我想根据谓词筛选java.util.Collection。
当前回答
您确定要筛选Collection本身,而不是迭代器吗?
看到org.apache.commons.collections.iterators.FilterIterator
或者使用apache commons的第四版org.apache.commons.collections4.iterators.FilterIterator
其他回答
从java 9开始收集。启用过滤:
public static <T, A, R>
Collector<T, ?, R> filtering(Predicate<? super T> predicate,
Collector<? super T, A, R> downstream)
因此过滤应该是:
collection.stream().collect(Collectors.filtering(predicate, collector))
例子:
List<Integer> oddNumbers = List.of(1, 19, 15, 10, -10).stream()
.collect(Collectors.filtering(i -> i % 2 == 1, Collectors.toList()));
设置:
public interface Predicate<T> {
public boolean filter(T t);
}
void filterCollection(Collection<T> col, Predicate<T> predicate) {
for (Iterator i = col.iterator(); i.hasNext();) {
T obj = i.next();
if (predicate.filter(obj)) {
i.remove();
}
}
}
的用法:
List<MyObject> myList = ...;
filterCollection(myList, new Predicate<MyObject>() {
public boolean filter(MyObject obj) {
return obj.shouldFilter();
}
});
我写了一个扩展的Iterable类,它支持在不复制集合内容的情况下应用函数式算法。
用法:
List<Integer> myList = new ArrayList<Integer>(){ 1, 2, 3, 4, 5 }
Iterable<Integer> filtered = Iterable.wrap(myList).select(new Predicate1<Integer>()
{
public Boolean call(Integer n) throws FunctionalException
{
return n % 2 == 0;
}
})
for( int n : filtered )
{
System.out.println(n);
}
上面的代码将实际执行
for( int n : myList )
{
if( n % 2 == 0 )
{
System.out.println(n);
}
}
我需要根据列表中已经存在的值来筛选列表。例如,删除后面小于当前值的所有值。{2 5 3 4 7 5} ->{2 5 7}。或者例如删除所有重复项{3 5 4 2 3 5 6}->{3 5 4 2 6}。
public class Filter {
public static <T> void List(List<T> list, Chooser<T> chooser) {
List<Integer> toBeRemoved = new ArrayList<>();
leftloop:
for (int right = 1; right < list.size(); ++right) {
for (int left = 0; left < right; ++left) {
if (toBeRemoved.contains(left)) {
continue;
}
Keep keep = chooser.choose(list.get(left), list.get(right));
switch (keep) {
case LEFT:
toBeRemoved.add(right);
continue leftloop;
case RIGHT:
toBeRemoved.add(left);
break;
case NONE:
toBeRemoved.add(left);
toBeRemoved.add(right);
continue leftloop;
}
}
}
Collections.sort(toBeRemoved, new Comparator<Integer>() {
@Override
public int compare(Integer o1, Integer o2) {
return o2 - o1;
}
});
for (int i : toBeRemoved) {
if (i >= 0 && i < list.size()) {
list.remove(i);
}
}
}
public static <T> void List(List<T> list, Keeper<T> keeper) {
Iterator<T> iterator = list.iterator();
while (iterator.hasNext()) {
if (!keeper.keep(iterator.next())) {
iterator.remove();
}
}
}
public interface Keeper<E> {
boolean keep(E obj);
}
public interface Chooser<E> {
Keep choose(E left, E right);
}
public enum Keep {
LEFT, RIGHT, BOTH, NONE;
}
}
这将被这样使用。
List<String> names = new ArrayList<>();
names.add("Anders");
names.add("Stefan");
names.add("Anders");
Filter.List(names, new Filter.Chooser<String>() {
@Override
public Filter.Keep choose(String left, String right) {
return left.equals(right) ? Filter.Keep.LEFT : Filter.Keep.BOTH;
}
});
https://code.google.com/p/joquery/
支持不同的可能性,
给定的集合,
Collection<Dto> testList = new ArrayList<>();
的类型,
class Dto
{
private int id;
private String text;
public int getId()
{
return id;
}
public int getText()
{
return text;
}
}
过滤器
Java 7
Filter<Dto> query = CQ.<Dto>filter(testList)
.where()
.property("id").eq().value(1);
Collection<Dto> filtered = query.list();
Java 8
Filter<Dto> query = CQ.<Dto>filter(testList)
.where()
.property(Dto::getId)
.eq().value(1);
Collection<Dto> filtered = query.list();
同时,
Filter<Dto> query = CQ.<Dto>filter()
.from(testList)
.where()
.property(Dto::getId).between().value(1).value(2)
.and()
.property(Dto::grtText).in().value(new string[]{"a","b"});
排序(也可用于Java 7)
Filter<Dto> query = CQ.<Dto>filter(testList)
.orderBy()
.property(Dto::getId)
.property(Dto::getName)
Collection<Dto> sorted = query.list();
分组(也可用于Java 7)
GroupQuery<Integer,Dto> query = CQ.<Dto,Dto>query(testList)
.group()
.groupBy(Dto::getId)
Collection<Grouping<Integer,Dto>> grouped = query.list();
连接(也可用于Java 7)
考虑到,
class LeftDto
{
private int id;
private String text;
public int getId()
{
return id;
}
public int getText()
{
return text;
}
}
class RightDto
{
private int id;
private int leftId;
private String text;
public int getId()
{
return id;
}
public int getLeftId()
{
return leftId;
}
public int getText()
{
return text;
}
}
class JoinedDto
{
private int leftId;
private int rightId;
private String text;
public JoinedDto(int leftId,int rightId,String text)
{
this.leftId = leftId;
this.rightId = rightId;
this.text = text;
}
public int getLeftId()
{
return leftId;
}
public int getRightId()
{
return rightId;
}
public int getText()
{
return text;
}
}
Collection<LeftDto> leftList = new ArrayList<>();
Collection<RightDto> rightList = new ArrayList<>();
可以像这样连接,
Collection<JoinedDto> results = CQ.<LeftDto, LeftDto>query().from(leftList)
.<RightDto, JoinedDto>innerJoin(CQ.<RightDto, RightDto>query().from(rightList))
.on(LeftFyo::getId, RightDto::getLeftId)
.transformDirect(selection -> new JoinedDto(selection.getLeft().getText()
, selection.getLeft().getId()
, selection.getRight().getId())
)
.list();
表达式
Filter<Dto> query = CQ.<Dto>filter()
.from(testList)
.where()
.exec(s -> s.getId() + 1).eq().value(2);
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