我知道如何通过编程来做到这一点,但我相信有一种内置的方式……
我使用过的每种语言都有某种对象集合的默认文本表示,当您试图将Array与字符串连接起来或将其传递给print()函数等时,它会吐出这些文本表示。苹果的Swift语言是否有一种内置的方式,可以轻松地将数组转换为字符串,或者我们总是必须显式地对数组进行字符串化?
我知道如何通过编程来做到这一点,但我相信有一种内置的方式……
我使用过的每种语言都有某种对象集合的默认文本表示,当您试图将Array与字符串连接起来或将其传递给print()函数等时,它会吐出这些文本表示。苹果的Swift语言是否有一种内置的方式,可以轻松地将数组转换为字符串,或者我们总是必须显式地对数组进行字符串化?
当前回答
如果你的问题是这样的: tobeFormattedString = ["a", "b", "c"] 输出= "abc"
String(tobeFormattedString)
其他回答
试试这个:
let categories = dictData?.value(forKeyPath: "listing_subcategories_id") as! NSMutableArray
let tempArray = NSMutableArray()
for dc in categories
{
let dictD = dc as? NSMutableDictionary
tempArray.add(dictD?.object(forKey: "subcategories_name") as! String)
}
let joinedString = tempArray.componentsJoined(by: ",")
当您想要将结构类型的列表转换为字符串时,请使用此方法
struct MyStruct {
var name : String
var content : String
}
let myStructList = [MyStruct(name: "name1" , content: "content1") , MyStruct(name: "name2" , content: "content2")]
然后像这样隐藏你的数组
let myString = myStructList.map({$0.name}).joined(separator: ",")
将产生===> "name1,name2"
为数组创建扩展:
extension Array {
var string: String? {
do {
let data = try JSONSerialization.data(withJSONObject: self, options: [.prettyPrinted])
return String(data: data, encoding: .utf8)
} catch {
return nil
}
}
}
对于swift 3:
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
if textField == phoneField
{
let newString = NSString(string: textField.text!).replacingCharacters(in: range, with: string)
let components = newString.components(separatedBy: NSCharacterSet.decimalDigits.inverted)
let decimalString = NSString(string: components.joined(separator: ""))
let length = decimalString.length
let hasLeadingOne = length > 0 && decimalString.character(at: 0) == (1 as unichar)
if length == 0 || (length > 10 && !hasLeadingOne) || length > 11
{
let newLength = NSString(string: textField.text!).length + (string as NSString).length - range.length as Int
return (newLength > 10) ? false : true
}
var index = 0 as Int
let formattedString = NSMutableString()
if hasLeadingOne
{
formattedString.append("1 ")
index += 1
}
if (length - index) > 3
{
let areaCode = decimalString.substring(with: NSMakeRange(index, 3))
formattedString.appendFormat("(%@)", areaCode)
index += 3
}
if length - index > 3
{
let prefix = decimalString.substring(with: NSMakeRange(index, 3))
formattedString.appendFormat("%@-", prefix)
index += 3
}
let remainder = decimalString.substring(from: index)
formattedString.append(remainder)
textField.text = formattedString as String
return false
}
else
{
return true
}
}
在Swift 4中
let array:[String] = ["Apple", "Pear ","Orange"]
array.joined(separator: " ")