我试图在php中生成一个随机密码。

但是我得到的都是'a'返回类型是数组类型,我希望它是字符串。对如何修改代码有什么想法吗?

谢谢。

function randomPassword() {
    $alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, count($alphabet)-1);
        $pass[$i] = $alphabet[$n];
    }
    return $pass;
}

当前回答

快速。简单,干净和一致的格式,如果这是你想要的

$pw = chr(mt_rand(97,122)).mt_rand(0,9).chr(mt_rand(97,122)).mt_rand(10,99).chr(mt_rand(97,122)).mt_rand(100,999);

其他回答

该函数将根据参数中的规则生成密码

function random_password( $length = 8, $characters = true, $numbers = true, $case_sensitive = true, $hash = true ) {

    $password = '';

    if($characters)
    {
        $charLength = $length;
        if($numbers) $charLength-=2;
        if($case_sensitive) $charLength-=2;
        if($hash) $charLength-=2;
        $chars = "abcdefghijklmnopqrstuvwxyz";
        $password.= substr( str_shuffle( $chars ), 0, $charLength );
    }

    if($numbers)
    {
        $numbersLength = $length;
        if($characters) $numbersLength-=2;
        if($case_sensitive) $numbersLength-=2;
        if($hash) $numbersLength-=2;
        $chars = "0123456789";
        $password.= substr( str_shuffle( $chars ), 0, $numbersLength );
    }

    if($case_sensitive)
    {
        $UpperCaseLength = $length;
        if($characters) $UpperCaseLength-=2;
        if($numbers) $UpperCaseLength-=2;
        if($hash) $UpperCaseLength-=2;
        $chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
        $password.= substr( str_shuffle( $chars ), 0, $UpperCaseLength );
    }

    if($hash)
    {
        $hashLength = $length;
        if($characters) $hashLength-=2;
        if($numbers) $hashLength-=2;
        if($case_sensitive) $hashLength-=2;
        $chars = "!@#$%^&*()_-=+;:,.?";
        $password.= substr( str_shuffle( $chars ), 0, $hashLength );
    }

    $password = str_shuffle( $password );
    return $password;
}

一句话:

substr(str_shuffle('abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789') , 0 , 10 )
//define a function. It is only 3 lines!   
function generateRandomPassword($length = 5){
    $chars = "0123456789bcdfghjkmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ";
    return substr(str_shuffle($chars),0,$length);
}

//usage
echo generateRandomPassword(5); //random password legth: 5
echo generateRandomPassword(6); //random password legth: 6
echo generateRandomPassword(7); //random password legth: 7

安全警告:rand()不是一个加密安全的伪随机数生成器。在其他地方寻找在PHP中生成加密安全的伪随机字符串的方法。

试试这个(使用strlen而不是count,因为count在字符串上总是1):

function randomPassword() {
    $alphabet = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890';
    $pass = array(); //remember to declare $pass as an array
    $alphaLength = strlen($alphabet) - 1; //put the length -1 in cache
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, $alphaLength);
        $pass[] = $alphabet[$n];
    }
    return implode($pass); //turn the array into a string
}

Demo

这是基于本页的另一个答案,https://stackoverflow.com/a/21498316/525649

这个答案只生成十六进制字符,0-9,a-f。对于一些看起来不像hex的东西,试试这个:

str_shuffle(
  rtrim(
    base64_encode(bin2hex(openssl_random_pseudo_bytes(5))),
    '='
  ). 
  strtoupper(bin2hex(openssl_random_pseudo_bytes(7))).
  bin2hex(openssl_random_pseudo_bytes(13))
)

Base64_encode返回更广泛的字母数字字符 Rtrim有时会在结尾删除=

例子:

32 efvfgdg891be5e7293e54z1d23110m3zu3fmjb30z9a740ej0jz4 b280R72b48eOm77a25YCj093DE5d9549Gc73Jg8TdD9Z0Nj4b98760 051年b33654c0eg201cfw0e6na4b9614ze8d2fn49e12y0zy557aucb8 y67Q86ffd83G0z00M0Z152f7O2ADcY313gD7a774fc5FF069zdb5b7

对于为用户创建界面来说,这不是很可配置的,但对于某些目的来说,这是可以的。增加字符数,以弥补特殊字符的不足。