使用官方的java电子邮件包是最简单的:

public static boolean isValidEmailAddress(String email) {
   boolean result = true;
   try {
      InternetAddress emailAddr = new InternetAddress(email);
      emailAddr.validate();
   } catch (AddressException ex) {
      result = false;
   }
   return result;
}

public class Validations {

    private Pattern regexPattern;
    private Matcher regMatcher;

    public String validateEmailAddress(String emailAddress) {

        regexPattern = Pattern.compile("^[(a-zA-Z-0-9-\\_\\+\\.)]+@[(a-z-A-z)]+\\.[(a-zA-z)]{2,3}$");
        regMatcher   = regexPattern.matcher(emailAddress);
        if(regMatcher.matches()) {
            return "Valid Email Address";
        } else {
            return "Invalid Email Address";
        }
    }

    public String validateMobileNumber(String mobileNumber) {
        regexPattern = Pattern.compile("^\\+[0-9]{2,3}+-[0-9]{10}$");
        regMatcher   = regexPattern.matcher(mobileNumber);
        if(regMatcher.matches()) {
            return "Valid Mobile Number";
        } else {
            return "Invalid Mobile Number";
        }
    }

    public static void main(String[] args) {

        String emailAddress = "suryaprakash.pisay@gmail.com";
        String mobileNumber = "+91-9986571622";
        Validations validations = new Validations();
        System.out.println(validations.validateEmailAddress(emailAddress));
        System.out.println(validations.validateMobileNumber(mobileNumber));
    }
}

这是最好的方法:

public static boolean isValidEmail(String enteredEmail){
        String EMAIL_REGIX = "^[\\\\w!#$%&’*+/=?`{|}~^-]+(?:\\\\.[\\\\w!#$%&’*+/=?`{|}~^-]+)*@(?:[a-zA-Z0-9-]+\\\\.)+[a-zA-Z]{2,6}$";
        Pattern pattern = Pattern.compile(EMAIL_REGIX);
        Matcher matcher = pattern.matcher(enteredEmail);
        return ((!enteredEmail.isEmpty()) && (enteredEmail!=null) && (matcher.matches()));
    }

来源: http://howtodoinjava.com/2014/11/11/java-regex-validate-email-address/

http://www.rfc-editor.org/rfc/rfc5322.txt

Apache Commons通常被认为是一个可靠的项目。但是请记住，如果你想确保它是一个真实的电子邮件，并且所有者希望它在你的网站上使用，你仍然需要发送一封验证邮件到这个地址。

编辑:有一个错误，它对域名的限制太大，导致它不接受来自新顶级域名的有效电子邮件。 此错误已于03/Jan/15 02:48在common -validator版本1.4.1中解决

似乎没有任何完美的库或方法可以自己做到这一点，除非您必须有时间向电子邮件地址发送电子邮件并等待回复(尽管这可能不是一个选项)。我最终使用了这里的一个建议http://blog.logichigh.com/2010/09/02/validating-an-e-mail-address/，并调整了代码，使其可以在Java中工作。

public static boolean isValidEmailAddress(String email) {
    boolean stricterFilter = true; 
    String stricterFilterString = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
    String laxString = ".+@.+\\.[A-Za-z]{2}[A-Za-z]*";
    String emailRegex = stricterFilter ? stricterFilterString : laxString;
    java.util.regex.Pattern p = java.util.regex.Pattern.compile(emailRegex);
    java.util.regex.Matcher m = p.matcher(email);
    return m.matches();
}

另一种选择是使用Hibernate电子邮件验证器，使用注释@Email或以编程方式使用验证器类，例如:

import org.hibernate.validator.internal.constraintvalidators.hv.EmailValidator; 

class Validator {
    // code
    private boolean isValidEmail(String email) {
        EmailValidator emailValidator = new EmailValidator();
        return emailValidator.isValid(email, null);
    }

}