如何删除已合并的分支?我可以一次删除所有分支,而不是逐个删除每个分支吗?
当前回答
我的Bash脚本贡献大致基于mmrobin的答案。
它需要一些有用的参数来指定include和exclude,或者只检查/删除本地或远程分支,而不是两者。
#!/bin/bash
# exclude branches regex, configure as "(branch1|branch2|etc)$"
excludes_default="(master|next|ag/doc-updates)$"
excludes="__NOTHING__"
includes=
merged="--merged"
local=1
remote=1
while [ $# -gt 0 ]; do
case "$1" in
-i) shift; includes="$includes $1" ;;
-e) shift; excludes="$1" ;;
--no-local) local=0 ;;
--no-remote) remote=0 ;;
--all) merged= ;;
*) echo "Unknown argument $1"; exit 1 ;;
esac
shift # next option
done
if [ "$includes" == "" ]; then
includes=".*"
else
includes="($(echo $includes | sed -e 's/ /|/g'))"
fi
current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
if [ "$current_branch" != "master" ]; then
echo "WARNING: You are on branch $current_branch, NOT master."
fi
echo -e "Fetching branches...\n"
git remote update --prune
remote_branches=$(git branch -r $merged | grep -v "/$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
local_branches=$(git branch $merged | grep -v "$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
echo "No existing branches have been merged into $current_branch."
else
echo "This will remove the following branches:"
if [ "$remote" == 1 -a -n "$remote_branches" ]; then
echo "$remote_branches"
fi
if [ "$local" == 1 -a -n "$local_branches" ]; then
echo "$local_branches"
fi
read -p "Continue? (y/n): " -n 1 choice
echo
if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
if [ "$remote" == 1 ]; then
remotes=$(git remote)
# Remove remote branches
for remote in $remotes
do
branches=$(echo "$remote_branches" | grep "$remote/" | sed "s/$remote\/\(.*\)/:\1 /g" | tr -d '\n')
git push $remote $branches
done
fi
if [ "$local" == 1 ]; then
# Remove local branches
locals=$(echo "$local_branches" | sed 's/origin\///g' | tr -d '\n')
if [ -z "$locals" ]; then
echo "No branches removed."
else
git branch -d $(echo "$locals" | tr -d '\n')
fi
fi
fi
fi
其他回答
编写一个脚本,Git将检查所有已合并到master的分支。
然后做git结账大师。
最后,删除合并的分支。
for k in $(git branch -ra --merged | egrep -v "(^\*|master)"); do
branchnew=$(echo $k | sed -e "s/origin\///" | sed -e "s/remotes\///")
echo branch-name: $branchnew
git checkout $branchnew
done
git checkout master
for k in $(git branch -ra --merged | egrep -v "(^\*|master)"); do
branchnew=$(echo $k | sed -e "s/origin\///" | sed -e "s/remotes\///")
echo branch-name: $branchnew
git push origin --delete $branchnew
done
这也适用于删除除主分支之外的所有合并分支。
git branch --merged | grep -v '^* master$' | grep -v '^ master$' | xargs git branch -d
以下查询适用于我
for branch in `git branch -r --merged | grep -v '\*\|master\|develop'|awk 'NR > 0 {print$1}'|awk '{gsub(/origin\//, "")}1'`;do git push origin --delete $branch; done
这将过滤grep管道中的任何给定分支。
在http克隆上运行良好,但在ssh连接上运行不太好。
对于那些使用Windows并喜欢PowerShell脚本的人,这里有一个删除本地合并分支的脚本:
function Remove-MergedBranches
{
git branch --merged |
ForEach-Object { $_.Trim() } |
Where-Object { $_ -NotMatch "^\*" } |
Where-Object { -not ( $_ -Like "*master" -or $_ -Like "*main" ) } |
ForEach-Object { git branch -d $_ }
}
或者简称:
git branch --merged | %{$_.trim()} | ?{$_ -notmatch 'dev' -and $_ -notmatch 'master' -and $_ -notmatch 'main'} | %{git branch -d $_.trim()}
我使用一个Python脚本,它自动执行最流行的答案中的步骤,并检查其余分支,看看它们是否会在合并时产生任何更改,如果没有,则交互提示删除它们:https://github.com/robertknight/prune-merged-branches.
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