实现如下所示的状态栏:
[========== ] 45%
[================ ] 60%
[==========================] 100%
我想把这个打印到标准输出,并保持刷新,而不是打印到另一行。如何做到这一点?
实现如下所示的状态栏:
[========== ] 45%
[================ ] 60%
[==========================] 100%
我想把这个打印到标准输出,并保持刷新,而不是打印到另一行。如何做到这一点?
当前回答
如果你正在开发一个命令行界面,我建议你看看click,它非常好:
import click
import time
for filename in range(3):
with click.progressbar(range(100), fill_char='=', empty_char=' ') as bar:
for user in bar:
time.sleep(0.01)
下面是你得到的输出:
$ python test.py
[====================================] 100%
[====================================] 100%
[========= ] 27%
其他回答
在这里你可以使用以下代码作为函数:
def drawProgressBar(percent, barLen = 20):
sys.stdout.write("\r")
progress = ""
for i in range(barLen):
if i < int(barLen * percent):
progress += "="
else:
progress += " "
sys.stdout.write("[ %s ] %.2f%%" % (progress, percent * 100))
sys.stdout.flush()
使用.format:
def drawProgressBar(percent, barLen = 20):
# percent float from 0 to 1.
sys.stdout.write("\r")
sys.stdout.write("[{:<{}}] {:.0f}%".format("=" * int(barLen * percent), barLen, percent * 100))
sys.stdout.flush()
根据上面的答案和其他类似的关于CLI进度条的问题,我想我得到了一个普遍的答案。请登录https://stackoverflow.com/a/15860757/2254146查看。
下面是这个函数的一个副本,但是为了适合你的风格进行了修改:
import time, sys
# update_progress() : Displays or updates a console progress bar
## Accepts a float between 0 and 1. Any int will be converted to a float.
## A value under 0 represents a 'halt'.
## A value at 1 or bigger represents 100%
def update_progress(progress):
barLength = 20 # Modify this to change the length of the progress bar
status = ""
if isinstance(progress, int):
progress = float(progress)
if not isinstance(progress, float):
progress = 0
status = "error: progress var must be float\r\n"
if progress < 0:
progress = 0
status = "Halt...\r\n"
if progress >= 1:
progress = 1
status = "Done...\r\n"
block = int(round(barLength*progress))
text = "\rPercent: [{0}] {1}% {2}".format( "="*block + " "*(barLength-block), progress*100, status)
sys.stdout.write(text)
sys.stdout.flush()
看起来像
百分比:[====================]99.0%
正如Mark Rushakoff的解决方案中所描述的,您可以输出回车符sys.stdout.write('\r')来将光标重置到行首。要泛化该解决方案,同时实现Python 3的f- string,您可以使用
from time import sleep
import sys
n_bar = 50
iterable = range(33) # for demo purposes
n_iter = len(iterable)
for i, item in enumerate(iterable):
j = (i + 1) / n_iter
sys.stdout.write('\r')
sys.stdout.write(f"[{'=' * int(n_bar * j):{n_bar}s}] {int(100 * j)}%")
sys.stdout.flush()
sleep(0.05)
# do something with <item> here
根据Steven C. Howell对Mark Rushakoff回答的评论
j = (i + 1) / n
stdout.write('\r')
stdout.write('[%-20s] %d%%' % ('='*int(20*j), 100*j))
stdout.flush()
其中I是当前项目n是项目总数
如果你正在开发一个命令行界面,我建议你看看click,它非常好:
import click
import time
for filename in range(3):
with click.progressbar(range(100), fill_char='=', empty_char=' ') as bar:
for user in bar:
time.sleep(0.01)
下面是你得到的输出:
$ python test.py
[====================================] 100%
[====================================] 100%
[========= ] 27%