下面的代码在第2行接收到seg错误:

char *str = "string";
str[0] = 'z';  // could be also written as *str = 'z'
printf("%s\n", str);

虽然这个方法非常有效:

char str[] = "string";
str[0] = 'z';
printf("%s\n", str);

用MSVC和GCC测试。