我想将我的项目打包在一个可执行的JAR中进行分发。
如何使Maven项目将所有依赖JAR打包到输出JAR中?
我想将我的项目打包在一个可执行的JAR中进行分发。
如何使Maven项目将所有依赖JAR打包到输出JAR中?
当前回答
对于任何想要从über JAR文件中排除特定依赖项的人来说,这是一个适合我的解决方案:
<project...>
<dependencies>
<dependency>
<groupId>org.apache.spark</groupId>
<artifactId>spark-core_2.11</artifactId>
<version>1.6.1</version>
<scope>provided</scope> <!-- <============= -->
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<archive>
<manifest>
<mainClass>...</mainClass>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
它不是mvn程序集插件的配置,而是依赖项的属性。
其他回答
您可以将以下内容添加到pom.xml文件中:
<build>
<defaultGoal>install</defaultGoal>
<plugins>
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<version>2.3.2</version>
<configuration>
<source>1.6</source>
<target>1.6</target>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.3.1</version>
<configuration>
<archive>
<manifest>
<addClasspath>true</addClasspath>
<mainClass>com.mycompany.package.MainClass</mainClass>
</manifest>
</archive>
</configuration>
</plugin>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<archive>
<manifest>
<mainClass>com.mycompany.package.MainClass</mainClass>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-my-jar-with-dependencies</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
然后,您必须通过控制台切换到pom.xml文件所在的目录。然后,您必须执行mvn assembly:single,然后希望构建具有依赖关系的可执行JAR文件。您可以在切换到带有cd的输出(目标)目录时检查它/目标并使用类似于java-jarmavenproject1-1.0-SNAPSHOT-JAR-with-dependencies.JAR的命令启动JAR。
我用Apache Maven 3.0.3测试了这一点。
这是我找到的最好的方法:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.4</version>
<configuration>
<archive>
<manifest>
<addClasspath>true</addClasspath>
<mainClass>com.myDomain.etc.MainClassName</mainClass>
<classpathPrefix>dependency-jars/</classpathPrefix>
</manifest>
</archive>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.5.1</version>
<executions>
<execution>
<id>copy-dependencies</id>
<phase>package</phase>
<goals>
<goal>copy-dependencies</goal>
</goals>
<configuration>
<outputDirectory>
${project.build.directory}/dependency-jars/
</outputDirectory>
</configuration>
</execution>
</executions>
</plugin>
使用此配置,所有依赖项都将位于依赖项jar中。我的应用程序没有Main类,只有上下文类,但我的一个依赖项确实有一个Main类(com.myDomain.ec.MainClassName),它启动JMX服务器,并接收start或stop参数。因此,我可以这样启动我的应用程序:
java -jar ./lib/TestApp-1.0-SNAPSHOT.jar start
要从命令行本身创建可执行JAR,只需从项目路径运行以下命令:
mvn assembly:assembly
您可以使用依赖插件在包阶段之前在单独的目录中生成所有依赖项,然后将其包含在清单的类路径中:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<executions>
<execution>
<id>copy-dependencies</id>
<phase>prepare-package</phase>
<goals>
<goal>copy-dependencies</goal>
</goals>
<configuration>
<outputDirectory>${project.build.directory}/lib</outputDirectory>
<overWriteReleases>false</overWriteReleases>
<overWriteSnapshots>false</overWriteSnapshots>
<overWriteIfNewer>true</overWriteIfNewer>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<configuration>
<archive>
<manifest>
<addClasspath>true</addClasspath>
<classpathPrefix>lib/</classpathPrefix>
<mainClass>theMainClass</mainClass>
</manifest>
</archive>
</configuration>
</plugin>
或者,使用${project.build.directory}/classes/lib作为OutputDirectory将所有JAR文件集成到主JAR文件中,但随后需要添加自定义类加载代码来加载JAR文件。
我想将我的Spring应用程序(使用Apereo Foundation的CAS客户端)迁移到Spring Boot 1.5。我遇到了很多问题,比如:
target/cas-client-web.jar中没有主清单属性
我试图创建一个具有所有依赖项的唯一JAR文件。在互联网上搜索后,我能够用以下几句话做到这一点:
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
<fork>true</fork>
<mainClass>${start-class}</mainClass>
</configuration>
<executions>
<execution>
<goals>
<goal>repackage</goal>
</goals>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<executions>
<execution>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
<configuration>
<archive>
<manifest>
<addClasspath>true</addClasspath>
<mainClass>${start-class}</mainClass>
</manifest>
</archive>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
</configuration>
</plugin>
开始上课是我的主要课程:
<properties>
<java.version>1.8</java.version>
<start-class>com.test.Application</start-class>
</properties>
我的申请是:
package com.test;
import java.util.Arrays;
import com.test.TestProperties;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.properties.EnableConfigurationProperties;
import org.springframework.context.ApplicationContext;
import org.springframework.context.annotation.Bean;
@SpringBootApplication
@EnableAutoConfiguration
@EnableConfigurationProperties({TestProperties.class})
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
@Bean
public CommandLineRunner commandLineRunner(ApplicationContext ctx) {
return args -> {
System.out.println("Let's inspect the beans provided by Spring Boot:");
String[] beanNames = ctx.getBeanDefinitionNames();
Arrays.sort(beanNames);
for (String beanName : beanNames) {
System.out.println(beanName);
}
};
}
}