给定一个透明的PNG显示一个简单的形状在白色，它是有可能以某种方式改变这通过CSS的颜色?某种叠加还是什么?
当前回答
I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.
注意:这只适用于HTML5，因为它使用内联SVG。但我认为，通过将SVG放在一个单独的文件中，您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。
Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>
其他回答
我在谷歌上找到了这个，我发现最适合我的工作…
HTML
<div class="img"></div>
CSS
.img {
background-color: red;
width: 60px;
height: 60px;
-webkit-mask-image: url('http://i.stack.imgur.com/gZvK4.png');
}
http://jsfiddle.net/a63b0exm/
body{ background: #333 url(/images/classy_fabric.png); width: 430px; margin: 0 auto; padding: 30px; } .preview{ background: #ccc; width: 415px; height: 430px; border: solid 10px #fff; } input[type='radio'] { -webkit-appearance: none; -moz-appearance: none; width: 25px; height: 25px; margin: 5px 0 5px 5px; background-size: 225px 70px; position: relative; float: left; display: inline; top: 0; border-radius: 3px; z-index: 99999; cursor: pointer; box-shadow: 1px 1px 1px #000; } input[type='radio']:hover{ -webkit-filter: opacity(.4); filter: opacity(.4); } .red{ background: red; } .red:checked{ background: linear-gradient(brown, red) } .green{ background: green; } .green:checked{ background: linear-gradient(green, lime); } .yellow{ background: yellow; } .yellow:checked{ background: linear-gradient(orange, yellow); } .purple{ background: purple; } .pink{ background: pink; } .purple:checked{ background: linear-gradient(purple, violet); } .red:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 red); filter: opacity(.5) drop-shadow(0 0 0 red); } .green:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 green); filter: opacity(.5) drop-shadow(0 0 0 green); } .yellow:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 yellow); filter: opacity(.5) drop-shadow(0 0 0 yellow); } .purple:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 purple); filter: opacity(.5) drop-shadow(0 0 0 purple); } .pink:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 pink); filter: opacity(.5) drop-shadow(0 0 0 pink); } img{ width: 394px; height: 375px; position: relative; } .label{ width: 150px; height: 75px; position: absolute; top: 170px; margin-left: 130px; } ::selection{ background: #000; } <div class="preview"> <input class='red' name='color' type='radio' /> <input class='green' name='color' type='radio' /> <input class='pink' name='color' type='radio' /> <input checked class='yellow' name='color' type='radio' /> <input class='purple' name='color' type='radio' /> <img src="https://i.stack.imgur.com/bd7VJ.png"/> </div>
来源:https://codepen.io/taryaoui/pen/EKkcu
如果你只需要一个图标，就不需要整个字体集，而且我觉得它作为一个单独的元素更“干净”。因此，出于这个目的，在HTML5中可以直接在文档流中放置SVG。然后你可以在你的.CSS样式表中定义一个类，并使用fill属性访问它的背景色:
工作小提琴: http://jsfiddle.net/qmsj0ez1/
请注意，在示例中，我使用:hover来说明行为;如果您只是想更改“正常”状态的颜色，则应该删除伪类。
你可以使用-webkit-filter和filter来使用过滤器: 过滤器对于浏览器来说相对较新，但根据以下CanIUse表:https://caniuse.com/#feat=css-filters，超过90%的浏览器支持过滤器
你可以将图像更改为灰度，深褐色和更多(请看示例)。
所以你现在可以用滤镜改变PNG文件的颜色。
body { background-color:#03030a; min-width: 800px; min-height: 400px } img { width:20%; float:left; margin:0; } /*Filter styles*/ .saturate { filter: saturate(3); } .grayscale { filter: grayscale(100%); } .contrast { filter: contrast(160%); } .brightness { filter: brightness(0.25); } .blur { filter: blur(3px); } .invert { filter: invert(100%); } .sepia { filter: sepia(100%); } .huerotate { filter: hue-rotate(180deg); } .rss.opacity { filter: opacity(50%); } <!--- img src http://upload.wikimedia.org/wikipedia/commons/thumb/e/ec/Mona_Lisa%2C_by_Leonardo_da_Vinci%2C_from_C2RMF_retouched.jpg/500px-Mona_Lisa%2C_by_Leonardo_da_Vinci%2C_from_C2RMF_retouched.jpg --> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="original"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="saturate" class="saturate"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="grayscale" class="grayscale"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="contrast" class="contrast"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="brightness" class="brightness"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="blur" class="blur"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="invert" class="invert"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="sepia" class="sepia"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="huerotate" class="huerotate"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="opacity" class="rss opacity">
源
I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.
注意:这只适用于HTML5，因为它使用内联SVG。但我认为，通过将SVG放在一个单独的文件中，您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。
Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>
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