如何将一个数除3而不使用*、/、+、-、%等运算符?

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当前回答

这个方法(c#)怎么样?

private int dividedBy3(int n) {
        List<Object> a = new Object[n].ToList();
        List<Object> b = new List<object>();
        while (a.Count > 2) {
            a.RemoveRange(0, 3);
            b.Add(new Object());
        }
        return b.Count;
    }

其他回答

#!/bin/ruby

def div_by_3(i)
  i.div 3        # always return int http://www.ruby-doc.org/core-1.9.3/Numeric.html#method-i-div
end

好吧,我想我们都同意这不是一个现实世界的问题。为了好玩,这里是如何用Ada和多线程来做这件事:

with Ada.Text_IO;

procedure Divide_By_3 is

   protected type Divisor_Type is
      entry Poke;
      entry Finish;
   private
      entry Release;
      entry Stop_Emptying;
      Emptying : Boolean := False;
   end Divisor_Type;

   protected type Collector_Type is
      entry Poke;
      entry Finish;
   private
      Emptying : Boolean := False;
   end Collector_Type;

   task type Input is
   end Input;
   task type Output is
   end Output;

   protected body Divisor_Type is
      entry Poke when not Emptying and Stop_Emptying'Count = 0 is
      begin
         requeue Release;
      end Poke;
      entry Release when Release'Count >= 3 or Emptying is
         New_Output : access Output;
      begin
         if not Emptying then
            New_Output := new Output;
            Emptying := True;
            requeue Stop_Emptying;
         end if;
      end Release;
      entry Stop_Emptying when Release'Count = 0 is
      begin
         Emptying := False;
      end Stop_Emptying;
      entry Finish when Poke'Count = 0 and Release'Count < 3 is
      begin
         Emptying := True;
         requeue Stop_Emptying;
      end Finish;
   end Divisor_Type;

   protected body Collector_Type is
      entry Poke when Emptying is
      begin
         null;
      end Poke;
      entry Finish when True is
      begin
         Ada.Text_IO.Put_Line (Poke'Count'Img);
         Emptying := True;
      end Finish;
   end Collector_Type;

   Collector : Collector_Type;
   Divisor : Divisor_Type;

   task body Input is
   begin
      Divisor.Poke;
   end Input;

   task body Output is
   begin
      Collector.Poke;
   end Output;

   Cur_Input : access Input;

   -- Input value:
   Number : Integer := 18;
begin
   for I in 1 .. Number loop
      Cur_Input := new Input;
   end loop;
   Divisor.Finish;
   Collector.Finish;
end Divide_By_3;

使用黑客的喜悦魔术数字计算器

int divideByThree(int num)
{
  return (fma(num, 1431655766, 0) >> 32);
}

其中fma是在math.h头文件中定义的标准库函数。

#include <stdio.h>

typedef struct { char a,b,c; } Triple;

unsigned long div3(Triple *v, char *r) {
  if ((long)v <= 2)  
    return (unsigned long)r;
  return div3(&v[-1], &r[1]);
}

int main() {
  unsigned long v = 21; 
  int r = div3((Triple*)v, 0); 
  printf("%ld / 3 = %d\n", v, r); 
  return 0;
}

很好bc:

$ num=1337; printf "scale=5;${num}\x2F3;\n" | bc
445.66666