什么是最有效的方式来克隆一个JavaScript对象?我已经看到obj = eval(uneval(o));被使用,但它是非标准的,仅支持Firefox.我做了事情,如obj = JSON.parse(JSON.stringify(o));但质疑效率。
当前回答
如果你发现自己做这种类型的事情是正常的(例如,创建 undo redo 功能 ) 它可能值得看看 Immutable.js
const map1 = Immutable.fromJS( { a: 1, b: 2, c: { d: 3 } } );
const map2 = map1.setIn( [ 'c', 'd' ], 50 );
console.log( `${ map1.getIn( [ 'c', 'd' ] ) } vs ${ map2.getIn( [ 'c', 'd' ] ) }` ); // "3 vs 50"
https://codepen.io/anon/pen/OBpqNE?编辑器=1111
其他回答
英格兰
好吧,如果你使用角,你也可以这样做。
var newObject = angular.copy(oldObject);
这里是一个全面的克隆()方法,可以克隆任何JavaScript对象,它处理几乎所有情况:
function clone(src, deep) {
var toString = Object.prototype.toString;
if (!src && typeof src != "object") {
// Any non-object (Boolean, String, Number), null, undefined, NaN
return src;
}
// Honor native/custom clone methods
if (src.clone && toString.call(src.clone) == "[object Function]") {
return src.clone(deep);
}
// DOM elements
if (src.nodeType && toString.call(src.cloneNode) == "[object Function]") {
return src.cloneNode(deep);
}
// Date
if (toString.call(src) == "[object Date]") {
return new Date(src.getTime());
}
// RegExp
if (toString.call(src) == "[object RegExp]") {
return new RegExp(src);
}
// Function
if (toString.call(src) == "[object Function]") {
//Wrap in another method to make sure == is not true;
//Note: Huge performance issue due to closures, comment this :)
return (function(){
src.apply(this, arguments);
});
}
var ret, index;
//Array
if (toString.call(src) == "[object Array]") {
//[].slice(0) would soft clone
ret = src.slice();
if (deep) {
index = ret.length;
while (index--) {
ret[index] = clone(ret[index], true);
}
}
}
//Object
else {
ret = src.constructor ? new src.constructor() : {};
for (var prop in src) {
ret[prop] = deep
? clone(src[prop], true)
: src[prop];
}
}
return ret;
};
// obj target object, vals source object
var setVals = function (obj, vals) {
if (obj && vals) {
for (var x in vals) {
if (vals.hasOwnProperty(x)) {
if (obj[x] && typeof vals[x] === 'object') {
obj[x] = setVals(obj[x], vals[x]);
} else {
obj[x] = vals[x];
}
}
}
}
return obj;
};
代码:
// extends 'from' object with members from 'to'. If 'to' is null, a deep clone of 'from' is returned
function extend(from, to)
{
if (from == null || typeof from != "object") return from;
if (from.constructor != Object && from.constructor != Array) return from;
if (from.constructor == Date || from.constructor == RegExp || from.constructor == Function ||
from.constructor == String || from.constructor == Number || from.constructor == Boolean)
return new from.constructor(from);
to = to || new from.constructor();
for (var name in from)
{
to[name] = typeof to[name] == "undefined" ? extend(from[name], null) : to[name];
}
return to;
}
测试:
var obj =
{
date: new Date(),
func: function(q) { return 1 + q; },
num: 123,
text: "asdasd",
array: [1, "asd"],
regex: new RegExp(/aaa/i),
subobj:
{
num: 234,
text: "asdsaD"
}
}
var clone = extend(obj);
这是我创建的最快的方法,不使用原型,所以它将保持在新对象中拥有自己的所有权。
解决方案是对原件的顶级属性进行 iterate,创建两个副本,从原件中删除每个属性,然后重新设置原件并返回新副本,它只需要像顶级属性一样多次 iterate。
唯一的缺点是,原始对象必须配备其原创创建的名称空间,以便重新设置。
copyDeleteAndReset:function(namespace,strObjName){
var obj = namespace[strObjName],
objNew = {},objOrig = {};
for(i in obj){
if(obj.hasOwnProperty(i)){
objNew[i] = objOrig[i] = obj[i];
delete obj[i];
}
}
namespace[strObjName] = objOrig;
return objNew;
}
var namespace = {};
namespace.objOrig = {
'0':{
innerObj:{a:0,b:1,c:2}
}
}
var objNew = copyDeleteAndReset(namespace,'objOrig');
objNew['0'] = 'NEW VALUE';
console.log(objNew['0']) === 'NEW VALUE';
console.log(namespace.objOrig['0']) === innerObj:{a:0,b:1,c:2};