只是想知道，是否有一种方法可以向.includes方法添加多个条件，例如:
var value = str.includes("hello", "hi", "howdy");
想象一下逗号表示“或”。
它现在询问字符串是否包含hello, hi或howdy。所以只有当其中一个条件为真。
有什么方法可以做到吗?
当前回答
不是最好的答案，也不是最干净的答案，但我认为它更宽容。 比如，如果你想对所有的支票使用相同的过滤器。 实际上.filter()与数组一起工作并返回一个过滤后的数组(我发现这也更容易使用)。
var str1 = 'hi, how do you do?';
var str2 = 'regular string';
var conditions = ["hello", "hi", "howdy"];
// Solve the problem
var res1 = [str1].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));
var res2 = [str2].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));
console.log(res1); // ["hi, how do you do?"]
console.log(res2); // []
// More useful in this case
var text = [str1, str2, "hello world"];
// Apply some filters on data
var res3 = text.filter(data => data.includes(conditions[0]) && data.includes(conditions[2]));
// You may use again the same filters for a different check
var res4 = text.filter(data => data.includes(conditions[0]) || data.includes(conditions[1]));
console.log(res3); // []
console.log(res4); // ["hi, how do you do?", "hello world"]
其他回答
您可以使用这里引用的.some方法。
some()方法测试数组中是否至少有一个元素 通过由提供的函数实现的测试。
// test cases const str1 = 'hi hello, how do you do?'; const str2 = 'regular string'; const str3 = 'hello there'; // do the test strings contain these terms? const conditions = ["hello", "hi", "howdy"]; // run the tests against every element in the array const test1 = conditions.some(el => str1.includes(el)); const test2 = conditions.some(el => str2.includes(el)); // strictly check that contains 1 and only one match const test3 = conditions.reduce((a,c) => a + str3.includes(c), 0) == 1; // display results console.log(`Loose matching, 2 matches "${str1}" => ${test1}`); console.log(`Loose matching, 0 matches "${str2}" => ${test2}`); console.log(`Exact matching, 1 matches "${str3}" => ${test3}`);
另外，正如下面一位用户提到的那样，匹配上面提到的“恰好一个”外观也很有趣(这是OP要求的)。这可以类似地用.reduce计算交点，然后检查它们是否等于1。
这可以通过使用Array和RegEx的一些/每个方法来完成。
检查list(array)中的所有单词是否存在于字符串中:
const multiSearchAnd = (text, searchWords) => (
searchWords.every((el) => {
return text.match(new RegExp(el,"i"))
})
)
multiSearchAnd("Chelsey Dietrich Engineer 2018-12-11 Hire", ["cle", "hire"]) //returns false
multiSearchAnd("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "hire"]) //returns true
检查list(array)中的任何单词是否存在于字符串中:
const multiSearchOr = (text, searchWords) => (
searchWords.some((el) => {
return text.match(new RegExp(el,"i"))
})
)
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "hire"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["aaa", "hire"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "zzzz"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["aaa", "1111"]) //returns false
与数组数据/的精确匹配
const dataArray = ["amoos"， "rifat"， "hello"]; const findId = (data, id) => { 让res = data。Find (el => el == id) 返回res ?真:假; ｝ console.log(findId(dataArray， 'Hi')) // false console.log(findId(dataArray， 'amoos')) // true
const givenArray = ['Hi, how are you'， 'how are you'， 'howdy, how you doing'] const includeValues = ["hello"， "hi"， "howdy"] const filteredStrArray = givenArray。filter(str => includeValues)str.toLowerCase().includes(value))) console.log (filteredStrArray);
不是最好的答案，也不是最干净的答案，但我认为它更宽容。 比如，如果你想对所有的支票使用相同的过滤器。 实际上.filter()与数组一起工作并返回一个过滤后的数组(我发现这也更容易使用)。
var str1 = 'hi, how do you do?';
var str2 = 'regular string';
var conditions = ["hello", "hi", "howdy"];
// Solve the problem
var res1 = [str1].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));
var res2 = [str2].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));
console.log(res1); // ["hi, how do you do?"]
console.log(res2); // []
// More useful in this case
var text = [str1, str2, "hello world"];
// Apply some filters on data
var res3 = text.filter(data => data.includes(conditions[0]) && data.includes(conditions[2]));
// You may use again the same filters for a different check
var res4 = text.filter(data => data.includes(conditions[0]) || data.includes(conditions[1]));
console.log(res3); // []
console.log(res4); // ["hi, how do you do?", "hello world"]
