由于这个问题有很多注意力和答案,参考内置的功能,如 Object.assign 或自定义代码到深克隆,我想分享一些图书馆到深克隆,

1、斯克隆

npm 安装 --savedev esclone https://www.npmjs.com/package/esclone

在 ES6 中使用例子:

import esclone from "esclone";

const rockysGrandFather = {
  name: "Rockys grand father",
  father: "Don't know :("
};
const rockysFather = {
  name: "Rockys Father",
  father: rockysGrandFather
};

const rocky = {
  name: "Rocky",
  father: rockysFather
};

const rockyClone = esclone(rocky);

在 ES5 中使用例子:

var esclone = require("esclone")
var foo = new String("abcd")
var fooClone = esclone.default(foo)
console.log(fooClone)
console.log(foo === fooClone)

二、深度复制

npm 安装深复制 https://www.npmjs.com/package/deep-copy

例子:

var dcopy = require('deep-copy')

// deep copy object 
var copy = dcopy({a: {b: [{c: 5}]}})

// deep copy array 
var copy = dcopy([1, 2, {a: {b: 5}}])

3、克隆深度

$ npm 安装 --save clone-deep https://www.npmjs.com/package/clone-deep

例子:

var cloneDeep = require('clone-deep');

var obj = {a: 'b'};
var arr = [obj];

var copy = cloneDeep(arr);
obj.c = 'd';

console.log(copy);
//=> [{a: 'b'}] 

console.log(arr);

我知道这是一个古老的帖子,但我以为这可能有助于下一个人,谁在跳动。

只要你不分配一个对象到任何东西,它保留没有参考在记忆中,所以要创建一个对象,你想在其他对象中分享,你将不得不创建一个工厂如下:

var a = function(){
    return {
        father:'zacharias'
    };
},
b = a(),
c = a();
c.father = 'johndoe';
alert(b.father);

代码:

// extends 'from' object with members from 'to'. If 'to' is null, a deep clone of 'from' is returned
function extend(from, to)
{
    if (from == null || typeof from != "object") return from;
    if (from.constructor != Object && from.constructor != Array) return from;
    if (from.constructor == Date || from.constructor == RegExp || from.constructor == Function ||
        from.constructor == String || from.constructor == Number || from.constructor == Boolean)
        return new from.constructor(from);

    to = to || new from.constructor();

    for (var name in from)
    {
        to[name] = typeof to[name] == "undefined" ? extend(from[name], null) : to[name];
    }

    return to;
}

测试:

var obj =
{
    date: new Date(),
    func: function(q) { return 1 + q; },
    num: 123,
    text: "asdasd",
    array: [1, "asd"],
    regex: new RegExp(/aaa/i),
    subobj:
    {
        num: 234,
        text: "asdsaD"
    }
}

var clone = extend(obj);

structuredClone(value)

如有必要,先加载聚合物:

import structuredClone from '@ungap/structured-clone';

查看此答案更多详细信息

如果您不使用日期、功能、未定义、无限、RegExps、地图、集、博布、文件列表、图像数据、分布式列表、类型列表或其它复杂类型在您的对象中,那么一个非常简单的单一列表来深化对象是:

JSON.parse(JSON.stringify(对象) )

lodash - cloneDeep; 可以通过 lodash.clonedeep 模块单独进口,并且可能是您最好的选择,如果您已经不使用图书馆,提供深度克隆功能 AngularJS - angular.copy jQuery - jQuery.extend(真实, { }, oldObject);.clone() 只克隆 DOM 元素仅图书馆 - just-clone; 一部分图书馆的零依赖 npm 模块,只做一件事。

如果您正在使用它,UnderScore.js图书馆有一个克隆方法。

var newObject = _.clone(oldObject);

单线 ECMAScript 6 解决方案(特殊对象类型如 Date/Regex 未处理):

const clone = (o) => typeof o === 'object' && o!== null? // only clone objects (Array.isArray(o)? // if cloning an array o.map(e => clone(e)) : // clone each of its elements Object.keys(o).reduce( // otherwise reduce every key in the object (r, k) => (r[k] = clone(o[k]), r), {} // and save its cloned value