我最喜欢Webjins的答案，所以我扩展了它以显示d后缀的日子，使显示有条件，并包括一个s后缀的普通秒:

function sec2str(t){
    var d = Math.floor(t/86400),
        h = ('0'+Math.floor(t/3600) % 24).slice(-2),
        m = ('0'+Math.floor(t/60)%60).slice(-2),
        s = ('0' + t % 60).slice(-2);
    return (d>0?d+'d ':'')+(h>0?h+':':'')+(m>0?m+':':'')+(t>60?s:s+'s');
}

返回"3d 16:32:12"或"16:32:12"或"32:12"或"12s"

正则表达式可以用来匹配Date对象的toString()方法返回的字符串中的时间子字符串，该字符串的格式如下:“Thu Jul 05 2012 02:45:12 GMT+0100 (GMT夏令时)”。请注意，此解决方案使用自epoch以来的时间:1970年1月1日午夜。这个解决方案可以是一行代码，不过将其拆分会更容易理解。

function secondsToTime(seconds) {
    const start = new Date(1970, 1, 1, 0, 0, 0, 0).getTime();
    const end = new Date(1970, 1, 1, 0, 0, parseInt(seconds), 0).getTime();
    const duration = end - start;

    return new Date(duration).toString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}

主题的变奏。处理个位数秒的方式有点不同

seconds2time(0)  ->  "0s" 
seconds2time(59) -> "59s" 
seconds2time(60) -> "1:00" 
seconds2time(1000) -> "16:40" 
seconds2time(4000) -> "1:06:40"

function seconds2time (seconds) {
    var hours   = Math.floor(seconds / 3600);
    var minutes = Math.floor((seconds - (hours * 3600)) / 60);
    var seconds = seconds - (hours * 3600) - (minutes * 60);
    var time = "";

    if (hours != 0) {
      time = hours+":";
    }
    if (minutes != 0 || time !== "") {
      minutes = (minutes < 10 && time !== "") ? "0"+minutes : String(minutes);
      time += minutes+":";
    }
    if (time === "") {
      time = seconds+"s";
    }
    else {
      time += (seconds < 10) ? "0"+seconds : String(seconds);
    }
    return time;
}

最普遍的答案是

function hms(seconds) {
  return [3600, 60]
    .reduceRight(
      (p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
      r => [r]
    )(seconds)
    .map(a => a.toString().padStart(2, '0'))
    .join(':');
}

一些示例输出:

> hms(0)
< "00:00:00"

> hms(5)
< "00:00:05"

> hms(60)
< "00:01:00"

> hms(3785)
< "01:03:05"

> hms(37850)
< "10:30:50"

> hms(378500)
< "105:08:20"

详见https://stackoverflow.com/a/66504936/1310733

/**
 * Formats seconds (number) to H:i:s format.
 * 00:12:00
 *
 * When "short" option is set to true, will return:
 * 0:50
 * 2:00
 * 12:00
 * 1:00:24
 * 10:00:00
 */
export default function formatTimeHIS (seconds, { short = false } = {}) {
  const pad = num => num < 10 ? `0${num}` : num

  const H = pad(Math.floor(seconds / 3600))
  const i = pad(Math.floor(seconds % 3600 / 60))
  const s = pad(seconds % 60)

  if (short) {
    let result = ''
    if (H > 0) result += `${+H}:`
    result += `${H > 0 ? i : +i}:${s}`
    return result
  } else {
    return `${H}:${i}:${s}`
  }
}

我不喜欢在JavaScript中为标准数据类型添加属性，所以我建议这样做:

/**
 * Format a duration in seconds to a human readable format using the notion
 * "h+:mm:ss", e.g. "4:40:78". Negative durations are preceeded by "-".
 *
 * @param t Duration in seconds
 * @return The formatted duration string
 */
var readableDuration = (function() {

    // Each unit is an object with a suffix s and divisor d
    var units = [
        {s: '', d: 1}, // Seconds
        {s: ':', d: 60}, // Minutes
        {s: ':', d: 60}, // Hours
    ];

    // Closure function
    return function(t) {
        t = parseInt(t); // In order to use modulus
        var trunc, n = Math.abs(t), i, out = []; // out: list of strings to concat
        for (i = 0; i < units.length; i++) {
            n = Math.floor(n / units[i].d); // Total number of this unit
            // Truncate e.g. 26h to 2h using modulus with next unit divisor
            if (i+1 < units.length) // Tweak substr with two digits
                trunc = ('00'+ n % units[i+1].d).substr(-2, 2); // …if not final unit
            else
                trunc = n;
            out.unshift(''+ trunc + units[i].s); // Output
        }
        (t < 0) ? out.unshift('-') : null; // Handle negative durations
        return out.join('');
    };
})();

用法:

var str = readableDuration(3808); // "1:03:28"

我还创建了一个更通用的版本。主要的区别是它接受毫秒(这是JS中的标准时间单位)，而输出格式使用空格。