有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
我的简单解决方案是按设备分组，支持新设备iPhone 8和iPhone X在Swift 3:
public extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPhone3,1", "iPhone3,2", "iPhone3,3", "iPhone4,1":
return "iPhone 4"
case "iPhone5,1", "iPhone5,2", "iPhone5,3", "iPhone5,4", "iPhone6,1", "iPhone6,2", "iPhone8,4":
return "iPhone 5"
case "iPhone7,2", "iPhone8,1", "iPhone9,1", "iPhone9,3", "iPhone10,1", "iPhone10,4":
return "iPhone 6,7,8"
case "iPhone7,1", "iPhone8,2", "iPhone9,2", "iPhone9,4", "iPhone10,2", "iPhone10,5":
return "iPhone Plus"
case "iPhone10,3", "iPhone10,6":
return "iPhone X"
case "i386", "x86_64":
return "Simulator"
default:
return identifier
}
}
}
和使用:
switch UIDevice.current.modelName {
case "iPhone 4":
case "iPhone 5":
case "iPhone 6,7,8":
case "iPhone Plus":
case "iPhone X":
case "Simulator":
default:
}
其他回答
还有另一个简单的替代方案(模型标识符参考可在https://www.theiphonewiki.com/wiki/Models):找到)
Swift 3/4/5的更新答案，包括字符串修剪和模拟器支持:
func modelIdentifier() -> String {
if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
var sysinfo = utsname()
uname(&sysinfo) // ignore return value
return String(bytes: Data(bytes: &sysinfo.machine, count: Int(_SYS_NAMELEN)), encoding: .ascii)!.trimmingCharacters(in: .controlCharacters)
}
下面是获取硬件字符串的代码，但是您需要比较这些硬件字符串才能知道它是哪个设备。我已经创建了一个类，包含几乎所有的设备字符串(我们保持字符串最新的新设备)。使用方便，请检查
吉hub /恶魔大师
Objective-C: GitHub/DeviceUtil
public func hardwareString() -> String {
var name: [Int32] = [CTL_HW, HW_MACHINE]
var size: Int = 2
sysctl(&name, 2, nil, &size, &name, 0)
var hw_machine = [CChar](count: Int(size), repeatedValue: 0)
sysctl(&name, 2, &hw_machine, &size, &name, 0)
let hardware: String = String.fromCString(hw_machine)!
return hardware
}
我在UIDevice上做了另一个示例扩展，包括基于@HAS的答案的模拟器模型标识符。它在上面的Swift3.2(包括Swift 4)中工作得很好。x, Swift 5):
let modelName = UIDevice.current.modelName
新增型号:iPod touch(第七代)，iPhone SE(第二代)，iPhone 12 mini, iPhone 12 Pro, iPhone 12 Pro Max, iPad Pro(12.9英寸)(第四代)
import UIKit
public extension UIDevice {
/// pares the deveice name as the standard name
var modelName: String {
#if targetEnvironment(simulator)
let identifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"]!
#else
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
#endif
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPod9,1": return "iPod touch (7th generation)"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPhone12,1": return "iPhone 11"
case "iPhone12,3": return "iPhone 11 Pro"
case "iPhone12,5": return "iPhone 11 Pro Max"
case "iPhone12,8": return "iPhone SE (2nd generation)"
case "iPhone13,1": return "iPhone 12 mini"
case "iPhone13,2": return "iPhone 12"
case "iPhone13,3": return "iPhone 12 Pro"
case "iPhone13,4": return "iPhone 12 Pro Max"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)"
case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
default: return identifier
}
}
}
如果你不想每次苹果向设备家族添加新型号时都更新你的代码，可以使用下面的方法只返回型号代码。
func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafeMutablePointer(&systemInfo.machine) {
ptr in String.fromCString(UnsafePointer<CChar>(ptr))
}
return String.fromCString(modelCode!)!
