我知道下面是不可能的,因为枚举的类型必须是int
enum GroupTypes
{
TheGroup = "OEM",
TheOtherGroup = "CMB"
}
从我的数据库中,我得到了一个不全面的代码字段(OEM和CMBs)。我想让这个字段成为一个枚举或其他可以理解的东西。因为如果目标是可读性,解决方案就应该简洁。
我还有其他选择吗?
我知道下面是不可能的,因为枚举的类型必须是int
enum GroupTypes
{
TheGroup = "OEM",
TheOtherGroup = "CMB"
}
从我的数据库中,我得到了一个不全面的代码字段(OEM和CMBs)。我想让这个字段成为一个枚举或其他可以理解的东西。因为如果目标是可读性,解决方案就应该简洁。
我还有其他选择吗?
当前回答
如果不是你的枚举的所有值都有一个字符串,如果你想稍后设置这些值,我使用如下类:
public class SessionResoult
{
public enum SessionResoultType
{
Success,
Error,
}
public SessionResoult(SessionResoultType sesionResoultType, string value = null)
{
Type = sesionResoultType;
Value = value;
}
public SessionResoultType Type { get; set; }
public string Value { get; private set; }
public sealed class Success : SessionResoult
{
public Success() : base(SessionResoultType.Success) { }
}
public sealed class Error : SessionResoult
{
public Error(string value) : base(SessionResoultType.Error, value) { }
}
public override string ToString()
{
if(this is Success)
{
return (SessionResoultType.Success.ToString());
}else if(this is Error)
{
return $"{SessionResoultType.Error}:{this.Value}";
}
else { return base.ToString(); }
}
}
使用的例子:
private SessionResoult ok = new SessionResoult. success ();private SessionResoult错误=新的SessionResoult。错误(“没有可用的网络”);
其他回答
我使用了在之前的回答中提到的结构,但去掉了任何复杂性。对我来说,这就像创建一个字符串枚举。它的使用方式与枚举的使用方式相同。
struct ViewTypes
{
public const string View1 = "Whatever string you like";
public const string View2 = "another string";
}
使用示例:
switch( some_string_variable )
{
case ViewTypes.View1: /* do something */ break;
case ViewTypes.View2: /* do something else */ break;
}
下面是我对这个问题的看法,使用c# 9.0语法来保持整洁。我为枚举定义了一个基类:
public class StringEnum
{
protected StringEnum(string value) { Value = value; }
public string Value { get; }
public override string ToString() => Value;
}
创建新的枚举样式类型是简单而紧凑的:
public class GroupTypes : StringEnum
{
private GroupTypes(string value) : base(value) {}
public static readonly GroupTypes TheGroup = new("OEM");
public static readonly GroupTypes TheOtherGroup = new("CMB");
}
像这样使用它:
void Example(GroupTypes groupType)
{
Console.WriteLine(groupType); // Will print "OEM" or "CMB"
if (groupType == GroupTypes.TheGroup) { ... }
}
你也可以给StringEnum添加更多的功能,这样你的所有子类都可以使用(例如,实现IComparable和重写Equals和GetHashCode)
基于https://stackoverflow.com/a/1343517/1818723,我提出了一个枚举与TryParse方法
public class FancyStringEnum
{
private FancyStringEnum(string value) { Value = value; }
public string Value { get; private set; }
private static List<FancyStringEnum> choices = new List<FancyStringEnum>
{
new FancyStringEnum("Small") ,
new FancyStringEnum("Big Thing") ,
new FancyStringEnum("Value with Spaces")
};
public static FancyStringEnum Small { get { return choices[0]; } }
public static FancyStringEnum BigThing { get { return choices[1]; } }
public static FancyStringEnum ValueWithSpaces { get { return choices[2]; } }
public override string ToString()
{
return Value;
}
public static bool TryParse(string value, bool ignoreCase, out FancyStringEnum result)
{
var sc = StringComparison.InvariantCulture;
if (ignoreCase)
sc = StringComparison.InvariantCultureIgnoreCase;
foreach (var choice in choices)
{
if (choice.Value.Equals(value, sc))
{
result = choice;
return true;
}
}
result = new FancyStringEnum(null);
return false;
}
public static FancyStringEnum Parse(string value, bool ignoreCase)
{
var sc = StringComparison.InvariantCulture;
if (ignoreCase)
sc = StringComparison.InvariantCultureIgnoreCase;
foreach (var choice in choices)
{
if (choice.Value.Equals(value, sc))
{
return choice;
}
}
return new FancyStringEnum(null);
}
}
传入类型安全的字符串值作为参数:
public static void Do(string message, FancyStringEnum value)
{
if (value == FancyStringEnum.Small)
{
//do something
} else if (value == FancyStringEnum.BigThing)
{
//do something else
}
}
TryParse和Parse在行动:
string something = "something"; //substiture with "small" to see it parsed
if (FancyStringEnum.TryParse(something, true, out var se))
Console.WriteLine(se.Value);
else
Console.WriteLine($"unable to parse {something}");
//or
var v2 = FancyStringEnum.Parse(something, true);
if (v2.Value == null)
Console.WriteLine($"unable to parse {something}");
else
Console.WriteLine(v2.Value); //do something with parsed enum
是否可以提取基类,用更少的代码创建StringEnums
我基本上是在寻找@ArthurC的反思答案
稍微扩展一下他的回答,你可以通过一个泛型函数来让它更好:
// If you want for a specific Enum
private static string EnumStringValue(GroupTypes e)
{
return EnumStringValue<GroupTypes>(e);
}
// Generic
private static string EnumStringValue<T>(T enumInstance)
{
return Enum.GetName(typeof(T), enumInstance);
}
然后你就可以把你有的东西都包起来了
EnumStringValue(GroupTypes.TheGroup) // if you incorporate the top part
or
EnumStringValue<GroupTypes>(GroupTypes.TheGroup) // if you just use the generic
使用类。
编辑:更好的例子
class StarshipType
{
private string _Name;
private static List<StarshipType> _StarshipTypes = new List<StarshipType>();
public static readonly StarshipType Ultralight = new StarshipType("Ultralight");
public static readonly StarshipType Light = new StarshipType("Light");
public static readonly StarshipType Mediumweight = new StarshipType("Mediumweight");
public static readonly StarshipType Heavy = new StarshipType("Heavy");
public static readonly StarshipType Superheavy = new StarshipType("Superheavy");
public string Name
{
get { return _Name; }
private set { _Name = value; }
}
public static IList<StarshipType> StarshipTypes
{
get { return _StarshipTypes; }
}
private StarshipType(string name, int systemRatio)
{
Name = name;
_StarshipTypes.Add(this);
}
public static StarshipType Parse(string toParse)
{
foreach (StarshipType s in StarshipTypes)
{
if (toParse == s.Name)
return s;
}
throw new FormatException("Could not parse string.");
}
}