什么是最有效的方式来克隆一个JavaScript对象?我已经看到obj = eval(uneval(o));被使用,但它是非标准的,仅支持Firefox.我做了事情,如obj = JSON.parse(JSON.stringify(o));但质疑效率。
当前回答
这是我创建的最快的方法,不使用原型,所以它将保持在新对象中拥有自己的所有权。
解决方案是对原件的顶级属性进行 iterate,创建两个副本,从原件中删除每个属性,然后重新设置原件并返回新副本,它只需要像顶级属性一样多次 iterate。
唯一的缺点是,原始对象必须配备其原创创建的名称空间,以便重新设置。
copyDeleteAndReset:function(namespace,strObjName){
var obj = namespace[strObjName],
objNew = {},objOrig = {};
for(i in obj){
if(obj.hasOwnProperty(i)){
objNew[i] = objOrig[i] = obj[i];
delete obj[i];
}
}
namespace[strObjName] = objOrig;
return objNew;
}
var namespace = {};
namespace.objOrig = {
'0':{
innerObj:{a:0,b:1,c:2}
}
}
var objNew = copyDeleteAndReset(namespace,'objOrig');
objNew['0'] = 'NEW VALUE';
console.log(objNew['0']) === 'NEW VALUE';
console.log(namespace.objOrig['0']) === innerObj:{a:0,b:1,c:2};
其他回答
class Handler { static deepCopy (obj) { if (Object.prototype.toString.call(obj) === '[object Array]') { const result = []; for (let i = 0, len = obj.length; i < len; i++) { result[i] = Handler.deepCopy(obj[i]); } return result; } else if (Object.prototype.toString.call(obj) === '[object Object]') { const result = {}; for (let prop in obj) { result[prop] = Handler.deepCopy(obj[prop]); } return result; } return obj; } }
结构化克隆
HTML 标准包含一个内部结构化的克隆/序列化算法,可以创建对象的深度克隆,它仍然仅限于某些内置类型,但除了由 JSON 支持的少数类型之外,它还支持日期、RegExps、地图、套件、Blobs、FileLists、ImageDatas、Sparse Arrays、Typed Arrays等。
结构化Clone 全球功能由 Node 17.0 提供:
const clone = structuredClone(original);
以前版本: Node.js 的 v8 模块(如 Node 11 )直接展示了结构化序列化 API,但此功能仍然被标记为“实验性”,并在未来的版本中可更改或删除。
const v8 = require('v8');
const structuredClone = obj => {
return v8.deserialize(v8.serialize(obj));
};
直接支持浏览器:可用于Firefox 94
const clone = structuredClone(original);
class StructuredCloner {
constructor() {
this.pendingClones_ = new Map();
this.nextKey_ = 0;
const channel = new MessageChannel();
this.inPort_ = channel.port1;
this.outPort_ = channel.port2;
this.outPort_.onmessage = ({data: {key, value}}) => {
const resolve = this.pendingClones_.get(key);
resolve(value);
this.pendingClones_.delete(key);
};
this.outPort_.start();
}
cloneAsync(value) {
return new Promise(resolve => {
const key = this.nextKey_++;
this.pendingClones_.set(key, resolve);
this.inPort_.postMessage({key, value});
});
}
}
const structuredCloneAsync = window.structuredCloneAsync =
StructuredCloner.prototype.cloneAsync.bind(new StructuredCloner);
const main = async () => {
const original = { date: new Date(), number: Math.random() };
original.self = original;
const clone = await structuredCloneAsync(original);
// They're different objects:
console.assert(original !== clone);
console.assert(original.date !== clone.date);
// They're cyclical:
console.assert(original.self === original);
console.assert(clone.self === clone);
// They contain equivalent values:
console.assert(original.number === clone.number);
console.assert(Number(original.date) === Number(clone.date));
console.log("Assertions complete.");
};
main();
const structuredClone = obj => {
const oldState = history.state;
history.replaceState(obj, null);
const clonedObj = history.state;
history.replaceState(oldState, null);
return clonedObj;
};
雖然同步,但這可能非常慢。 它發生了所有與操縱瀏覽器歷史相關的頭部. 重複召喚這種方法可能會導致Chrome暫時變成無責任。
const structuredClone = obj => {
const n = new Notification('', {data: obj, silent: true});
n.onshow = n.close.bind(n);
return n.data;
};
这通常不是最有效的解决方案,但它是我需要的。
function clone(obj, clones) {
// Makes a deep copy of 'obj'. Handles cyclic structures by
// tracking cloned obj's in the 'clones' parameter. Functions
// are included, but not cloned. Functions members are cloned.
var new_obj,
already_cloned,
t = typeof obj,
i = 0,
l,
pair;
clones = clones || [];
if (obj === null) {
return obj;
}
if (t === "object" || t === "function") {
// check to see if we've already cloned obj
for (i = 0, l = clones.length; i < l; i++) {
pair = clones[i];
if (pair[0] === obj) {
already_cloned = pair[1];
break;
}
}
if (already_cloned) {
return already_cloned;
} else {
if (t === "object") { // create new object
new_obj = new obj.constructor();
} else { // Just use functions as is
new_obj = obj;
}
clones.push([obj, new_obj]); // keep track of objects we've cloned
for (key in obj) { // clone object members
if (obj.hasOwnProperty(key)) {
new_obj[key] = clone(obj[key], clones);
}
}
}
}
return new_obj || obj;
}
自行车测试...
a = []
a.push("b", "c", a)
aa = clone(a)
aa === a //=> false
aa[2] === a //=> false
aa[2] === a[2] //=> false
aa[2] === aa //=> true
功能测试...
f = new Function
f.a = a
ff = clone(f)
ff === f //=> true
ff.a === a //=> false
有很多答案,但没有一个给了我需要的效果,我想利用jQuery的深复制的力量......但是,当它进入一个序列时,它只是复制了对序列的参考,并深复制了其中内容。
(它甚至检查 kendo.data.ObservableArray 如果你想要它! 但是, 确保你打电话 kendo.observable(newItem) 如果你想 Arrays 再次可观察。
所以,要完全复制一个现有项目,你只是这样做:
var newItem = jQuery.extend(true, {}, oldItem);
createNewArrays(newItem);
function createNewArrays(obj) {
for (var prop in obj) {
if ((kendo != null && obj[prop] instanceof kendo.data.ObservableArray) || obj[prop] instanceof Array) {
var copy = [];
$.each(obj[prop], function (i, item) {
var newChild = $.extend(true, {}, item);
createNewArrays(newChild);
copy.push(newChild);
});
obj[prop] = copy;
}
}
}
对于想要使用 JSON.parse(JSON.stringify(obj)) 版本的人,但没有失去日期对象,您可以使用 Parse 方法的第二个论点将行转换为日期:
function clone(obj) { var regExp = /^\d{4}-\d{2}-\d{2}T\d{2}:\d{2}:\d{2}\.\d{3}Z$/; return JSON.parse(JSON.stringify(obj), function(k, v) { if (typeof v === 'string' && regExp.test(v)) return new Date(v) return v; }) } // usage: var original = { a: [1, null, undefined, 0, {a:null}, new Date()], b: { c(){ return 0 } } } var cloned = clone(original) console.log(cloned)