活动或片段都可以实现这一点，从而变得更简单。

代码是用Kotlin编写的，并且具有java互操作。

我使用协程来延迟和重置标志变量。但是您可以根据自己的需要进行修改。

其他文件:SafeToast.kt

lateinit var toast: Toast

fun Context.safeToast(msg: String, length: Int = Toast.LENGTH_LONG, action: (Context) -> Toast = default) {
    toast = SafeToast.makeText(this@safeToast, msg, length).apply {
        // do anything new here
        action(this@safeToast)
        show()
    }
}

fun Context.toastSpammable(msg: String) {
    cancel()
    safeToast(msg, Toast.LENGTH_SHORT)
}

fun Fragment.toastSpammable(msg: String) {
    cancel()
    requireContext().safeToast(msg, Toast.LENGTH_SHORT)
}

private val default: (Context) -> Toast = { it -> SafeToast.makeText(it, "", Toast.LENGTH_LONG) }

private fun cancel() {
    if (::toast.isInitialized) toast.cancel()
}

ActivityUtils.kt

@file:JvmMultifileClass
@file:JvmName("ActivityUtils")
package your.company.com

import android.app.Activity
import your.company.com.R
import kotlinx.coroutines.GlobalScope
import kotlinx.coroutines.delay
import kotlinx.coroutines.launch


private var backButtonPressedTwice = false

fun Activity.onBackPressedTwiceFinish() {
    onBackPressedTwiceFinish(getString(R.string.msg_back_pressed_to_exit), 2000)
}

fun Activity.onBackPressedTwiceFinish(@StringRes message: Int, time: Long) {
    onBackPressedTwiceFinish(getString(message), time)
}

fun Activity.onBackPressedTwiceFinish(message: String, time: Long) {
    if (backButtonPressedTwice) {
        onBackPressed()
    } else {
        backButtonPressedTwice = true
        toastSpammable(message)
        GlobalScope.launch {
            delay(time)
            backButtonPressedTwice = false
        }
    }
}

Kotlin中的用法

// ActivityA.kt
override fun onBackPressed() {
    onBackPressedTwiceFinish()
}

在Java中使用

@Override 
public void onBackPressed() {
    ActivityUtils.onBackPressedTwiceFinish()
}

这段代码的灵感来自这里的@webserveis

在所有这些答案中，有一个非常简单的方法。

只需在onBackPressed()方法中编写以下代码。

long back_pressed;

@Override
public void onBackPressed() {
    if (back_pressed + 1000 > System.currentTimeMillis()){
        super.onBackPressed();
    }
    else{
        Toast.makeText(getBaseContext(),
                "Press once again to exit!", Toast.LENGTH_SHORT)
                .show();
    }
    back_pressed = System.currentTimeMillis();
}

您需要将back_pressed对象定义为活动中的long。

我知道这是一个很老的问题，但这是你想做的最简单的方法。

@Override
public void onBackPressed() {
   ++k; //initialise k when you first start your activity.
   if(k==1){
      //do whatever you want to do on first click for example:
      Toast.makeText(this, "Press back one more time to exit", Toast.LENGTH_LONG).show();
   }else{
      //do whatever you want to do on the click after the first for example:
      finish(); 
   }
}

我知道这不是最好的方法，但它很有效!

我只是想分享一下我是如何做到的，我只是在我的活动中添加了:

private boolean doubleBackToExitPressedOnce = false;

@Override
protected void onResume() {
    super.onResume();
    // .... other stuff in my onResume ....
    this.doubleBackToExitPressedOnce = false;
}

@Override
public void onBackPressed() {
    if (doubleBackToExitPressedOnce) {
        super.onBackPressed();
        return;
    }
    this.doubleBackToExitPressedOnce = true;
    Toast.makeText(this, R.string.exit_press_back_twice_message, Toast.LENGTH_SHORT).show();
}

它就像我想要的那样工作。包括每当活动恢复时对状态的重置。