根据这个线程中的回答，我创建了涵盖所有情况的清单模型指令:

简单的原语数组 对象数组(选择id或整个对象) 对象属性迭代

对于主题启动案例，它将是:

<label ng-repeat="fruit in ['apple', 'orange', 'pear', 'naartjie']">
    <input type="checkbox" checklist-model="selectedFruits" checklist-value="fruit"> {{fruit}}
</label>

我在控制器中放了一个数组。

$scope.statuses = [{ name: 'Shutdown - Reassessment Required' },
    { name: 'Under Construction' },
    { name: 'Administrative Cancellation' },
    { name: 'Initial' },
    { name: 'Shutdown - Temporary' },
    { name: 'Decommissioned' },
    { name: 'Active' },
    { name: 'SO Shutdown' }]

在标记上，我添加了如下内容

<div ng-repeat="status in $scope.statuses">
   <input type="checkbox" name="unit_status" ng-model="$scope.checkboxes[status.name]"> {{status.name}}
   <br>                        
</div>
{{$scope.checkboxes}}

输出如下，在控制器中，我只需要检查它是真还是假;选中为True，未选中为null /false。

{
"Administrative Cancellation":true,
"Under Construction":true,
"Shutdown - Reassessment Required":true,
"Decommissioned":true,
"Active":true
}

希望这能有所帮助。

我改编了Yoshi接受的答案来处理复杂的对象(而不是字符串)。

HTML

<div ng-controller="TestController">
    <p ng-repeat="permission in allPermissions">
        <input type="checkbox" ng-checked="selectedPermissions.containsObjectWithProperty('id', permission.id)" ng-click="toggleSelection(permission)" />
        {{permission.name}}
    </p>

    <hr />

    <p>allPermissions: | <span ng-repeat="permission in allPermissions">{{permission.name}} | </span></p>
    <p>selectedPermissions: | <span ng-repeat="permission in selectedPermissions">{{permission.name}} | </span></p>
</div>

JavaScript

Array.prototype.indexOfObjectWithProperty = function(propertyName, propertyValue)
{
    for (var i = 0, len = this.length; i < len; i++) {
        if (this[i][propertyName] === propertyValue) return i;
    }

    return -1;
};


Array.prototype.containsObjectWithProperty = function(propertyName, propertyValue)
{
    return this.indexOfObjectWithProperty(propertyName, propertyValue) != -1;
};


function TestController($scope)
{
    $scope.allPermissions = [
    { "id" : 1, "name" : "ROLE_USER" },
    { "id" : 2, "name" : "ROLE_ADMIN" },
    { "id" : 3, "name" : "ROLE_READ" },
    { "id" : 4, "name" : "ROLE_WRITE" } ];

    $scope.selectedPermissions = [
    { "id" : 1, "name" : "ROLE_USER" },
    { "id" : 3, "name" : "ROLE_READ" } ];

    $scope.toggleSelection = function toggleSelection(permission) {
        var index = $scope.selectedPermissions.indexOfObjectWithProperty('id', permission.id);

        if (index > -1) {
            $scope.selectedPermissions.splice(index, 1);
        } else {
            $scope.selectedPermissions.push(permission);
        }
    };
}

工作示例:http://jsfiddle.net/tCU8v/

我认为最简单的解决方法是使用'select'并指定'multiple':

<select ng-model="selectedfruit" multiple ng-options="v for v in fruit"></select>

否则，我认为您将不得不处理该列表来构造该列表 (通过$watch()用复选框绑定模型数组)。

如果在同一个表单上有多个复选框

控制器代码

vm.doYouHaveCheckBox = ['aaa', 'ccc', 'bbb'];
vm.desiredRoutesCheckBox = ['ddd', 'ccc', 'Default'];
vm.doYouHaveCBSelection = [];
vm.desiredRoutesCBSelection = [];

视图代码

<div ng-repeat="doYouHaveOption in vm.doYouHaveCheckBox">
    <div class="action-checkbox">
        <input id="{{doYouHaveOption}}" type="checkbox" value="{{doYouHaveOption}}" ng-checked="vm.doYouHaveCBSelection.indexOf(doYouHaveOption) > -1" ng-click="vm.toggleSelection(doYouHaveOption,vm.doYouHaveCBSelection)" />
        <label for="{{doYouHaveOption}}"></label>
        {{doYouHaveOption}}
    </div>
</div>

<div ng-repeat="desiredRoutesOption in vm.desiredRoutesCheckBox">
     <div class="action-checkbox">
          <input id="{{desiredRoutesOption}}" type="checkbox" value="{{desiredRoutesOption}}" ng-checked="vm.desiredRoutesCBSelection.indexOf(desiredRoutesOption) > -1" ng-click="vm.toggleSelection(desiredRoutesOption,vm.desiredRoutesCBSelection)" />
          <label for="{{desiredRoutesOption}}"></label>
          {{desiredRoutesOption}}
     </div>
</div>        

<input type='checkbox' ng-repeat="fruit in fruits"
  ng-checked="checkedFruits.indexOf(fruit) != -1" ng-click="toggleCheck(fruit)">

.

function SomeCtrl ($scope) {
    $scope.fruits = ["apple, orange, pear, naartjie"];
    $scope.checkedFruits = [];
    $scope.toggleCheck = function (fruit) {
        if ($scope.checkedFruits.indexOf(fruit) === -1) {
            $scope.checkedFruits.push(fruit);
        } else {
            $scope.checkedFruits.splice($scope.checkedFruits.indexOf(fruit), 1);
        }
    };
}