我从来都不记得我是怎么做到的,因为它很少出现在我身上。但是在C或c++中,从标准输入中读取字符而不等待换行符(按enter)的最佳方法是什么?

理想情况下,它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。


当前回答

C和c++对I/O有一个非常抽象的看法,没有标准的方法来做你想做的事情。有从标准输入流中获取字符的标准方法(如果有的话),这两种语言都没有定义其他任何方法。因此,任何答案都必须是特定于平台的,可能不仅取决于操作系统,还取决于软件框架。

这里有一些合理的猜测,但如果不知道目标环境是什么,就无法回答您的问题。

其他回答

CONIO.H

你需要的函数是:

int getch();
Prototype
    int _getch(void); 
Description
    _getch obtains a character  from stdin. Input is unbuffered, and this
    routine  will  return as  soon as  a character is  available  without 
    waiting for a carriage return. The character is not echoed to stdout.
    _getch bypasses the normal buffering done by getchar and getc. ungetc 
    cannot be used with _getch. 
Synonym
    Function: getch 


int kbhit();
Description
    Checks if a keyboard key has been pressed but not yet read. 
Return Value
    Returns a non-zero value if a key was pressed. Otherwise, returns 0.

libconio http://sourceforge.net/projects/libconio

or

conio.h的Linux c++实现 http://sourceforge.net/projects/linux-conioh

下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)

#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>

char* getStr( char* buffer , int maxRead ) {
  int  numRead  = 0;
  char ch;

  struct termios old = {0};
  struct termios new = {0};
  if( tcgetattr( 0 , &old ) < 0 )        perror( "tcgetattr() old settings" );
  if( tcgetattr( 0 , &new ) < 0 )        perror( "tcgetaart() new settings" );
  cfmakeraw( &new );
  if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );

  for( int i = 0 ; i < maxRead ; i++)  {
    ch = getchar();
    switch( ch )  {
      case EOF: 
      case '\n':
      case '\r':
        goto exit_getStr;
        break;

      default:
        printf( "%1c" , ch );
        buffer[ numRead++ ] = ch;
        if( numRead >= maxRead )  {
          goto exit_getStr;
        }
        break;
    }
  }

exit_getStr:
  if( tcsetattr( 0 , TCSADRAIN , &old) < 0)   perror ("tcsetattr reset to old" );
  printf( "\n" );   
  return buffer;
}


int main( void ) 
{
  const int maxChars = 20;
  char      stringBuffer[ maxChars+1 ];
  memset(   stringBuffer , 0 , maxChars+1 ); // initialize to 0

  printf( "enter a string: ");
  getStr( stringBuffer , maxChars );
  printf( "you entered: [%s]\n" , stringBuffer );
}

You can do it portably using SDL (the Simple DirectMedia Library), though I suspect you may not like its behavior. When I tried it, I had to have SDL create a new video window (even though I didn't need it for my program) and have this window "grab" almost all keyboard and mouse input (which was okay for my usage but could be annoying or unworkable in other situations). I suspect it's overkill and not worth it unless complete portability is a must--otherwise try one of the other suggested solutions.

顺便说一下,这将分别提供按键和释放事件,如果你喜欢的话。

#include <conio.h>

if (kbhit() != 0) {
    cout << getch() << endl;
}

它使用kbhit()来检查键盘是否被按下,并使用getch()来获取被按下的字符。

在Linux(和其他类unix系统)上,这可以通过以下方式完成:

#include <unistd.h>
#include <termios.h>

char getch() {
        char buf = 0;
        struct termios old = {0};
        if (tcgetattr(0, &old) < 0)
                perror("tcsetattr()");
        old.c_lflag &= ~ICANON;
        old.c_lflag &= ~ECHO;
        old.c_cc[VMIN] = 1;
        old.c_cc[VTIME] = 0;
        if (tcsetattr(0, TCSANOW, &old) < 0)
                perror("tcsetattr ICANON");
        if (read(0, &buf, 1) < 0)
                perror ("read()");
        old.c_lflag |= ICANON;
        old.c_lflag |= ECHO;
        if (tcsetattr(0, TCSADRAIN, &old) < 0)
                perror ("tcsetattr ~ICANON");
        return (buf);
}

基本上你必须关闭规范模式(和回声模式来抑制回声)。