如何删除已合并的分支?我可以一次删除所有分支,而不是逐个删除每个分支吗?


当前回答

我的Bash脚本贡献大致基于mmrobin的答案。

它需要一些有用的参数来指定include和exclude,或者只检查/删除本地或远程分支,而不是两者。

#!/bin/bash

# exclude branches regex, configure as "(branch1|branch2|etc)$"
excludes_default="(master|next|ag/doc-updates)$"
excludes="__NOTHING__"
includes=
merged="--merged"
local=1
remote=1

while [ $# -gt 0 ]; do
  case "$1" in
  -i) shift; includes="$includes $1" ;;
  -e) shift; excludes="$1" ;;
  --no-local) local=0 ;;
  --no-remote) remote=0 ;;
  --all) merged= ;;
  *) echo "Unknown argument $1"; exit 1 ;;
  esac
  shift   # next option
done

if [ "$includes" == "" ]; then
  includes=".*"
else
  includes="($(echo $includes | sed -e 's/ /|/g'))"
fi

current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
if [ "$current_branch" != "master" ]; then
  echo "WARNING: You are on branch $current_branch, NOT master."
fi
echo -e "Fetching branches...\n"

git remote update --prune
remote_branches=$(git branch -r $merged | grep -v "/$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
local_branches=$(git branch $merged | grep -v "$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
  echo "No existing branches have been merged into $current_branch."
else
  echo "This will remove the following branches:"
  if [ "$remote" == 1 -a -n "$remote_branches" ]; then
    echo "$remote_branches"
  fi
  if [ "$local" == 1 -a -n "$local_branches" ]; then
    echo "$local_branches"
  fi
  read -p "Continue? (y/n): " -n 1 choice
  echo
  if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
    if [ "$remote" == 1 ]; then
      remotes=$(git remote)
      # Remove remote branches
      for remote in $remotes
      do
        branches=$(echo "$remote_branches" | grep "$remote/" | sed "s/$remote\/\(.*\)/:\1 /g" | tr -d '\n')
        git push $remote $branches
      done
    fi

    if [ "$local" == 1 ]; then
      # Remove local branches
      locals=$(echo "$local_branches" | sed 's/origin\///g' | tr -d '\n')
      if [ -z "$locals" ]; then
        echo "No branches removed."
      else
        git branch -d $(echo "$locals" | tr -d '\n')
      fi
    fi
  fi
fi

其他回答

您可以使用git del br工具。

git-del-br -a

您可以使用pip安装它

pip install git-del-br

P.S:我是这个工具的作者。欢迎提出任何建议/反馈。

以下查询适用于我

for branch in  `git branch -r --merged | grep -v '\*\|master\|develop'|awk 'NR > 0 {print$1}'|awk '{gsub(/origin\//, "")}1'`;do git push origin --delete $branch; done

这将过滤grep管道中的任何给定分支。

在http克隆上运行良好,但在ssh连接上运行不太好。

基于这些答案,我也制作了自己的Bash脚本来实现这一点!

它使用gitbranch--merged和gitbranch-d删除已合并的分支,并在删除之前提示您输入每个分支。

merged_branches () {
    local current_branch=$(git rev-parse --abbrev-ref HEAD)
    for branch in $(git branch --merged | cut -c3-)
      do
        echo "Branch $branch is already merged into $current_branch."
        echo "Would you like to delete it? [Y]es/[N]o "
        read REPLY
        if [[ $REPLY =~ ^[Yy] ]]; then
            git branch -d $branch
        fi
    done
}
$ git config --global alias.cleanup
'!git branch --merged origin/master | egrep -v "(^\*|master|staging|dev)" | xargs git branch -d'

(为便于阅读,拆分为多行)

调用“gitcleanup”将删除已合并到origin/master中的本地分支。它跳过master、staging和dev,因为我们不想在正常情况下删除它们。

将其分解为以下内容:

git-config--全局别名清理这将创建一个名为“cleanup”的全局别名(在所有回购中)这个在命令的开头,我们将使用一些非git命令作为别名的一部分,因此我们需要在这里实际运行bash命令git branch—合并的原始/主此命令返回已合并到原始/master的分支名称列表egrep-v“(^\*|master|staging|dev)”这将从已合并的分支列表中删除master、staging和dev分支。我们不想删除这些分支,因为它们不是功能。xargs git分支-d这将为每个未合并的分支运行gitbranch-d xxxxx命令。这将逐个删除本地分支。

对于那些使用Windows并喜欢PowerShell脚本的人,这里有一个删除本地合并分支的脚本:

function Remove-MergedBranches
{
  git branch --merged |
    ForEach-Object { $_.Trim() } |
    Where-Object { $_ -NotMatch "^\*" } |
    Where-Object { -not ( $_ -Like "*master" -or $_ -Like "*main" ) } |
    ForEach-Object { git branch -d $_ }
}

或者简称:

git branch --merged | %{$_.trim()}  | ?{$_ -notmatch 'dev' -and $_ -notmatch 'master' -and $_ -notmatch 'main'} | %{git branch -d $_.trim()}