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2024-02-03 08:00:02

使用Newtonsoft反序列化JSON到.NET对象(或LINQ到JSON ?)

我知道有一些关于Newtonsoft的帖子，所以希望这不是一次重复……我试图将Kazaa的API返回的JSON数据转换为某种类型的漂亮对象

WebClient client = new WebClient();
Stream stream = client.OpenRead("http://api.kazaa.com/api/v1/search.json?q=muse&type=Album");
StreamReader reader = new StreamReader(stream);

List<string> list = Newtonsoft.Json.JsonConvert.DeserializeObject<List<string>>(reader.Read().ToString());

foreach (string item in list)
{
    Console.WriteLine(item);
}

//Console.WriteLine(reader.ReadLine());
stream.Close();

那JsonConvert行只是最近一个我正在尝试…我不太明白，希望通过问你们来消除一些步法。我本来是想把它转换成字典什么的……实际上，我只需要在那里抓住几个值，所以根据文档判断，也许Newtonsoft的LINQ到JSON可能是一个更好的选择?想法/链接?

下面是JSON返回数据的示例:

{
  "page": 1,
  "total_pages": 8,
  "total_entries": 74,
  "q": "muse",
  "albums": [
    {
      "name": "Muse",
      "permalink": "Muse",
      "cover_image_url": "http://image.kazaa.com/images/69/01672812 1569/Yaron_Herman_Trio/Muse/Yaron_Herman_Trio-Muse_1.jpg",
      "id": 93098,
      "artist_name": "Yaron Herman Trio"
    },
    {
      "name": "Muse",
      "permalink": "Muse",
      "cover_image_url": "htt p://image.kazaa.com/images/54/888880301154/Candy_Lo/Muse/Candy_Lo-Muse_1.jpg",
      "i d": 102702,
      "artist_name": "\u76e7\u5de7\u97f3"
    },
    {
      "name": "Absolution",
      "permalink": " Absolution",
      "cover_image_url": "http://image.kazaa.com/images/65/093624873365/Mus e/Absolution/Muse-Absolution_1.jpg",
      "id": 48896,
      "artist_name": "Muse"
    },
    {
      "name": "Ab solution",
      "permalink": "Absolution-2",
      "cover_image_url": "http://image.kazaa.com/i mages/20/825646911820/Muse/Absolution/Muse-Absolution_1.jpg",
      "id": 118573,
      "artist _name": "Muse"
    },
    {
      "name": "Black Holes And Revelations",
      "permalink": "Black-Holes-An d-Revelations",
      "cover_image_url": "http://image.kazaa.com/images/66/093624428466/ Muse/Black_Holes_And_Revelations/Muse-Black_Holes_And_Revelations_1.jpg",
      "id": 48813,
      "artist_name": "Muse"
    },
    {
      "name": "Black Holes And Revelations",
      "permalink": "Bla ck-Holes-And-Revelations-2",
      "cover_image_url": "http://image.kazaa.com/images/86/ 825646911486/Muse/Black_Holes_And_Revelations/Muse-Black_Holes_And_Revelations_1 .jpg",
      "id": 118543,
      "artist_name": "Muse"
    },
    {
      "name": "Origin Of Symmetry",
      "permalink": "Origin-Of-Symmetry",
      "cover_image_url": "http://image.kazaa.com/images/29/825646 912629/Muse/Origin_Of_Symmetry/Muse-Origin_Of_Symmetry_1.jpg",
      "id": 120491,
      "artis t_name": "Muse"
    },
    {
      "name": "Showbiz",
      "permalink": "Showbiz",
      "cover_image_url": "http: //image.kazaa.com/images/68/825646182268/Muse/Showbiz/Muse-Showbiz_1.jpg",
      "id": 60444,
      "artist_name": "Muse"
    },
    {
      "name": "Showbiz",
      "permalink": "Showbiz-2",
      "cover_imag e_url": "http://image.kazaa.com/images/50/825646912650/Muse/Showbiz/Muse-Showbiz_ 1.jpg",
      "id": 118545,
      "artist_name": "Muse"
    },
    {
      "name": "The Resistance",
      "permalink": "T he-Resistance",
      "cover_image_url": "http://image.kazaa.com/images/36/825646864836/ Muse/The_Resistance/Muse-The_Resistance_1.jpg",
      "id": 121171,
      "artist_name": "Muse"
    }
  ],
  "per_page": 10
}

我做了更多的阅读，发现Newtonsoft的LINQ到JSON正是我想要的…使用WebClient，流，StreamReader，和Newtonsoft…我可以点击Kazaa获取JSON数据，提取URL，下载文件，这一切都在七行代码中完成!我很喜欢。

WebClient client = new WebClient();
Stream stream = client.OpenRead("http://api.kazaa.com/api/v1/search.json?q=muse&type=Album");
StreamReader reader = new StreamReader(stream);

Newtonsoft.Json.Linq.JObject jObject = Newtonsoft.Json.Linq.JObject.Parse(reader.ReadLine());

// Instead of WriteLine, 2 or 3 lines of code here using WebClient to download the file
Console.WriteLine((string)jObject["albums"][0]["cover_image_url"]);
stream.Close();

这篇文章点击率很高，我认为在评论中加入“使用”的部分可能会有所帮助。

using(var client = new WebClient())
using(var stream = client.OpenRead("http://api.kazaa.com/api/v1/search.json?q=muse&type=Album"))
using (var reader = new StreamReader(stream))
{
    var jObject = Newtonsoft.Json.Linq.JObject.Parse(reader.ReadLine());
    Console.WriteLine((string) jObject["albums"][0]["cover_image_url"]);
}

当前回答

最后从JSON中获取州名

谢谢!

