我如何通过iPhone键盘上的“下一步”按钮浏览所有的文本字段?
最后一个文本字段应该关闭键盘。
我已经设置了IB按钮(下一步/完成),但现在我卡住了。
我实现了textFieldShouldReturn动作,但现在下一步和完成按钮关闭键盘。
我如何通过iPhone键盘上的“下一步”按钮浏览所有的文本字段?
最后一个文本字段应该关闭键盘。
我已经设置了IB按钮(下一步/完成),但现在我卡住了。
我实现了textFieldShouldReturn动作,但现在下一步和完成按钮关闭键盘。
当前回答
我更喜欢:
@interface MyViewController : UIViewController
@property (nonatomic, retain) IBOutletCollection(UIView) NSArray *inputFields;
@end
在NIB文件中,我以所需的顺序将textFields钩子到这个inputFields数组中。之后,我做了一个简单的UITextField的索引测试,报告用户点击返回:
// for UITextField
-(BOOL)textFieldShouldReturn:(UITextField*)textField {
NSUInteger index = [_inputFields indexOfObject:textField];
index++;
if (index < _inputFields.count) {
UIView *v = [_inputFields objectAtIndex:index];
[v becomeFirstResponder];
}
return NO;
}
// for UITextView
-(BOOL)textView:(UITextView*)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString*)text {
if ([@"\n" isEqualToString:text]) {
NSUInteger index = [_inputFields indexOfObject:textView];
index++;
if (index < _inputFields.count) {
UIView *v = [_inputFields objectAtIndex:index];
[v becomeFirstResponder];
} else {
[self.view endEditing:YES];
}
return NO;
}
return YES;
}
其他回答
下面是一个swift3版本的Anth0的答案。我把它贴在这里,以帮助任何想要利用他的伟大答案的敏捷开发人员!当您设置关联对象时,我擅自添加了一个返回键类型“Next”。
extension UITextField {
@nonobjc static var NextHashKey: UniChar = 0
var nextTextField: UITextField? {
get {
return objc_getAssociatedObject(self,
&UITextField.NextHashKey) as? UITextField
}
set(next) {
self.returnKeyType = UIReturnKeyType.next
objc_setAssociatedObject(self,
&UITextField.NextHashKey,next,.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
}
}
}
下面是另一个扩展,它显示了使用上述代码循环遍历UITextFields列表的可能性。
extension UIViewController: UITextFieldDelegate {
public func textFieldShouldReturn(_ textField: UITextField) -> Bool {
guard let next = textField.nextTextField else {
textField.resignFirstResponder()
return true
}
next.becomeFirstResponder()
return false
}
}
然后在你的ViewController或者其他地方,你可以像这样设置你的文本框。
@IBOutlet fileprivate weak var textfield1: UITextField!
@IBOutlet fileprivate weak var textfield2: UITextField!
@IBOutlet fileprivate weak var textfield3: UITextField!
...
[textfield1, textfield2, textfield3].forEach{ $0?.delegate = self }
textfield1.nextTextField = textfield2
textfield2.nextTextField = textfield3
// We don't assign a nextTextField to textfield3 because we want
// textfield3 to be the last one and resignFirstResponder when
// the return button on the soft keyboard is tapped.
这对我在Xamarin很有效。iOS / Monotouch。 将键盘按钮更改为Next,将控件传递给下一个UITextField,并将键盘隐藏在最后一个UITextField之后。
private void SetShouldReturnDelegates(IEnumerable<UIView> subViewsToScout )
{
foreach (var item in subViewsToScout.Where(item => item.GetType() == typeof (UITextField)))
{
(item as UITextField).ReturnKeyType = UIReturnKeyType.Next;
(item as UITextField).ShouldReturn += (textField) =>
{
nint nextTag = textField.Tag + 1;
var nextResponder = textField.Superview.ViewWithTag(nextTag);
if (null != nextResponder)
nextResponder.BecomeFirstResponder();
else
textField.Superview.EndEditing(true);
//You could also use textField.ResignFirstResponder();
return false; // We do not want UITextField to insert line-breaks.
};
}
}
在ViewDidLoad里面你会有:
如果你的TextFields没有标签设置它现在:
txtField1.Tag = 0;
txtField2.Tag = 1;
txtField3.Tag = 2;
//...
只是一个电话
SetShouldReturnDelegates(yourViewWithTxtFields.Subviews.ToList());
//If you are not sure of which view contains your fields you can also call it in a safer way:
SetShouldReturnDelegates(txtField1.Superview.Subviews.ToList());
//You can also reuse the same method with different containerViews in case your UITextField are under different views.
我已经添加到PeyloW的答案,以防你想实现一个previous/next按钮功能:
- (IBAction)moveThroughTextFields:(UIBarButtonItem *)sender
{
NSInteger nextTag;
UITextView *currentTextField = [self.view findFirstResponderAndReturn];
if (currentTextField != nil) {
// I assigned tags to the buttons. 0 represent prev & 1 represents next
if (sender.tag == 0) {
nextTag = currentTextField.tag - 1;
} else if (sender.tag == 1) {
nextTag = currentTextField.tag + 1;
}
}
// Try to find next responder
UIResponder* nextResponder = [self.view viewWithTag:nextTag];
if (nextResponder) {
// Found next responder, so set it.
// I added the resign here in case there's different keyboards in place.
[currentTextField resignFirstResponder];
[nextResponder becomeFirstResponder];
} else {
// Not found, so remove keyboard.
[currentTextField resignFirstResponder];
}
}
你像这样子类化UIView:
@implementation UIView (FindAndReturnFirstResponder)
- (UITextView *)findFirstResponderAndReturn
{
for (UITextView *subView in self.subviews) {
if (subView.isFirstResponder){
return subView;
}
}
return nil;
}
@end
Swift 4 for mxcl答案:
txtFirstname.addTarget(txtLastname, action:
#selector(becomeFirstResponder), for: UIControlEvents.editingDidEndOnExit)
Swift 3解决方案,使用UITextField的有序数组
func nextTextField() {
let textFields = // Your textfields array
for i in 0 ..< textFields.count{
if let textfield = textFields[i], textfield.isFirstResponder{
textfield.resignFirstResponder()
if i+1 < textFields.count, let nextextfield = textFields[i+1]{
nextextfield.becomeFirstResponder()
return
}
}
}
}