如何删除已合并的分支?我可以一次删除所有分支,而不是逐个删除每个分支吗?
当前回答
我的Bash脚本贡献大致基于mmrobin的答案。
它需要一些有用的参数来指定include和exclude,或者只检查/删除本地或远程分支,而不是两者。
#!/bin/bash
# exclude branches regex, configure as "(branch1|branch2|etc)$"
excludes_default="(master|next|ag/doc-updates)$"
excludes="__NOTHING__"
includes=
merged="--merged"
local=1
remote=1
while [ $# -gt 0 ]; do
case "$1" in
-i) shift; includes="$includes $1" ;;
-e) shift; excludes="$1" ;;
--no-local) local=0 ;;
--no-remote) remote=0 ;;
--all) merged= ;;
*) echo "Unknown argument $1"; exit 1 ;;
esac
shift # next option
done
if [ "$includes" == "" ]; then
includes=".*"
else
includes="($(echo $includes | sed -e 's/ /|/g'))"
fi
current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
if [ "$current_branch" != "master" ]; then
echo "WARNING: You are on branch $current_branch, NOT master."
fi
echo -e "Fetching branches...\n"
git remote update --prune
remote_branches=$(git branch -r $merged | grep -v "/$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
local_branches=$(git branch $merged | grep -v "$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
echo "No existing branches have been merged into $current_branch."
else
echo "This will remove the following branches:"
if [ "$remote" == 1 -a -n "$remote_branches" ]; then
echo "$remote_branches"
fi
if [ "$local" == 1 -a -n "$local_branches" ]; then
echo "$local_branches"
fi
read -p "Continue? (y/n): " -n 1 choice
echo
if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
if [ "$remote" == 1 ]; then
remotes=$(git remote)
# Remove remote branches
for remote in $remotes
do
branches=$(echo "$remote_branches" | grep "$remote/" | sed "s/$remote\/\(.*\)/:\1 /g" | tr -d '\n')
git push $remote $branches
done
fi
if [ "$local" == 1 ]; then
# Remove local branches
locals=$(echo "$local_branches" | sed 's/origin\///g' | tr -d '\n')
if [ -z "$locals" ]; then
echo "No branches removed."
else
git branch -d $(echo "$locals" | tr -d '\n')
fi
fi
fi
fi
其他回答
如果您使用的是带有git插件的OhMyZSH,则可以使用gbda别名。
如何在PowerShell控制台中删除合并的分支
git branch --merged | %{git branch -d $_.Trim()}
如果要排除master或任何其他分支名称,可以使用PowerShell Select String这样进行管道,并将结果传递给git branch-d:
git branch -d $(git branch --merged | Select-String -NotMatch "master" | %{$_.ToString().Trim()})
您可以将提交添加到--merged选项。这样,您可以确保只删除合并到原始/主文件中的分支
以下命令将从原点删除合并的分支。
git branch -r --merged origin/master | grep -v "^.*master" | sed s:origin/:: |xargs -n 1 git push origin --delete
您可以测试将删除哪些分支来替换git推送原点--delete with echo
git branch -r --merged origin/master | grep -v "^.*master" | sed s:origin/:: |xargs -n 1 echo
使用Git版本2.5.0:
git branch -d `git branch --merged`
刚刚为此创建了python脚本:
import sys
from shutil import which
import logging
from subprocess import check_output, call
logger = logging.getLogger(__name__)
if __name__ == '__main__':
if which("git") is None:
logger.error("git is not found!")
sys.exit(-1)
branches = check_output("git branch -r --merged".split()).strip().decode("utf8").splitlines()
current = check_output("git branch --show-current".split()).strip().decode("utf8")
blacklist = ["master", current]
for b in branches:
b = b.split("/")[-1]
if b in blacklist:
continue
else:
if input(f"Do you want to delete branch: '{b}' [y/n]\n").lower() == "y":
call(f"git branch -D {b}".split())
call(f"git push --delete origin {b}".split())
推荐文章
- 为什么我需要显式地推一个新分支?
- 如何撤消最后的git添加?
- Rubymine:如何让Git忽略Rubymine创建的.idea文件
- Gitignore二进制文件,没有扩展名
- Git隐藏错误:Git隐藏弹出并最终与合并冲突
- 了解Git和GitHub的基础知识
- 没有。Git目录的Git克隆
- Git与Mercurial仓库的互操作性
- 忽略git中修改(但未提交)的文件?
- “git restore”命令是什么?“git restore”和“git reset”之间有什么区别?
- Git合并与强制覆盖
- Git拉另一个分支
- 在Bash命令提示符上添加git分支
- 如何更改Git日志日期格式
- git pull -rebase和git pull -ff-only之间的区别