经过大量的试验和错误,我放弃了,并提出了这个问题。我见过很多人有类似的问题,但不能得到所有的答案工作正确。

我有一个由自定义单元格组成的UITableView。单元格由相邻的5个文本字段组成(有点像网格)。

当我试图滚动和编辑UITableView底部的单元格时,我不能设法让我的单元格正确地定位在键盘上方。

我看到过很多关于改变视图大小的回答……但到目前为止,没有一种效果很好。

谁能用一个具体的代码示例来阐明这样做的“正确”方式?


当前回答

这非常有效,在iPad上也是如此。

- (BOOL)textFieldShouldReturn:(UITextField *)textField 
{

    if(textField == textfield1){
            [accountName1TextField becomeFirstResponder];
        }else if(textField == textfield2){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:0 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield3 becomeFirstResponder];

        }else if(textField == textfield3){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:1 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield4 becomeFirstResponder];

        }else if(textField == textfield4){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:2 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield5 becomeFirstResponder];

        }else if(textField == textfield5){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:3 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield6 becomeFirstResponder];

        }else if(textField == textfield6){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:4 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield7 becomeFirstResponder];

        }else if(textField == textfield7){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:5 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield8 becomeFirstResponder];

        }else if(textField == textfield8){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:6 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textfield9 becomeFirstResponder];

        }else if(textField == textfield9){
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:7 inSection:1] atScrollPosition:UITableViewScrollPositionTop animated:YES];
            [textField resignFirstResponder];
        }

其他回答

如果你使用UITableViewController而不是UIViewController,它会自动这样做。

这个解决方案为我工作,请注意这一行

[tableView setContentOffset:CGPointMake(0.0, activeField.frame.origin.y-kbSize.height+160) animated:YES];

您可以更改160值以使其与您的工作相匹配

- (void)keyboardWasShown:(NSNotification*)aNotification
{
    NSDictionary* info = [aNotification userInfo];
    CGSize kbSize = [[info objectForKey:UIKeyboardFrameBeginUserInfoKey] CGRectValue].size;
    CGRect bkgndRect = activeField.superview.frame;
                        bkgndRect.size.height += kbSize.height;
     [activeField.superview setFrame:bkgndRect];
     [tableView setContentOffset:CGPointMake(0.0, activeField.frame.origin.y-kbSize.height+160) animated:YES];
}

- (void)textFieldDidBeginEditing:(UITextField *)textField
{
   activeField = textField;
}
-(void)textFieldDidEndEditing:(UITextField *)textField
 {
     activeField = nil;
 }
// Called when the UIKeyboardWillHideNotification is sent
- (void)keyboardWillBeHidden:(NSNotification*)aNotification
{
    UIEdgeInsets contentInsets = UIEdgeInsetsZero;
    tableView.contentInset = contentInsets;
    tableView.scrollIndicatorInsets = contentInsets;
    NSDictionary* info = [aNotification userInfo];
    CGSize kbSize = [[info objectForKey:UIKeyboardFrameBeginUserInfoKey] CGRectValue].size;
    CGRect bkgndRect = activeField.superview.frame;
    //bkgndRect.size.height += kbSize.height;
    [activeField.superview setFrame:bkgndRect];
    [tableView setContentOffset:CGPointMake(0.0, activeField.frame.origin.y-kbSize.height) animated:YES];
}

我刚刚解决了这样一个问题,我参考了大量的解决方案通过谷歌和堆栈溢出。

首先,请确保你已经为UIScrollView设置了IBOutlet, 那么请仔细看看Apple Doc: Keyboard Management。 最后,如果你可以滚动背景,但键盘仍然覆盖文本字段,请看看这段代码:

// If active text field is hidden by keyboard, scroll it so it's visible
// Your application might not need or want this behavior.
CGRect aRect = self.view.frame;
aRect.size.height -= kbSize.height;

if (aRect.size.height < activeField.frame.origin.y+activeField.frame.size.height) {

    CGPoint scrollPoint = CGPointMake(0.0, activeField.frame.origin.y+activeField.frame.size.height-aRect.size.height);

    [scrollView setContentOffset:scrollPoint animated:YES];

这款游戏与苹果游戏的主要区别在于if条件。我认为apple计算滚动距离和键盘是否覆盖文本字段的条件不准确,所以我做了如上修改。

如果有用请告诉我

Swift最简单的解决方案:

override func viewDidLoad() {
    super.viewDidLoad()
    
    searchBar?.becomeFirstResponder()
    NSNotificationCenter.defaultCenter().addObserver(self, selector: #selector(MyViewController.keyboardWillShow(_:)), name: UIKeyboardDidShowNotification, object: nil)
    NSNotificationCenter.defaultCenter().addObserver(self, selector: #selector(MyViewController.keyboardWillHide(_:)), name: UIKeyboardDidHideNotification, object: nil)
}

deinit {
    NSNotificationCenter.defaultCenter().removeObserver(self)
}

func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
        if let keyboardHeight = userInfo[UIKeyboardFrameEndUserInfoKey]?.CGRectValue.size.height {
            tableView.contentInset = UIEdgeInsetsMake(0, 0, keyboardHeight, 0)
        }
    }
}

func keyboardWillHide(notification: NSNotification) {
    UIView.animateWithDuration(0.2, animations: { self.table_create_issue.contentInset = UIEdgeInsetsMake(0, 0, 0, 0) })
    // For some reason adding inset in keyboardWillShow is animated by itself but removing is not, that's why we have to use animateWithDuration here
    }

Swift 4.2或更高版本

override func viewDidLoad() {
    super.viewDidLoad()
    searchBar?.becomeFirstResponder()
    NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillShow), name: UIResponder.keyboardDidShowNotification, object: nil)
    NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillHide), name: UIResponder.keyboardDidHideNotification, object: nil)
}

deinit {
    NotificationCenter.default.removeObserver(self)
}

 @objc func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
            let keyboardHeight = (userInfo[UIResponder.keyboardFrameEndUserInfoKey] as AnyObject).cgRectValue.size.height
            accountSettingsTableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: keyboardHeight, right: 0)
        
    }
}
@objc func keyboardWillHide(notification: NSNotification) {
    UIView.animate(withDuration: 0.2, animations: { self.accountSettingsTableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: 0, right: 0) })}
}

因为你在一个表格中有文本字段,最好的方法是调整表格的大小——你需要设置tableView.frame的高度比键盘的大小小(我认为大约165像素),然后当键盘被关闭时再次展开它。

如果你不想让用户滚动,你也可以选择在那个时候禁用tableView的用户交互。