如何使用JavaScript删除当前域的所有cookie ?
当前回答
这里有一个清除所有路径和所有变体域(www.mydomain.example, mydomain。例等):
(function () {
var cookies = document.cookie.split("; ");
for (var c = 0; c < cookies.length; c++) {
var d = window.location.hostname.split(".");
while (d.length > 0) {
var cookieBase = encodeURIComponent(cookies[c].split(";")[0].split("=")[0]) + '=; expires=Thu, 01-Jan-1970 00:00:01 GMT; domain=' + d.join('.') + ' ;path=';
var p = location.pathname.split('/');
document.cookie = cookieBase + '/';
while (p.length > 0) {
document.cookie = cookieBase + p.join('/');
p.pop();
};
d.shift();
}
}
})();
其他回答
函数方法+ ES6
const cookieCleaner = () => {
return document.cookie.split(";").reduce(function (acc, cookie) {
const eqPos = cookie.indexOf("=");
const cleanCookie = `${cookie.substr(0, eqPos)}=;expires=Thu, 01 Jan 1970 00:00:00 GMT;`;
return `${acc}${cleanCookie}`;
}, "");
}
注意:不处理路径
简单。得更快。
function deleteAllCookies() {
var c = document.cookie.split("; ");
for (i in c)
document.cookie =/^[^=]+/.exec(c[i])[0]+"=;expires=Thu, 01 Jan 1970 00:00:00 GMT";
}
如果你只关心清除安全源上的Cookie,你可以使用Cookie Store API和它的.delete()方法。
cookieStore.getAll().then(cookies => cookies.forEach(cookie => {
console.log('Cookie deleted:', cookie);
cookieStore.delete(cookie.name);
}));
访问caniuse.com表,查看Cookie Store API的浏览器支持情况。
我们可以这样做:
deleteAllCookies=()=>
{
let c=document.cookie.split(';')
for(const k of c)
{
let s=k.split('=')
document.cookie=s[0].trim()+'=;expires=Fri, 20 Aug 2021 00:00:00 UTC'
}
}
用法:
deleteAllCookies()
截止日期是这个答案之前的任意一天;它可以是当天之前的任何日期 在JS中,你不能基于路径读取cookie 在JS中,你只能设置或获取cookie
我在这里贡献是因为这个功能将允许您删除所有cookie(匹配路径,默认为no-path或\),也包括设置为包含在子域上的cookie
function clearCookies( wildcardDomain=false, primaryDomain=true, path=null ){
pathSegment = path ? '; path=' + path : ''
expSegment = "=;expires=Thu, 01 Jan 1970 00:00:00 GMT"
document.cookie.split(';').forEach(
function(c) {
primaryDomain && (document.cookie = c.replace(/^ +/, "").replace(/=.*/, expSegment + pathSegment))
wildcardDomain && (document.cookie = c.replace(/^ +/, "").replace(/=.*/, expSegment + pathSegment + '; domain=' + document.domain))
}
)
}