以下内容是否会使对象满足枚举在JavaScript中的所有特性?类似于:
my.namespace.ColorEnum = {
RED : 0,
GREEN : 1,
BLUE : 2
}
// later on
if(currentColor == my.namespace.ColorEnum.RED) {
// whatever
}
还是有其他方法可以做到这一点?
以下内容是否会使对象满足枚举在JavaScript中的所有特性?类似于:
my.namespace.ColorEnum = {
RED : 0,
GREEN : 1,
BLUE : 2
}
// later on
if(currentColor == my.namespace.ColorEnum.RED) {
// whatever
}
还是有其他方法可以做到这一点?
当前回答
你的答案太复杂了
var buildSet = function(array) {
var set = {};
for (var i in array) {
var item = array[i];
set[item] = item;
}
return set;
}
var myEnum = buildSet(['RED','GREEN','BLUE']);
// myEnum.RED == 'RED' ...etc
其他回答
我也在寻找这个问题的答案,并找到了这一页的答案,我认为答案与这里的大多数答案不同:https://www.sohamkamani.com/javascript/enums/
我将把文章的答案部分复制到这里,以防将来链接无效或其他情况:
带符号的枚举:符号让我们定义保证不会冲突的值彼此之间。例如:
const Summer1 = Symbol("summer")
const Summer2 = Symbol("summer")
// Even though they have the same apparent value
// Summer1 and Summer2 don't equate
console.log(Summer1 === Summer2)
// false
console.log(Summer1)
我们可以使用符号定义枚举,以确保它们不是复制:
const Summer = Symbol("summer")
const Autumn = Symbol("autumn")
const Winter = Symbol("winter")
const Spring = Symbol("spring")
let season = Spring
switch (season) {
case Summer:
console.log('the season is summer')
break;
case Winter:
console.log('the season is winter')
break;
case Spring:
console.log('the season is spring')
break;
case Autumn:
console.log('the season is autumn')
break;
default:
console.log('season not defined')
}
使用Symbol可以确保我们分配枚举值的唯一方法是使用我们最初定义的常量。
具有类的枚举:
为了使代码更加语义正确,我们可以创建一个类保存一组枚举。例如,我们的季节应该有一种方法来识别它们都属于类似的分类。让我们看看如何使用类和对象创建不同的枚举组:
// Season enums can be grouped as static members of a class
class Season {
// Create new instances of the same class as static attributes
static Summer = new Season("summer")
static Autumn = new Season("autumn")
static Winter = new Season("winter")
static Spring = new Season("spring")
constructor(name) {
this.name = name
}
}
// Now we can access enums using namespaced assignments
// this makes it semantically clear that "Summer" is a "Season"
let season = Season.Summer
// We can verify whether a particular variable is a Season enum
console.log(season instanceof Season)
// true
console.log(Symbol('something') instanceof Season)
//false
// We can explicitly check the type based on each enums class
console.log(season.constructor.name)
// 'Season'
个人注意:我本应该使用此构造函数:(注意:将this.name设置为字符串而不是对象,会丢失以下一些验证。可以选择删除:.description。我还想找到一种方法,不必键入Seasons.summer.name,而只需:Seasons.summer即可使其返回字符串)
constructor(name) {
this.name = Symbol(name).description
}
列出所有可能的枚举值:
如果我们使用上述基于类的方法Season类的键,以获取同一类下的所有枚举值组:
Object.keys(Season).forEach(season => console.log("season:", season))
// season: Summer
// season: Autumn
// season: Winter
// season: Spring
何时在Javascript中使用枚举?
