我已经实现了一个超轻量级的库，可以根据给出的一些答案来检测使用的设备:https://github.com/schickling/Device.swift

它可以通过迦太基安装，并像这样使用:

import Device

let deviceType = UIDevice.currentDevice().deviceType

switch deviceType {
case .IPhone6: print("Do stuff for iPhone6")
case .IPadMini: print("Do stuff for iPad mini")
default: print("Check other available cases of DeviceType")
}

使用Swift 3 (Xcode 8.3)

    func deviceName() -> String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let str = withUnsafePointer(to: &systemInfo.machine.0) { ptr in
            return String(cString: ptr)
        }
        return str
    }

注意:根据官方开发论坛的回答，以这种方式使用元组是安全的。大Int8元组的内存对齐方式将与大Int8数组相同。即:连续且无填充。

你可以使用BDLocalizedDevicesModels框架来解析设备信息并获得名称。

然后在代码中调用UIDevice.currentDevice.productName。

对于设备和模拟器， 创建一个名为UIDevice.swift的新swift文件

添加以下代码

import UIKit


public extension UIDevice {

var modelName: String {
    #if (arch(i386) || arch(x86_64)) && os(iOS)
        let DEVICE_IS_SIMULATOR = true
    #else
        let DEVICE_IS_SIMULATOR = false
    #endif

    var machineString : String = ""

    if DEVICE_IS_SIMULATOR == true
    {

        if let dir = NSProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
            machineString = dir
        }
    }
    else {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        machineString = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8 where value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
    }
    switch machineString {
    case "iPod5,1":                                 return "iPod Touch 5"
    case "iPod7,1":                                 return "iPod Touch 6"
    case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return "iPhone 4"
    case "iPhone4,1":                               return "iPhone 4s"
    case "iPhone5,1", "iPhone5,2":                  return "iPhone 5"
    case "iPhone5,3", "iPhone5,4":                  return "iPhone 5c"
    case "iPhone6,1", "iPhone6,2":                  return "iPhone 5s"
    case "iPhone7,2":                               return "iPhone 6"
    case "iPhone7,1":                               return "iPhone 6 Plus"
    case "iPhone8,1":                               return "iPhone 6s"
    case "iPhone8,2":                               return "iPhone 6s Plus"
    case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
    case "iPad3,1", "iPad3,2", "iPad3,3":           return "iPad 3"
    case "iPad3,4", "iPad3,5", "iPad3,6":           return "iPad 4"
    case "iPad4,1", "iPad4,2", "iPad4,3":           return "iPad Air"
    case "iPad5,3", "iPad5,4":                      return "iPad Air 2"
    case "iPad2,5", "iPad2,6", "iPad2,7":           return "iPad Mini"
    case "iPad4,4", "iPad4,5", "iPad4,6":           return "iPad Mini 2"
    case "iPad4,7", "iPad4,8", "iPad4,9":           return "iPad Mini 3"
    case "iPad5,1", "iPad5,2":                      return "iPad Mini 4"
    case "iPad6,7", "iPad6,8":                      return "iPad Pro"
    case "AppleTV5,3":                              return "Apple TV"
    default:                                        return machineString
    }
}
}

然后在你的视图控制器中，

 let deviceType = UIDevice.currentDevice().modelName

    if deviceType.lowercaseString.rangeOfString("iphone 4") != nil {
       print("iPhone 4 or iphone 4s")
    }
    else if deviceType.lowercaseString.rangeOfString("iphone 5") != nil {
        print("iPhone 5 or iphone 5s or iphone 5c")
    }
   else if deviceType.lowercaseString.rangeOfString("iphone 6") != nil {
        print("iPhone 6 Series")
    }

如果你不想每次苹果向设备家族添加新型号时都更新你的代码，可以使用下面的方法只返回型号代码。

func platform() -> String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let modelCode = withUnsafeMutablePointer(&systemInfo.machine) {
            ptr in String.fromCString(UnsafePointer<CChar>(ptr))
        }

        return String.fromCString(modelCode!)!
}

获取模型名称(营销名称)的最简单方法

小心使用私有API -[UIDevice _deviceinfokey:]，你不会被Apple拒绝。

// works on both simulators and real devices, iOS 8 to iOS 12
NSString *deviceModelName(void) {
    // For Simulator
    NSString *modelName = NSProcessInfo.processInfo.environment[@"SIMULATOR_DEVICE_NAME"];
    if (modelName.length > 0) {
        return modelName;
    }

    // For real devices and simulators, except simulators running on iOS 8.x
    UIDevice *device = [UIDevice currentDevice];
    NSString *selName = [NSString stringWithFormat:@"_%@ForKey:", @"deviceInfo"];
    SEL selector = NSSelectorFromString(selName);
    if ([device respondsToSelector:selector]) {
#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Warc-performSelector-leaks"
        modelName = [device performSelector:selector withObject:@"marketing-name"];
#pragma clang diagnostic pop
    }
    return modelName;
}

我是怎么得到"marketing-name"这个密钥的?

运行在模拟器上的NSProcessInfo.processInfo.environment包含一个名为“SIMULATOR_CAPABILITIES”的键，其值是一个plist文件。然后你打开plist文件，你会得到模型名称的关键字“marketing-name”。