给定这个函数，我想用随机颜色生成器替换颜色。
document.overlay = GPolyline.fromEncoded({
color: "#0000FF",
weight: 10,
points: encoded_points,
zoomFactor: 32,
levels: encoded_levels,
numLevels: 4
});
我该怎么做呢?
当前回答
function randomColor(format = 'hex') {
const rnd = Math.random().toString(16).slice(-6);
if (format === 'hex') {
return '#' + rnd;
}
if (format === 'rgb') {
const [r, g, b] = rnd.match(/.{2}/g).map(c=>parseInt(c, 16));
return `rgb(${r}, ${g}, ${b})`;
}
}
其他回答
'#'+Math.random().toString(16).slice(-3) // three-numbers format aka #f3c
'#'+Math.random().toString(16).slice(-6) // six-number format aka #abc123
几乎所有以前的速记方法都会生成无效的十六进制代码(五位数)。我在这里遇到了一个类似的技巧，只是没有这个问题:
"#"+(((1+Math.random())*(1<<24)|0).toString(16)).substr(-6)
Test
在控制台试试这个:
for(i = 0; i < 200; i++) {
console.log("#"+(((1+Math.random())*(1<<24)|0).toString(16)).substr(-6));
}
递归:
var randomColor = (s='') => s.length === 6 ? '#' + s : randomColor(s + '0123456789ABCDEF'[Math.floor(Math.random() * 16)]);
randomColor();
Use:
function random_color(format)
{
var rint = Math.round(0xffffff * Math.random());
switch(format)
{
case 'hex':
return ('#0' + rint.toString(16)).replace(/^#0([0-9a-f]{6})$/i, '#$1');
break;
case 'rgb':
return 'rgb(' + (rint >> 16) + ',' + (rint >> 8 & 255) + ',' + (rint & 255) + ')';
break;
default:
return rint;
break;
}
}
升级版:
function random_color( format ){
var rint = Math.floor( 0x100000000 * Math.random());
switch( format ){
case 'hex':
return '#' + ('00000' + rint.toString(16)).slice(-6).toUpperCase();
case 'hexa':
return '#' + ('0000000' + rint.toString(16)).slice(-8).toUpperCase();
case 'rgb':
return 'rgb(' + (rint & 255) + ',' + (rint >> 8 & 255) + ',' + (rint >> 16 & 255) + ')';
case 'rgba':
return 'rgba(' + (rint & 255) + ',' + (rint >> 8 & 255) + ',' + (rint >> 16 & 255) + ',' + (rint >> 24 & 255)/255 + ')';
default:
return rint;
}
}
使用getRandomColor()代替“#0000FF”:
function getRandomColor() { var letters = '0123456789ABCDEF'; var color = '#'; for (var i = 0; i < 6; i++) { color += letters[Math.floor(Math.random() * 16)]; } return color; } function setRandomColor() { $("#colorpad").css("background-color", getRandomColor()); } <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="colorpad" style="width:300px;height:300px;background-color:#000"> </div> <button onclick="setRandomColor()">Random Color</button>
