我有一个用Python编写的应用程序,它是由相当专业的观众(科学家)使用的。

我正在寻找一个好方法,使应用程序可扩展的用户,即脚本/插件架构。

I am looking for something extremely lightweight. Most scripts, or plugins, are not going to be developed and distributed by a third-party and installed, but are going to be something whipped up by a user in a few minutes to automate a repeating task, add support for a file format, etc. So plugins should have the absolute minimum boilerplate code, and require no 'installation' other than copying to a folder (so something like setuptools entry points, or the Zope plugin architecture seems like too much.)

是否已经有类似的系统存在,或者是否有项目实现了类似的方案,我应该看看想法/灵感?


当前回答

实际上,setuptools工作在一个“插件目录”下,下面的例子摘自项目文档: http://peak.telecommunity.com/DevCenter/PkgResources#locating-plugins

使用示例:

plugin_dirs = ['foo/plugins'] + sys.path
env = Environment(plugin_dirs)
distributions, errors = working_set.find_plugins(env)
map(working_set.add, distributions)  # add plugins+libs to sys.path
print("Couldn't load plugins due to: %s" % errors)

从长远来看,setuptools是一个更安全的选择,因为它可以加载插件而不会发生冲突或丢失需求。

另一个好处是插件本身可以使用相同的机制进行扩展,而无需原始应用程序关心它。

其他回答

我的是,基本上,一个名为“plugins”的目录,主应用程序可以轮询,然后使用imp.load_module来拾取文件,寻找一个已知的入口点,可能是模块级配置参数,然后从那里开始。我使用文件监控的东西来实现一定程度的动态,其中插件是活跃的,但这是一个很好的拥有。

当然,任何出现的要求都是“我不需要(大而复杂的东西)X;我只是想要一些轻量级的东西”会冒着一次重新实现一个已发现需求的风险。但这并不是说你不能从中获得乐趣。

虽然这个问题很有趣,但我认为在没有更多细节的情况下很难回答。这是什么类型的应用程序?它有GUI吗?它是命令行工具吗?一套脚本?具有唯一入口点的程序,等等……

鉴于我所掌握的信息不多,我将以非常一般的方式回答。

你有什么办法添加插件?

您可能必须添加一个配置文件,该文件将列出要加载的路径/目录。 另一种说法是“该插件/目录中的任何文件都将被加载”,但它要求用户移动文件是不方便的。 最后一个中间选项是要求所有插件都在同一个插件/文件夹中,然后在配置文件中使用相对路径激活/禁用它们。

在纯代码/设计实践中,您必须清楚地确定您希望用户扩展哪些行为/具体操作。确定将总是被覆盖的公共入口点/一组功能,并确定这些操作中的组。一旦完成了这些,扩展应用程序就很容易了,

使用钩子的例子,灵感来自MediaWiki (PHP,但语言真的重要吗?)

import hooks

# In your core code, on key points, you allow user to run actions:
def compute(...):
    try:
        hooks.runHook(hooks.registered.beforeCompute)
    except hooks.hookException:
        print('Error while executing plugin')

    # [compute main code] ...

    try:
        hooks.runHook(hooks.registered.afterCompute)
    except hooks.hookException:
        print('Error while executing plugin')

# The idea is to insert possibilities for users to extend the behavior 
# where it matters.
# If you need to, pass context parameters to runHook. Remember that
# runHook can be defined as a runHook(*args, **kwargs) function, not
# requiring you to define a common interface for *all* hooks. Quite flexible :)

# --------------------

# And in the plugin code:
# [...] plugin magic
def doStuff():
    # ....
# and register the functionalities in hooks

# doStuff will be called at the end of each core.compute() call
hooks.registered.afterCompute.append(doStuff)

另一个例子,灵感来自mercurial。在这里,扩展只向hg命令行可执行文件添加命令,扩展行为。

def doStuff(ui, repo, *args, **kwargs):
    # when called, a extension function always receives:
    # * an ui object (user interface, prints, warnings, etc)
    # * a repository object (main object from which most operations are doable)
    # * command-line arguments that were not used by the core program

    doMoreMagicStuff()
    obj = maybeCreateSomeObjects()

# each extension defines a commands dictionary in the main extension file
commands = { 'newcommand': doStuff }

对于这两种方法,您可能需要对扩展使用通用的initialize和finalize。 您可以使用所有扩展都必须实现的公共接口(更适合第二种方法;Mercurial使用一个用于所有扩展的reposetup(ui, repo),或者使用一种带有钩子的钩子类型的方法。安装钩子。

但同样,如果你想要更多有用的答案,你必须缩小你的问题;)

module_example.py:

def plugin_main(*args, **kwargs):
    print args, kwargs

loader.py:

def load_plugin(name):
    mod = __import__("module_%s" % name)
    return mod

def call_plugin(name, *args, **kwargs):
    plugin = load_plugin(name)
    plugin.plugin_main(*args, **kwargs)

call_plugin("example", 1234)

它当然是“最小的”,它绝对没有错误检查,可能有无数的安全问题,它不是很灵活-但它应该告诉你一个Python插件系统可以多么简单。

你可能也想看看imp模块,尽管你可以用__import__, os。Listdir和一些字符串操作。

I arrived here looking for a minimal plugin architecture, and found a lot of things that all seemed like overkill to me. So, I've implemented Super Simple Python Plugins. To use it, you create one or more directories and drop a special __init__.py file in each one. Importing those directories will cause all other Python files to be loaded as submodules, and their name(s) will be placed in the __all__ list. Then it's up to you to validate/initialize/register those modules. There's an example in the README file.

扩展@edomaur的回答,我建议看看simple_plugins(无耻的插件),这是一个简单的插件框架,灵感来自Marty Alchin的工作。

一个基于项目README的简短使用示例:

# All plugin info
>>> BaseHttpResponse.plugins.keys()
['valid_ids', 'instances_sorted_by_id', 'id_to_class', 'instances',
 'classes', 'class_to_id', 'id_to_instance']

# Plugin info can be accessed using either dict...
>>> BaseHttpResponse.plugins['valid_ids']
set([304, 400, 404, 200, 301])

# ... or object notation
>>> BaseHttpResponse.plugins.valid_ids
set([304, 400, 404, 200, 301])

>>> BaseHttpResponse.plugins.classes
set([<class '__main__.NotFound'>, <class '__main__.OK'>,
     <class '__main__.NotModified'>, <class '__main__.BadRequest'>,
     <class '__main__.MovedPermanently'>])

>>> BaseHttpResponse.plugins.id_to_class[200]
<class '__main__.OK'>

>>> BaseHttpResponse.plugins.id_to_instance[200]
<OK: 200>

>>> BaseHttpResponse.plugins.instances_sorted_by_id
[<OK: 200>, <MovedPermanently: 301>, <NotModified: 304>, <BadRequest: 400>, <NotFound: 404>]

# Coerce the passed value into the right instance
>>> BaseHttpResponse.coerce(200)
<OK: 200>