如何使用JavaScript检查/不检查复选框?


当前回答

对于单个检查,请尝试

myCheckBox.checked = 1 <input type="checkbox" id="myCheckBox">给她打电话

对于多重尝试

document.querySelectorAll(“.imChecked”)。forEach (c = > c.checked = 1) 买酒:<input type="checkbox" class="imChecked"><br> 播放流畅的爵士音乐:<input type="checkbox"><br> 剃须:<input type="checkbox" class="imChecked"><br>

其他回答

Javascript:

// Check
document.getElementById("checkbox").checked = true;

// Uncheck
document.getElementById("checkbox").checked = false;

jQuery 1.6 (+):

// Check
$("#checkbox").prop("checked", true);

// Uncheck
$("#checkbox").prop("checked", false);

jQuery (1.5 -):

// Check
$("#checkbox").attr("checked", true);

// Uncheck
$("#checkbox").attr("checked", false);
<script type="text/javascript">
    $(document).ready(function () {
        $('.selecctall').click(function (event) {
            if (this.checked) {
                $('.checkbox1').each(function () {
                    this.checked = true;
                });
            } else {
                $('.checkbox1').each(function () {
                    this.checked = false;
                });
            }
        });

    });

</script>

试试这个:

//Check
document.getElementById('checkbox').setAttribute('checked', 'checked');

//UnCheck
document.getElementById('chk').removeAttribute('checked');

使用vanilla js:

//for one element: 
document.querySelector('.myCheckBox').checked = true  //will select the first matched element
document.querySelector('.myCheckBox').checked = false//will unselect the first matched element

//for multiple elements:
for (const checkbox of document.querySelectorAll('.myCheckBox')) {
//iterating over all matched elements

checkbox.checked = true //for selection
checkbox.checked = false //for unselection
}
function setCheckboxValue(checkbox,value) {
    if (checkbox.checked!=value)
        checkbox.click();
}