}
维基设备
异步库，从iphonewiki给你答案
A crazy little experiment for automation fans like me. I made this algorithm that reads the identification code of the device, physical or simulated, and load the theiphonewiki page to extrapolate the model name based on the identification code (example iPhone11,2 -> iPhone XS). The algorithm interfaces with the WIKI page using the internal Wiki API Sandbox tool that allows you to have a JSON response, however the content is not obtainable in JSON (just the part that was needed, that is the wikitables) so I parsed the HTML content to get to the device name, without using third parts HTML parsing libraries.
优点:总是更新，你不需要添加新的设备
缺点:异步回答使用维基页面从网络
附注:请随意改进我的代码，以获得更精确的结果和更优雅的语法 P.S.S.如果你需要更直接的答案，请使用我之前在本页的答案
public extension UIDevice {
var identifier: String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
if modelCode == "x86_64" {
if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
if let simMap = String(validatingUTF8: simModelCode) {
return simMap
}
}
}
return modelCode ?? "?unrecognized?"
}
}
class WikiDevice {
static func model(_ completion: @escaping ((String) -> ())){
let unrecognized = "?unrecognized?"
guard let wikiUrl=URL(string:"https://www.theiphonewiki.com//w/api.php?action=parse&format=json&page=Models") else { return completion(unrecognized) }
var identifier: String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
if modelCode == "x86_64" {
if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
if let simMap = String(validatingUTF8: simModelCode) {
return simMap
}
}
}
return modelCode ?? unrecognized
}
guard identifier != unrecognized else { return completion(unrecognized)}
let request = URLRequest(url: wikiUrl)
URLSession.shared.dataTask(with: request) { (data, response, error) in
do {
guard let data = data,
let response = response as? HTTPURLResponse, (200 ..< 300) ~= response.statusCode,
error == nil else { return completion(unrecognized) }
guard let convertedString = String(data: data, encoding: String.Encoding.utf8) else { return completion(unrecognized) }
var wikiTables = convertedString.components(separatedBy: "wikitable")
wikiTables.removeFirst()
var tables = [[String]]()
wikiTables.enumerated().forEach{ index,table in
let rawRows = table.components(separatedBy: #"<tr>\n<td"#)
var counter = 0
var rows = [String]()
while counter < rawRows.count {
let rawRow = rawRows[counter]
if let subRowsNum = rawRow.components(separatedBy: #"rowspan=\""#).dropFirst().compactMap({ sub in
(sub.range(of: #"\">"#)?.lowerBound).flatMap { endRange in
String(sub[sub.startIndex ..< endRange])
}
}).first {
if let subRowsTot = Int(subRowsNum) {
var otherRows = ""
for i in counter..<counter+subRowsTot {
otherRows += rawRows[i]
}
let row = rawRow + otherRows
rows.append(row)
counter += subRowsTot-1
}
} else {
rows.append(rawRows[counter])
}
counter += 1
}
tables.append(rows)
}
for table in tables {
if let rowIndex = table.firstIndex(where: {$0.lowercased().contains(identifier.lowercased())}) {
let rows = table[rowIndex].components(separatedBy: "<td>")
if rows.count>0 {
if rows[0].contains("title") { //hyperlink
if let (cleanedGen) = rows[0].components(separatedBy: #">"#).dropFirst().compactMap({ sub in
(sub.range(of: "</")?.lowerBound).flatMap { endRange in
String(sub[sub.startIndex ..< endRange]).replacingOccurrences(of: #"\n"#, with: "")
}
}).first {
completion(cleanedGen)
}
} else {
let raw = rows[0].replacingOccurrences(of: "<td>", with: "")
let cleanedGen = raw.replacingOccurrences(of: #"\n"#, with: "")
completion(cleanedGen)
}
return
}
}
}
completion(unrecognized)
}
}.resume()
}
}
用法:
var deviceModel:String = ""
WikiDevice.model { (model) in
print("Using WikiDevice, running on: \(model)")
deviceModel = model
}
输出:
Using WikiDevice, running on: iPhone 11 Pro Max
GitHUB:
如果您需要测试这个库，您可以从这里下载测试项目
