我想转换时间的持续时间,即秒数,以冒号分隔的时间字符串(hh:mm:ss)

我在这里找到了一些有用的答案,但它们都谈到了转换成x小时和x分钟的格式。

那么有一个小片段,这是在jQuery或只是原始JavaScript?


当前回答

毫秒到持续时间,简单的方法是:

// To have leading zero digits in strings.
function pad(num, size) {
    var s = num + "";
    while (s.length < size) s = "0" + s;
    return s;
}

// ms to time/duration
msToDuration = function(ms){
    var seconds = ms / 1000;
    var hh = Math.floor(seconds / 3600),
    mm = Math.floor(seconds / 60) % 60,
    ss = Math.floor(seconds) % 60,
    mss = ms % 1000;
    return pad(hh,2)+':'+pad(mm,2)+':'+pad(ss,2)+'.'+pad(mss,3);
}

它将327577转换为00:05:27.577。

更新

另一种不同场景的方法:

toHHMMSS = function (n) {
    var sep = ':',
        n = parseFloat(n),
        sss = parseInt((n % 1)*1000),
        hh = parseInt(n / 3600);
    n %= 3600;
    var mm = parseInt(n / 60),
        ss = parseInt(n % 60);
    return pad(hh,2)+sep+pad(mm,2)+sep+pad(ss,2)+'.'+pad(sss,3);
    function pad(num, size) {
        var str = num + "";
        while (str.length < size) str = "0" + str;
        return str;
    }
}

toHHMMSS(6315.077) // Return 01:45:15.077

其他回答

这是我最近为MM:SS写的。它不完全符合问题,但它是一种不同的单行格式。

const time = 60 * 2 + 35; // 2 minutes, 35 seconds
const str = (~~(time / 60) + "").padStart(2, '0') + ":" + (~~((time / 60) % 1 * 60) + "").padStart(2, '0');

str // 02:35

编辑:添加这个是为了多样化,但这里最好的解决方案是下面的https://stackoverflow.com/a/25279399/639679。

s2t=function (t){
  return parseInt(t/86400)+'d '+(new Date(t%86400*1000)).toUTCString().replace(/.*(\d{2}):(\d{2}):(\d{2}).*/, "$1h $2m $3s");
}

s2t(123456);

结果:

1d 10h 17m 36s

const secondsToTime = (seconds, locale) => { const date = new date (0); 日期。setHours(0, 0, seconds, 0); 返回date.toLocaleTimeString(地区); } “en”console.log (secondsToTime (3610));

在哪里区域参数(“en”,“de”等)是可选的

我推荐使用普通的javascript,使用Date对象。(要获得更简短的解决方案,请使用toTimeString,请参阅第二个代码片段。)

var seconds = 9999;
// multiply by 1000 because Date() requires miliseconds
var date = new Date(seconds * 1000);
var hh = date.getUTCHours();
var mm = date.getUTCMinutes();
var ss = date.getSeconds();
// If you were building a timestamp instead of a duration, you would uncomment the following line to get 12-hour (not 24) time
// if (hh > 12) {hh = hh % 12;}
// These lines ensure you have two-digits
if (hh < 10) {hh = "0"+hh;}
if (mm < 10) {mm = "0"+mm;}
if (ss < 10) {ss = "0"+ss;}
// This formats your string to HH:MM:SS
var t = hh+":"+mm+":"+ss;
document.write(t);

(当然,创建的Date对象将有一个与之关联的实际日期,但该数据是无关的,因此出于这些目的,您不必担心它。)


编辑(简短的解决方案):

使用toTimeString函数并对空白进行分割:

var seconds = 9999; // Some arbitrary value
var date = new Date(seconds * 1000); // multiply by 1000 because Date() requires miliseconds
var timeStr = date.toTimeString().split(' ')[0];

toTimeString给出'16:54:58 GMT-0800 (PST)',对第一个空格进行分割给出'16:54:58'。

主题的变奏。处理个位数秒的方式有点不同

seconds2time(0)  ->  "0s" 
seconds2time(59) -> "59s" 
seconds2time(60) -> "1:00" 
seconds2time(1000) -> "16:40" 
seconds2time(4000) -> "1:06:40"

function seconds2time (seconds) {
    var hours   = Math.floor(seconds / 3600);
    var minutes = Math.floor((seconds - (hours * 3600)) / 60);
    var seconds = seconds - (hours * 3600) - (minutes * 60);
    var time = "";

    if (hours != 0) {
      time = hours+":";
    }
    if (minutes != 0 || time !== "") {
      minutes = (minutes < 10 && time !== "") ? "0"+minutes : String(minutes);
      time += minutes+":";
    }
    if (time === "") {
      time = seconds+"s";
    }
    else {
      time += (seconds < 10) ? "0"+seconds : String(seconds);
    }
    return time;
}