UIApplication.open(_:options:completionHandler:)只能在主线程中使用

解决方案:

if let appSettings = URL(string: UIApplication.openSettingsURLString + Bundle.main.bundleIdentifier!) {
  if UIApplication.shared.canOpenURL(appSettings) {
    DispatchQueue.main.async {
        UIApplication.shared.open(appSettings)
    }
  }
}

在iOS 10.3上，App-Specific URL Schemes的第一个响应对我来说很有效。

if let appSettings = URL(string: UIApplicationOpenSettingsURLString + Bundle.main.bundleIdentifier!) {
    if UIApplication.shared.canOpenURL(appSettings) {
      UIApplication.shared.open(appSettings)
    }
  }

使用UIApplication.openSettingsURLString

Swift 5.1更新

 override func viewDidAppear(_ animated: Bool) {
    let alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle: .alert)

    let settingsAction = UIAlertAction(title: "Settings", style: .default) { (_) -> Void in

        guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else {
            return
        }

        if UIApplication.shared.canOpenURL(settingsUrl) {
            UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
                print("Settings opened: \(success)") // Prints true
            })
        }
    }
    alertController.addAction(settingsAction)
    let cancelAction = UIAlertAction(title: "Cancel", style: .default, handler: nil)
    alertController.addAction(cancelAction)

    present(alertController, animated: true, completion: nil)
}

斯威夫特4.2

override func viewDidAppear(_ animated: Bool) {
    let alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle: .alert)

    let settingsAction = UIAlertAction(title: "Settings", style: .default) { (_) -> Void in

        guard let settingsUrl = URL(string: UIApplicationOpenSettingsURLString) else {
            return
        }

        if UIApplication.shared.canOpenURL(settingsUrl) {
            UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
                print("Settings opened: \(success)") // Prints true
            })
        }
    }
    alertController.addAction(settingsAction)
    let cancelAction = UIAlertAction(title: "Cancel", style: .default, handler: nil)
    alertController.addAction(cancelAction)

    present(alertController, animated: true, completion: nil)
}

UIApplication.open(_:options:completionHandler:)只能在主线程中使用

解决方案:

if let appSettings = URL(string: UIApplication.openSettingsURLString + Bundle.main.bundleIdentifier!) {
  if UIApplication.shared.canOpenURL(appSettings) {
    DispatchQueue.main.async {
        UIApplication.shared.open(appSettings)
    }
  }
}

斯威夫特5

if let settingsUrl = URL(string: UIApplication.openSettingsURLString) {

   UIApplication.shared.open(settingsUrl)

 }

在iOS 8+中，您可以执行以下操作:

 func buttonClicked(sender:UIButton)
    {
        UIApplication.sharedApplication().openURL(NSURL(string: UIApplicationOpenSettingsURLString))
    }

斯威夫特4

    let settingsUrl = URL(string: UIApplicationOpenSettingsURLString)!
    UIApplication.shared.open(settingsUrl)

App-Prefs:root=Privacy&path=LOCATION为我获得一般位置设置工作。注:仅在设备上有效。