我知道下面是不可能的,因为枚举的类型必须是int

enum GroupTypes
{
    TheGroup = "OEM",
    TheOtherGroup = "CMB"
}

从我的数据库中,我得到了一个不全面的代码字段(OEM和CMBs)。我想让这个字段成为一个枚举或其他可以理解的东西。因为如果目标是可读性,解决方案就应该简洁。

我还有其他选择吗?


当前回答

如果不是你的枚举的所有值都有一个字符串,如果你想稍后设置这些值,我使用如下类:

 public class SessionResoult
{
    public enum SessionResoultType
    {
        Success,
        Error,
    }
    public SessionResoult(SessionResoultType sesionResoultType, string value = null)
    {
        Type = sesionResoultType;
        Value = value;
       
    }

    public SessionResoultType Type { get; set; }

    public string Value { get; private set; }
  

    public sealed class Success : SessionResoult
    {
        public Success() : base(SessionResoultType.Success) { }
    }

    public sealed class Error : SessionResoult
    {
        public Error(string value) : base(SessionResoultType.Error, value) { }
    }

    public override string ToString()
    {
        if(this is Success)
        {
            return (SessionResoultType.Success.ToString());
        }else if(this is Error)
        {
            return $"{SessionResoultType.Error}:{this.Value}";
        }
        else { return base.ToString(); }
    }

}

使用的例子:

private SessionResoult ok = new SessionResoult. success ();private SessionResoult错误=新的SessionResoult。错误(“没有可用的网络”);

其他回答

我使用了在之前的回答中提到的结构,但去掉了任何复杂性。对我来说,这就像创建一个字符串枚举。它的使用方式与枚举的使用方式相同。

    struct ViewTypes
    {
        public const string View1 = "Whatever string you like";
        public const string View2 = "another string";
    }

使用示例:

   switch( some_string_variable )
   {
      case ViewTypes.View1: /* do something */ break;
      case ViewTypes.View2: /* do something else */ break;
   }

下面是我对这个问题的看法,使用c# 9.0语法来保持整洁。我为枚举定义了一个基类:

public class StringEnum
{
    protected StringEnum(string value) { Value = value; }
    public string Value { get; }
    public override string ToString() => Value;
}

创建新的枚举样式类型是简单而紧凑的:

public class GroupTypes : StringEnum
{ 
    private GroupTypes(string value) : base(value) {}

    public static readonly GroupTypes TheGroup = new("OEM");
    public static readonly GroupTypes TheOtherGroup = new("CMB");
}

像这样使用它:

void Example(GroupTypes groupType)
{
    Console.WriteLine(groupType); // Will print "OEM" or "CMB"
    if (groupType == GroupTypes.TheGroup) { ... }
}

你也可以给StringEnum添加更多的功能,这样你的所有子类都可以使用(例如,实现IComparable和重写Equals和GetHashCode)

基于https://stackoverflow.com/a/1343517/1818723,我提出了一个枚举与TryParse方法

public class FancyStringEnum
{
    private FancyStringEnum(string value) { Value = value; }

    public string Value { get; private set; }

    private static List<FancyStringEnum> choices = new List<FancyStringEnum>
    {
        new FancyStringEnum("Small") ,
        new FancyStringEnum("Big Thing") ,
        new FancyStringEnum("Value with Spaces")
    };

    public static FancyStringEnum Small { get { return choices[0]; } }
    public static FancyStringEnum BigThing { get { return choices[1]; } }
    public static FancyStringEnum ValueWithSpaces { get { return choices[2]; } }

    public override string ToString()
    {
        return Value;
    }

    public static bool TryParse(string value, bool ignoreCase, out FancyStringEnum result)
    {
        var sc = StringComparison.InvariantCulture;
        if (ignoreCase)
            sc = StringComparison.InvariantCultureIgnoreCase;

        foreach (var choice in choices)
        {

            if (choice.Value.Equals(value, sc))
            {
                result = choice;
                return true;
            }
        }

        result = new FancyStringEnum(null);
        return false;
    }

    public static FancyStringEnum Parse(string value, bool ignoreCase)
    {
        var sc = StringComparison.InvariantCulture;
        if (ignoreCase)
            sc = StringComparison.InvariantCultureIgnoreCase;

        foreach (var choice in choices)
        {

            if (choice.Value.Equals(value, sc))
            {
                return choice;
            }
        }

        return new FancyStringEnum(null);
    }
}

传入类型安全的字符串值作为参数:

public static void Do(string message, FancyStringEnum value)
{
    if (value == FancyStringEnum.Small)
    {
        //do something
    } else if (value == FancyStringEnum.BigThing)
    {
        //do something else
    }
}

TryParse和Parse在行动:

string something = "something"; //substiture with "small" to see it parsed 
if (FancyStringEnum.TryParse(something, true, out var se))
    Console.WriteLine(se.Value);
else
    Console.WriteLine($"unable to parse {something}");

//or    

var v2 = FancyStringEnum.Parse(something, true);
if (v2.Value == null)
    Console.WriteLine($"unable to parse {something}");
else
    Console.WriteLine(v2.Value); //do something with parsed enum

    

是否可以提取基类,用更少的代码创建StringEnums

我基本上是在寻找@ArthurC的反思答案

稍微扩展一下他的回答,你可以通过一个泛型函数来让它更好:

    // If you want for a specific Enum
    private static string EnumStringValue(GroupTypes e)
    {
        return EnumStringValue<GroupTypes>(e);
    }

    // Generic
    private static string EnumStringValue<T>(T enumInstance)
    {
        return Enum.GetName(typeof(T), enumInstance);
    } 

然后你就可以把你有的东西都包起来了

EnumStringValue(GroupTypes.TheGroup) // if you incorporate the top part

or

EnumStringValue<GroupTypes>(GroupTypes.TheGroup) // if you just use the generic

使用类。

编辑:更好的例子

class StarshipType
{
    private string _Name;
    private static List<StarshipType> _StarshipTypes = new List<StarshipType>();

    public static readonly StarshipType Ultralight = new StarshipType("Ultralight");
    public static readonly StarshipType Light = new StarshipType("Light");
    public static readonly StarshipType Mediumweight = new StarshipType("Mediumweight");
    public static readonly StarshipType Heavy = new StarshipType("Heavy");
    public static readonly StarshipType Superheavy = new StarshipType("Superheavy");

    public string Name
    {
        get { return _Name; }
        private set { _Name = value; }
    }

    public static IList<StarshipType> StarshipTypes
    {
        get { return _StarshipTypes; }
    }

    private StarshipType(string name, int systemRatio)
    {
        Name = name;
        _StarshipTypes.Add(this);
    }

    public static StarshipType Parse(string toParse)
    {
        foreach (StarshipType s in StarshipTypes)
        {
            if (toParse == s.Name)
                return s;
        }
        throw new FormatException("Could not parse string.");
    }
}