如何将整个输入流读到字节数组?


当前回答

Input Stream is ...
ByteArrayOutputStream bos = new ByteArrayOutputStream();
int next = in.read();
while (next > -1) {
    bos.write(next);
    next = in.read();
}
bos.flush();
byte[] result = bos.toByteArray();
bos.close();

其他回答

我知道已经太迟了,但我认为这里有更清晰的解决方案,更易于阅读……

/**
 * method converts {@link InputStream} Object into byte[] array.
 * 
 * @param stream the {@link InputStream} Object.
 * @return the byte[] array representation of received {@link InputStream} Object.
 * @throws IOException if an error occurs.
 */
public static byte[] streamToByteArray(InputStream stream) throws IOException {

    byte[] buffer = new byte[1024];
    ByteArrayOutputStream os = new ByteArrayOutputStream();

    int line = 0;
    // read bytes from stream, and store them in buffer
    while ((line = stream.read(buffer)) != -1) {
        // Writes bytes from byte array (buffer) into output stream.
        os.write(buffer, 0, line);
    }
    stream.close();
    os.flush();
    os.close();
    return os.toByteArray();
}

这是我的复制粘贴版本:

@SuppressWarnings("empty-statement")
public static byte[] inputStreamToByte(InputStream is) throws IOException {
    if (is == null) {
        return null;
    }
    // Define a size if you have an idea of it.
    ByteArrayOutputStream r = new ByteArrayOutputStream(2048);
    byte[] read = new byte[512]; // Your buffer size.
    for (int i; -1 != (i = is.read(read)); r.write(read, 0, i));
    is.close();
    return r.toByteArray();
}

你可以完全避免缓冲。

从http://www.exampledepot.com/egs/java.io/File2ByteArray.html复制的代码(是的,它非常冗长,但需要的内存大小是其他解决方案的一半)。

// Returns the contents of the file in a byte array.
public static byte[] getBytesFromFile(File file) throws IOException {
    InputStream is = new FileInputStream(file);

    // Get the size of the file
    long length = file.length();

    // You cannot create an array using a long type.
    // It needs to be an int type.
    // Before converting to an int type, check
    // to ensure that file is not larger than Integer.MAX_VALUE.
    if (length > Integer.MAX_VALUE) {
        // File is too large
    }

    // Create the byte array to hold the data
    byte[] bytes = new byte[(int)length];

    // Read in the bytes
    int offset = 0;
    int numRead = 0;
    while (offset < bytes.length
           && (numRead=is.read(bytes, offset, bytes.length-offset)) >= 0) {
        offset += numRead;
    }

    // Ensure all the bytes have been read in
    if (offset < bytes.length) {
        throw new IOException("Could not completely read file "+file.getName());
    }

    // Close the input stream and return bytes
    is.close();
    return bytes;
}

你真的需要图像作为字节[]吗?你在字节[]中到底期望什么-图像文件的完整内容,以图像文件的任何格式编码,或RGB像素值?

这里的其他答案向您展示了如何将文件读入字节[]。您的字节[]将包含文件的确切内容,并且您需要对其进行解码才能对图像数据进行处理。

用于读取(和写入)图像的Java标准API是ImageIO API,您可以在javax.imageio包中找到它。你可以用一行代码从文件中读入一张图片:

BufferedImage image = ImageIO.read(new File("image.jpg"));

这将给您一个BufferedImage,而不是一个字节[]。要获取图像数据,可以在BufferedImage上调用getRaster()。这将为您提供一个光栅对象,该对象具有访问像素数据的方法(它有几个getPixel() / getPixels()方法)。

查找javax.imageio的API文档。ImageIO java.awt.image。BufferedImage, java。awt。image。raster等等。

ImageIO默认支持多种图像格式:JPEG, PNG, BMP, WBMP和GIF。可以添加对更多格式的支持(您需要一个实现ImageIO服务提供程序接口的插件)。

另请参阅下面的教程:使用图像

我试图编辑@numan的答案,修复了写垃圾数据,但编辑被拒绝。虽然这段简短的代码并不出色,但我看不到其他更好的答案。以下是我认为最有意义的建议:

ByteArrayOutputStream out = new ByteArrayOutputStream();
byte[] buffer = new byte[1024]; // you can configure the buffer size
int length;

while ((length = in.read(buffer)) != -1) out.write(buffer, 0, length); //copy streams
in.close(); // call this in a finally block

byte[] result = out.toByteArray();

ByteArrayOutputStream不需要关闭。为了可读性,省略了一些结构