另一个!

let result const givenStr = 'A, X' //values separated by comma or space. const allowed = ['A', 'B'] const given = givenStr.split(/[\s,]+/).filter(v => v) console.log('given (array):', given) // given contains none or only allowed values: result = given.reduce((acc, val) => { return acc && allowed.includes(val) }, true) console.log('given contains none or only allowed values:', result) // given contains at least one allowed value: result = given.reduce((acc, val) => { return acc || allowed.includes(val) }, false) console.log('given contains at least one allowed value:', result)

也许晚了，但这里是我的解决方案为一个数组和两个或更多的项目 / 1 | 2 /。Test (['one'， 'two'， 'three'， 'four']。加入(' '))

console.log(/ 1 | 2 /。Test (['one'， 'two'， 'three'， 'four']。加入(' ')))

另一个!

let result const givenStr = 'A, X' //values separated by comma or space. const allowed = ['A', 'B'] const given = givenStr.split(/[\s,]+/).filter(v => v) console.log('given (array):', given) // given contains none or only allowed values: result = given.reduce((acc, val) => { return acc && allowed.includes(val) }, true) console.log('given contains none or only allowed values:', result) // given contains at least one allowed value: result = given.reduce((acc, val) => { return acc || allowed.includes(val) }, false) console.log('given contains at least one allowed value:', result)

(错误答案，不要抄)

你也可以这样做:

Const STR = "hi, there" Const res = str.includes("hello") || str.includes("hi") || str.includes('howdy'); console.log (res);

只要其中一个include返回真值，value就为真，否则，它就为假。这在ES6中工作得非常好。

使用includes()，没有，但你可以通过test()实现REGEX:

var value = /hello|hi|howdy/.test(str);

或者，如果词语来自动态来源:

var words = ['hello', 'hi', 'howdy'];
var value = new RegExp(words.join('|')).test(str);

REGEX方法是一个更好的主意，因为它允许您将单词匹配为实际单词，而不是其他单词的子字符串。你只需要边界标记\b这个词，那么:

var str = 'hilly';
var value = str.includes('hi'); //true, even though the word 'hi' isn't found
var value = /\bhi\b/.test(str); //false - 'hi' appears but not as its own word