Imports System
Imports System.Text
Imports System.IO
Imports System.Net
Imports Newtonsoft.Json
Imports Newtonsoft.Json.Linq
Imports System.collections.generic

Public Module Module1
    Public Sub Main()

         Dim url As String = "http://maps.google.com/maps/api/geocode/json&address=attur+salem&sensor=false"
            Dim request As WebRequest = WebRequest.Create(url)
        dim response As WebResponse = DirectCast(request.GetResponse(), HttpWebResponse)
        dim reader As New StreamReader(response.GetResponseStream(), Encoding.UTF8)
          Dim dataString As String = reader.ReadToEnd()

        Dim getResponse As JObject = JObject.Parse(dataString)

        Dim dictObj As Dictionary(Of String, Object) = getResponse.ToObject(Of Dictionary(Of String, Object))()
        'Get State Name
        Console.WriteLine(CStr(dictObj("results")(0)("address_components")(2)("long_name")))
    End Sub
End Module
2018-06-03 07:59:44

其他回答

最后从JSON中获取州名

谢谢!

Imports System
Imports System.Text
Imports System.IO
Imports System.Net
Imports Newtonsoft.Json
Imports Newtonsoft.Json.Linq
Imports System.collections.generic

Public Module Module1
    Public Sub Main()

         Dim url As String = "http://maps.google.com/maps/api/geocode/json&address=attur+salem&sensor=false"
            Dim request As WebRequest = WebRequest.Create(url)
        dim response As WebResponse = DirectCast(request.GetResponse(), HttpWebResponse)
        dim reader As New StreamReader(response.GetResponseStream(), Encoding.UTF8)
          Dim dataString As String = reader.ReadToEnd()

        Dim getResponse As JObject = JObject.Parse(dataString)

        Dim dictObj As Dictionary(Of String, Object) = getResponse.ToObject(Of Dictionary(Of String, Object))()
        'Get State Name
        Console.WriteLine(CStr(dictObj("results")(0)("address_components")(2)("long_name")))
    End Sub
End Module
2018-06-03 07:59:44

如果你只需要从JSON对象中获取一些项，我会使用JSON。NET的LINQ到JSON的JObject类。例如:

JToken token = JObject.Parse(stringFullOfJson);

int page = (int)token.SelectToken("page");
int totalPages = (int)token.SelectToken("total_pages");

我喜欢这种方法，因为您不需要完全反序列化JSON对象。这对于那些有时会因为缺少对象属性而让您感到惊讶的api(如Twitter)来说非常方便。

文档:使用JSON序列化和反序列化JSON。NET和LINQ转换成JSON。网

2011-01-20 16:29:28

使用JsonConvert.DeserializeObject()函数进行反序列化

public class ApiValues
    {
        [JsonProperty("Address")]
        public string Address { get; set; }

        [JsonProperty("BaseUrl")]
        public string BaseUrl{ get; set; }
    }

var json = 
{ 
    "Address":"some-address",
    "BaseUrl":"some-url-value"
}


var values = JsonConvert.DeserializeObject<ApiValues>(json);
2020-07-31 19:48:05

如果我说错了，请纠正我，但我认为前面的例子与James Newton的Json的最新版本略有不同步。网络图书馆。

var o = JObject.Parse(stringFullOfJson);
var page = (int)o["page"];
var totalPages = (int)o["total_pages"];
2011-01-20 17:54:54

您可以使用c#动态类型来简化工作。这种技术也使得重构更简单，因为它不依赖于魔法字符串。

JSON

下面的JSON字符串是来自HTTP API调用的简单响应，它定义了两个属性:Id和Name。

{"Id": 1, "Name": "biofractal"}

C#

使用JsonConvert.DeserializeObject<dynamic>()将该字符串反序列化为动态类型，然后按常规方式访问其属性。

dynamic results = JsonConvert.DeserializeObject<dynamic>(json);
var id = results.Id;
var name= results.Name;

如果你指定结果变量的类型为动态，而不是使用var关键字，那么属性值将正确地反序列化，例如Id为int而不是JValue(感谢GFoley83下面的注释)。

注意:Newtonsoft程序集的NuGet链接是http://nuget.org/packages/newtonsoft.json。

包:你也可以添加nuget live安装包，当你的项目打开时，只需要浏览包，然后安装它，卸载，更新，它会被添加到你的项目的依赖项/ nuget下

2012-05-23 10:30:29

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