我知道下面是不可能的,因为枚举的类型必须是int

enum GroupTypes
{
    TheGroup = "OEM",
    TheOtherGroup = "CMB"
}

从我的数据库中,我得到了一个不全面的代码字段(OEM和CMBs)。我想让这个字段成为一个枚举或其他可以理解的东西。因为如果目标是可读性,解决方案就应该简洁。

我还有其他选择吗?


当前回答

根据其他人的意见,这是我想到的。这种方法避免了在想要获得常量值的地方键入. value。

我有一个基类的所有字符串枚举像这样:

using System;
using Newtonsoft.Json;

[JsonConverter(typeof(ConstantConverter))]
public class StringEnum: IConvertible
{
    public string Value { get; set; }

    protected StringEnum(string value)
    {
        Value = value;
    }

    public static implicit operator string(StringEnum c)
    {
        return c.Value;
    }
    public string ToString(IFormatProvider provider)
    {
        return Value;
    }

    public TypeCode GetTypeCode()
    {
        throw new NotImplementedException();
    }

    public bool ToBoolean(IFormatProvider provider)
    {
        throw new NotImplementedException();
    }
    //The same for all the rest of IConvertible methods
}

JsonConverter是这样的:

using System;
using Newtonsoft.Json;

class ConstantConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return true;
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        if (value == null)
        {
            serializer.Serialize(writer, null);
        }
        else
        {
            serializer.Serialize(writer, value.ToString());
        }
    }
}

一个实际的string enum是这样的:

public sealed class Colors : StringEnum
{
    public static Colors Red { get { return new Catalog("Red"); } }
    public static Colors Yellow { get { return new Catalog("Yellow"); } }
    public static Colors White { get { return new Catalog("White"); } }

    private Colors(string value) : base(value) { }
}

有了这个,你可以使用颜色。红色甚至序列化到json而不使用Value属性

其他回答

您可以使用两个枚举。一个用于数据库,另一个用于可读性。

你只需要确保它们保持同步,这似乎是一个小成本。 你不必设置值,只是设置相同的位置,但设置值可以非常清楚地表明两个枚举是相关的,并防止错误重新排列枚举成员。注释让维护人员知道这些是相关的,必须保持同步。

// keep in sync with GroupTypes
public enum GroupTypeCodes
{
    OEM,
    CMB
}

// keep in sync with GroupTypesCodes
public enum GroupTypes
{
    TheGroup = GroupTypeCodes.OEM,
    TheOtherGroup = GroupTypeCodes.CMB
}

要使用它,你只需要先转换为代码:

GroupTypes myGroupType = GroupTypes.TheGroup;
string valueToSaveIntoDatabase = ((GroupTypeCodes)myGroupType).ToString();

然后,如果你想让它更方便,你可以添加一个扩展函数,只适用于这种类型的枚举:

public static string ToString(this GroupTypes source)
{
    return ((GroupTypeCodes)source).ToString();
}

然后你可以这样做:

GroupTypes myGroupType = GroupTypes.TheGroup;
string valueToSaveIntoDatabase = myGroupType.ToString();

使用类。

编辑:更好的例子

class StarshipType
{
    private string _Name;
    private static List<StarshipType> _StarshipTypes = new List<StarshipType>();

    public static readonly StarshipType Ultralight = new StarshipType("Ultralight");
    public static readonly StarshipType Light = new StarshipType("Light");
    public static readonly StarshipType Mediumweight = new StarshipType("Mediumweight");
    public static readonly StarshipType Heavy = new StarshipType("Heavy");
    public static readonly StarshipType Superheavy = new StarshipType("Superheavy");

    public string Name
    {
        get { return _Name; }
        private set { _Name = value; }
    }

    public static IList<StarshipType> StarshipTypes
    {
        get { return _StarshipTypes; }
    }

    private StarshipType(string name, int systemRatio)
    {
        Name = name;
        _StarshipTypes.Add(this);
    }

    public static StarshipType Parse(string toParse)
    {
        foreach (StarshipType s in StarshipTypes)
        {
            if (toParse == s.Name)
                return s;
        }
        throw new FormatException("Could not parse string.");
    }
}

Glennular Extension方法的一个小调整,所以你可以在其他东西上使用扩展,而不仅仅是ENUM的;

using System;
using System.ComponentModel;
namespace Extensions {
    public static class T_Extensions {
        /// <summary>
        /// Gets the Description Attribute Value
        /// </summary>
        /// <typeparam name="T">Entity Type</typeparam>
        /// <param name="val">Variable</param>
        /// <returns>The value of the Description Attribute or an Empty String</returns>
        public static string Description<T>(this T t) {
            DescriptionAttribute[] attributes = (DescriptionAttribute[])t.GetType().GetField(t.ToString()).GetCustomAttributes(typeof(DescriptionAttribute), false);
            return attributes.Length > 0 ? attributes[0].Description : string.Empty;
        }
    }
}

或者使用Linq

using System;
using System.ComponentModel;
using System.Linq;

namespace Extensions {


public static class T_Extensions {
        public static string Description<T>(this T t) =>
            ((DescriptionAttribute[])t
            ?.GetType()
            ?.GetField(t?.ToString())
            ?.GetCustomAttributes(typeof(DescriptionAttribute), false))
            ?.Select(a => a?.Description)
            ?.FirstOrDefault() 
            ?? string.Empty;  
    }
}

我要分享一个不同的答案。我想发送一个字符串来返回一个字符串。例如:Airport = A, Railway = R。

public enum LocationType
    {
        AIRPORT = 1,
        RAILWAY = 2,
        DOWNTOWN = 3
    }
    
public enum ShortLocationType
    {
        A = 1,
        R = 2,
        D = 3
    }

((ShortLocationType)(int)Enum.Parse(typeof(LocationType), "AIRPORT")).ToString();

输出“”

((ShortLocationType)(int)Enum.Parse(typeof(LocationType), "DOWNTOWN")).ToString();

输出“D”

我使用了在之前的回答中提到的结构,但去掉了任何复杂性。对我来说,这就像创建一个字符串枚举。它的使用方式与枚举的使用方式相同。

    struct ViewTypes
    {
        public const string View1 = "Whatever string you like";
        public const string View2 = "another string";
    }

使用示例:

   switch( some_string_variable )
   {
      case ViewTypes.View1: /* do something */ break;
      case ViewTypes.View2: /* do something else */ break;
   }