我想我应该把这个片段放在这里:

确保声明了对UITextViewDelegate协议的支持。

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {

    if([text isEqualToString:@"\n"]) {
        [textView resignFirstResponder];
        return NO;
    }

    return YES;
}

Swift 4.0更新:

func textView(_ textView: UITextView, shouldChangeTextIn range: NSRange, replacementText text: String) -> Bool {
    if text == "\n" {
        textView.resignFirstResponder()
        return false
    }
    return true
}

在视图控制器中添加这个方法。

迅速:

func textView(textView: UITextView, shouldChangeTextInRange range: NSRange, replacementText text: String) -> Bool {
    if text == "\n" {
        textView.resignFirstResponder()
        return false
    }
    return true
}

这个方法对你也有帮助:

/**
Dismiss keyboard when tapped outside the keyboard or textView

:param: touches the touches
:param: event   the related event
*/
override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
    if let touch = touches.anyObject() as? UITouch {
        if touch.phase == UITouchPhase.Began {
            textField?.resignFirstResponder()
        }
    }
}

就像matt对samvermette的评论一样，我也不喜欢检测“\n”的想法。返回键在UITextView中是有原因的，当然是去下一行。

在我看来，最好的解决方案是模仿iPhone的消息应用程序-这是在键盘上添加工具栏(和按钮)。

我从以下博客文章中得到了代码:

http://www.iosdevnotes.com/2011/02/iphone-keyboard-toolbar/

步骤:

-添加工具栏到你的XIB文件-设置高度为460

-添加工具栏按钮项(如果尚未添加)。如果需要右对齐，还可以将灵活的工具栏按钮项添加到XIB，并移动工具栏按钮项

-创建将按钮项目链接到resignFirstResponder的动作，如下所示:

- (IBAction)hideKeyboard:(id)sender {
    [yourUITextView resignFirstResponder];
}

套:

- (void)viewWillAppear:(BOOL)animated {
    [super viewWillAppear:animated];

    [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(keyboardWillShow:) name:UIKeyboardWillShowNotification object:nil];
    [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(keyboardWillHide:) name:UIKeyboardWillHideNotification object:nil];
}

- (void)viewWillDisappear:(BOOL)animated {
    [super viewWillDisappear:animated];

    [[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillShowNotification object:nil];
    [[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillHideNotification object:nil];
}

- (void)keyboardWillShow:(NSNotification *)notification {
    [UIView beginAnimations:nil context:NULL];
    [UIView setAnimationDuration:0.3];

    CGRect frame = self.keyboardToolbar.frame;
    frame.origin.y = self.view.frame.size.height - 260.0;
    self.keyboardToolbar.frame = frame;

    [UIView commitAnimations];
}

- (void)keyboardWillHide:(NSNotification *)notification {
    [UIView beginAnimations:nil context:NULL];
    [UIView setAnimationDuration:0.3];

    CGRect frame = self.keyboardToolbar.frame;
    frame.origin.y = self.view.frame.size.height;
    self.keyboardToolbar.frame = frame;

    [UIView commitAnimations];
}

-(BOOL)textFieldShouldReturn:(UITextField *)textField; // called from textfield (keyboard)

-(BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text; // good tester function - thanks

函数hideQueboard。

- (void)HideQueyboard
{
    [[UIApplication sharedApplication] sendAction:@selector(resignFirstResponder)   to:nil from:nil forEvent:nil];
}

我知道这个问题已经被回答过很多次了，但下面是我对这个问题的看法。

我发现samvermette和ribeto的回答非常有用，还有maxpower在ribeto的回答中的评论。但这些方法存在一个问题。matt在samvermette的回答中提到的问题是，如果用户想要在其中粘贴带有换行符的东西，键盘将隐藏而不粘贴任何东西。

所以我的方法是上述三种解决方案的混合，只有检查输入的字符串是否为新行，当字符串的长度为1时，我们确保用户是键入而不是粘贴。

以下是我所做的:

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {
    NSRange resultRange = [text rangeOfCharacterFromSet:[NSCharacterSet newlineCharacterSet] options:NSBackwardsSearch];
    if ([text length] == 1 && resultRange.location != NSNotFound) {
        [textView resignFirstResponder];
        return NO;
    }

    return YES;
}