通常,如果有一定数量的固定任何一个变量的值_例如,Node.js的加密标准库有一个受支持的算法列表,可以将其视为枚举组。正确使用Javascript中的enums将产生更好的代码更稳定、更容易阅读和更少出错。
我编写了enumeranjs一个非常小的库来解决这个问题,它确保了类型安全,允许枚举常量从原型继承,保证枚举常量和枚举类型是不可变的+许多小特性。它允许重构大量代码,并在枚举定义中移动一些逻辑。下面是一个示例:
var CloseEventCodes = new Enumeration("closeEventCodes", {
CLOSE_NORMAL: { _id: 1000, info: "Connection closed normally" },
CLOSE_GOING_AWAY: { _id: 1001, info: "Connection closed going away" },
CLOSE_PROTOCOL_ERROR: { _id: 1002, info: "Connection closed due to protocol error" },
CLOSE_UNSUPPORTED: { _id: 1003, info: "Connection closed due to unsupported operation" },
CLOSE_NO_STATUS: { _id: 1005, info: "Connection closed with no status" },
CLOSE_ABNORMAL: { _id: 1006, info: "Connection closed abnormally" },
CLOSE_TOO_LARGE: { _id: 1009, info: "Connection closed due to too large packet" }
},{ talk: function(){
console.log(this.info);
}
});
CloseEventCodes.CLOSE_TOO_LARGE.talk(); //prints "Connection closed due to too large packet"
CloseEventCodes.CLOSE_TOO_LARGE instanceof CloseEventCodes //evaluates to true
枚举基本上是一个工厂。
此处提供完整记录的指南。希望这有帮助。
class Enum {
constructor (...vals) {
vals.forEach( val => {
const CONSTANT = Symbol(val);
Object.defineProperty(this, val.toUpperCase(), {
get () {
return CONSTANT;
},
set (val) {
const enum_val = "CONSTANT";
// generate TypeError associated with attempting to change the value of a constant
enum_val = val;
}
});
});
}
}
用法示例:
const COLORS = new Enum("red", "blue", "green");
这里有两种实现TypeScript枚举的不同方法。
最简单的方法是迭代一个对象,向该对象添加反向键值对。唯一的缺点是必须手动设置每个成员的值。
function _enum(list) {
for (var key in list) {
list[list[key] = list[key]] = key;
}
return Object.freeze(list);
}
var Color = _enum({
Red: 0,
Green: 5,
Blue: 2
});
// Color → {0: "Red", 2: "Blue", 5: "Green", "Red": 0, "Green": 5, "Blue": 2}
// Color.Red → 0
// Color.Green → 5
// Color.Blue → 2
// Color[5] → Green
// Color.Blue > Color.Green → false
这里有一个lodash mixin,用于使用字符串创建枚举。虽然这个版本有点复杂,但它会自动为您进行编号。本例中使用的所有lodash方法都有一个常规的JavaScript等价物,因此如果需要,可以很容易地将它们切换掉。
function enum() {
var key, val = -1, list = {};
_.reduce(_.toArray(arguments), function(result, kvp) {
kvp = kvp.split("=");
key = _.trim(kvp[0]);
val = _.parseInt(kvp[1]) || ++val;
result[result[val] = key] = val;
return result;
}, list);
return Object.freeze(list);
}
// Add enum to lodash
_.mixin({ "enum": enum });
var Color = _.enum(
"Red",
"Green",
"Blue = 5",
"Yellow",
"Purple = 20",
"Gray"
);
// Color.Red → 0
// Color.Green → 1
// Color.Blue → 5
// Color.Yellow → 6
// Color.Purple → 20
// Color.Gray → 21
// Color[5] → Blue
外星人的解决方案是让事情尽可能简单:
使用enum关键字(在javascript中保留)如果enum关键字只是保留的,但未在javascript中实现,请定义以下内容constenumerate=spec=>spec.split(/\s*,\s*/).reduce((e,n)=>对象.assign(e,{[n]:n}),{})
现在,您可以轻松使用它
const kwords = enumerate("begin,end, procedure,if")
console.log(kwords, kwords.if, kwords.if == "if", kwords.undef)
我认为没有理由使枚举值显式变量。无论如何,脚本都是纯文本的,如果代码的一部分是字符串或有效代码,则没有任何区别。真正重要的是,无论何时使用或定义引号,都不需要处理成吨的引号。