我正在用Node.js和mongoose写一个web应用程序。如何对我从.find()调用得到的结果进行分页?我想要一个功能可比的“限制50,100”在SQL。


当前回答

您也可以使用下面的代码行

per_page = parseInt(req.query.per_page) || 10
page_no = parseInt(req.query.page_no) || 1
var pagination = {
  limit: per_page ,
  skip:per_page * (page_no - 1)
}
users = await User.find({<CONDITION>}).limit(pagination.limit).skip(pagination.skip).exec()

这段代码将在最新版本的mongo中工作

其他回答

最简单和更快速的方法是,用objectId进行分页 例子;

初始加载条件

condition = {limit:12, type:""};

从响应数据中获取第一个和最后一个ObjectId

下一页条件

condition = {limit:12, type:"next", firstId:"57762a4c875adce3c38c662d", lastId:"57762a4c875adce3c38c6615"};

下一页条件

condition = {limit:12, type:"next", firstId:"57762a4c875adce3c38c6645", lastId:"57762a4c875adce3c38c6675"};

在猫鼬

var condition = {};
    var sort = { _id: 1 };
    if (req.body.type == "next") {
        condition._id = { $gt: req.body.lastId };
    } else if (req.body.type == "prev") {
        sort = { _id: -1 };
        condition._id = { $lt: req.body.firstId };
    }

var query = Model.find(condition, {}, { sort: sort }).limit(req.body.limit);

query.exec(function(err, properties) {
        return res.json({ "result": result);
});

您可以像这样编写查询。

mySchema.find().skip((page-1)*per_page).limit(per_page).exec(function(err, articles) {
        if (err) {
            return res.status(400).send({
                message: err
            });
        } else {
            res.json(articles);
        }
    });

Page:来自客户端作为请求参数的页码。 Per_page:每页显示的结果数目

如果你正在使用MEAN堆栈,下面的博客文章提供了很多信息,在前端使用angular-UI引导和在后端使用猫鼬跳过和限制方法创建分页。

参见:https://techpituwa.wordpress.com/2015/06/06/mean-js-pagination-with-angular-ui-bootstrap/

以上回答是正确的。

只是一个插件,任何人谁是异步等待而不是 承诺! !

const findAllFoo = async (req, resp, next) => {
    const pageSize = 10;
    const currentPage = 1;

    try {
        const foos = await FooModel.find() // find all documents
            .skip(pageSize * (currentPage - 1)) // we will not retrieve all records, but will skip first 'n' records
            .limit(pageSize); // will limit/restrict the number of records to display

        const numberOfFoos = await FooModel.countDocuments(); // count the number of records for that model

        resp.setHeader('max-records', numberOfFoos);
        resp.status(200).json(foos);

    } catch (err) {
        resp.status(500).json({
            message: err
        });
    }
};
const ITEMS_PER_PAGE = 2;

exports.getProducts = (req, res, next) => {
  // + will turn the string to a number
  const page = +req.query.page || 1;
  let totalItems;
  //Product model
  Product.find()
    .countDocuments()
    .then((numProducts) => {
      totalItems = numProducts;
      return Product.find()
         //If query param is 3, since ITEMS_PER_PAGE = 2, we skip 2*2 items   
         // we show only 5th and 6th item
        .skip((page - 1) * ITEMS_PER_PAGE)
        .limit(ITEMS_PER_PAGE);
    })
    .then((products) => {
      res.render("shop/products", {
        // maybe sending the products object to templating engine
      });
    })
    .catch((err) => {
      const error = new Error(err);
      error.httpStatusCode = 500;
      // if you are set express error handler, use this
      // when we call next() with an argument passed in, we let express know, we skip all other middlewares, we move to error handling middleware

      return next(error);
    });
};

你可以像这样串起来:

var query = Model.find().sort('mykey', 1).skip(2).limit(5)

使用exec执行查询

query.exec(callback);