我有一个JavaScript数组,如:
[["$6"], ["$12"], ["$25"], ["$25"], ["$18"], ["$22"], ["$10"]]
如何将单独的内部数组合并为一个,例如:
["$6", "$12", "$25", ...]
我有一个JavaScript数组,如:
[["$6"], ["$12"], ["$25"], ["$25"], ["$18"], ["$22"], ["$10"]]
如何将单独的内部数组合并为一个,例如:
["$6", "$12", "$25", ...]
当前回答
/**
* flatten an array first level
* @method flatten
* @param array {Array}
* @return {Array} flatten array
*/
function flatten(array) {
return array.reduce((acc, current) => acc.concat(current), []);
}
/**
* flatten an array recursively
* @method flattenDeep
* @param array {Array}
* @return {Array} flatten array
*/
function flattenDeep(array) {
return array.reduce((acc, current) => {
return Array.isArray(current) ? acc.concat(flattenDeep(current)) : acc.concat([current]);
}, []);
}
/**
* flatten an array recursively limited by depth
* @method flattenDepth
* @param array {Array}
* @return {Array} flatten array
*/
function flattenDepth(array, depth) {
if (depth === 0) {
return array;
}
return array.reduce((acc, current) => {
return Array.isArray(current) ? acc.concat(flattenDepth(current, --depth)) : acc.concat([current]);
}, []);
}
其他回答
如果你使用lodash,你可以使用它的flatten方法:https://lodash.com/docs/4.17.14#flatten
lodash的优点是它还具有使数组变平的方法:
i) 递归地:https://lodash.com/docs/4.17.14#flattenDeep
ii)多达n层嵌套:https://lodash.com/docs/4.17.14#flattenDepth
例如
const _ = require("lodash");
const pancake = _.flatten(array)
简单并处理多个嵌套级别:
// deeply nested array
const myArray = [1, 2, [3, 4, [5, 6, [[[7,8, [[[[[9, 10]]]]]]]]]]] ;
const flatten = (arr) => {
for (let index = 0; index < arr.length; index++) {
const elem = arr[index];
if (Array.isArray(elem)) {
arr.splice(index, 1, ...elem);
index--;
}
}
};
flatten(myArray);
console.log(myArray); // [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
const flatten = array => array.reduce((a, b) => a.concat(Array.isArray(b) ? flatten(b) : b), []);
根据请求,分解一行基本上就是这样。
function flatten(array) {
// reduce traverses the array and we return the result
return array.reduce(function(acc, b) {
// if is an array we use recursion to perform the same operations over the array we found
// else we just concat the element to the accumulator
return acc.concat( Array.isArray(b) ? flatten(b) : b);
}, []); // we initialize the accumulator on an empty array to collect all the elements
}
function flatten(input) {
let result = [];
function extractArrayElements(input) {
for(let i = 0; i < input.length; i++){
if(Array.isArray(input[i])){
extractArrayElements(input[i]);
}else{
result.push(input[i]);
}
}
}
extractArrayElements(input);
return result;
}
// let input = [1,2,3,[4,5,[44,7,8,9]]];
// console.log(flatten(input));
// output [1,2,3,4,5,6,7,8,9]
如果只有一个字符串元素的数组:
[["$6"], ["$12"], ["$25"], ["$25"]].join(',').split(',');
将完成这项工作。与您的代码示例具体匹配的Bt。